A compound has a pKa of 7.4. You have made up 100 mL of a 1.0 M solution ofthis compound at pH 8.0. What is the ratio of unprotonated to protonatedforms of the molecule?80%○ 66.7%100%○ 50%○ 20%

To find the ratio of the unprotonated to protonated form of the molecules, we'll use the…

Answered: A compound has a pKa of 7.4. You have…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Calculate the concentration of Y4-ion in 0.0100 M EDTA solution at pH 6. α4 = 2.2 x 10-5 for pH 6.
You need a buff er at pH 7.5 for use in purifying a protein at 4°C. You have chosen Tris, pK 8.08, ΔH° = 50 kJ · mol−1. You carefully make up 0.01 M Tris buffer, pH 7.5 at 25°C, and store it in the cold to equilibrate it to the temperature of the purifi cation. When you measure the pH of the temperature-equilibrated buff er it has increased to 8.1. What is the explanation for this increase? How can you avoid this problem?
What mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4. Please indicate the full solutions.
You need to make a protein buffer of: . • • 100 mM NaCl 25 mM Tris 8 5% w/v glycerol • 2 mM DTT Your stock solutions are: 5 M NaCl • 2 M Tris 8 • 70% w/v glycerol • DTT @ 154.25 g/mol How would you make a 1L protein buffer Solution? Show your work and describe.
What mass of sodium glycolate (NaC2H3O3) should be added to 400.0 mL of 1.00 M glycolic acid to produce a buffer solution with a pH of 4.00? Ka = 1.47 x 10-4
9. 3 μL of a 45 mM stock solution of a substrate is added to 8 mL of water. Calculate the following values. The substrate molecular weight is 125 g/mol. Substrate volume in mL Dilution factor Substrate number of moles Substrate concentration for the diluted solution in mM Substrate concentration for the diluted solution in mole/L Substrate concentration for the diluted solution in mg/mL
A 0.200 M solution of a weak monoprotic acid (HA) has a pH of 2.35. What is the value of K of this acid? a K =2.011e-4 a What is the percent ionization of this acid? Percent Ionization = .10 %
at 257 nm) is dissolved in 2.5 mL of buffer. A 250 microliter aliquot is removed and placed in a 1.0 cm A sample of adenosine triphosphate (ATP) (MW 507, ɛ = 14,700 M'cm cuvette with sufficient buffer to give a total volume of 2.0 mL. The absorbance of the sample at 257 nm is 2.0. Calculate the weight of ATP in the original 2.5 mL sample. (Choose the correct value from the drop-down list provided. The values of weight are listed in units of milligrams.) Weight of ATP: v mg
If an aqueous solution has a hydroxyl ion concentration of 1 × 10-6 M, what is the concentration of hydrogen ion ([H+]) ? [H+] = 1.0 x10-5 M
pH of solution 14.00 12.00 10.00 8.00 6.00 First 4.00 equivalence point 2.00 0 First midpoint Second equivalence point Third midpoint pH = pKa=12.32 Third equivalence point HPO4(aq) + OH(aq) PO4(aq) + H2O(1) Second midpoint pH = pKa = 7.21 H2PO4 (aq) + OH(aq) HPO42 (aq) + H2O(1) Using the Henderson- Hasselback equation, show how to create 2L of a 0.1 M KPhos pH 7.5 buffer using K2HPO4 and KH2PO4. The chart to the left should help you understand what pKa to start with. Show your work. pH = pKa = 2.16 H3PO4(aq) + OH(aq) H2PO4(aq) + H2O(l) 25.0 50.0 75.0 100.0 Volume of NaOH added (mL)
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A compound has a pKa of 7.4. You have made up 100 mL of a 1.0 M solution of this compound at pH 8.0. What is the ratio of unprotonated to protonated forms of the molecule? 80% ○ 66.7% 100% ○ 50% ○ 20%