There are several factors that affect the rate of a reaction. These factors include temperature, activation energy, steric factors (orientation), and also collision frequency, which changes with concentration and phase. All the factors that affect reaction rate can be summarized in an equation called the Arrhenius equation:k=Ae−Ea/RTk=Ae−Ea/RTwhere kkk is the rate constant, AAA is the frequency factor, EaEaE_a is the activation energy, R=8.314 J/(mol⋅K)R=8.314 J/(mol⋅K) is the universal gas constant, and TTT is the absolute temperature. Part AA certain reaction has an activation energy of 63.0 kJ/molkJ/mol and a frequency factor of A1A1A_1 = 4.50×1012. What is the rate constant, kkk, of this reaction at 21.0 ∘C∘C ?Express your answer numerically. The linear form of the Arrhenius equationThe Arrhenius equation can be rearranged to a form that resembles the equation for a straight line:lnky==−(EaR)m(1T)x++lnAbln⁡k=−(EaR)(1T)+ln⁡Ay=mx+bwhere yyy is lnkln⁡k, mmm is the slope or −EaR−EaR, xxx is 1T1T, and bbb is the yyy-intercept or lnAln⁡A. The linearity of this equation is illustrated graphically in the image.Part BAn unknown reaction was observed, and the following data were collected: TTT(KK)kkk(M−1⋅s−1M−1⋅s−1)352109426185 Determine the activation energy for this reaction.Express your answer in kilojoules per mole.

Here we have to determine the rate constant and activation energy of reaction by using Arrehenius…

Answered: A certain reaction has an activation…

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter11: Chemical Kinetics: Rates Of Reactions

Section: Chapter Questions

Problem 11.ACP: (Section 11-5) A rule of thumb is that for a typical reaction, if concentrations are unchanged, a...

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Part A

A certain reaction has an activation energy of 63.0 kJ/molkJ/mol and a frequency factor of A1A1A_1 = 4.50×10¹². What is the rate constant, kkk, of this reaction at 21.0 ∘C∘C ?

Express your answer numerically.

The linear form of the Arrhenius equation

The Arrhenius equation can be rearranged to a form that resembles the equation for a straight line:

lnky==−(EaR)m(1T)x++lnAbln⁡k=−(EaR)(1T)+ln⁡Ay=mx+b

where yyy is lnkln⁡k, mmm is the slope or −EaR−EaR, xxx is 1T1T, and bbb is the yyy-intercept or lnAln⁡A. The linearity of this equation is illustrated graphically in the image.

Part B

An unknown reaction was observed, and the following data were collected:

TTT (KK)	kkk (M−1⋅s−1M−1⋅s−1)
352	109
426	185

Determine the activation energy for this reaction.

Express your answer in kilojoules per mole.

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