A 1m thick triangular soil block is shown below. Vertical dimension is H. The bottom face is inclined at e (radian) with horizontal. The weight of the block is W= y*area of the triangle*1; y = weight of the soil per unit volume. The resistance force along the bottom face of the block F = N*tan(o') + c*inclined length of the triangle at the bottom. N is the normal force at the bottom face of the block. o' = effective friction angle and c' = effective cohesion. A horizontal force P is set to keep the triangle from moving towards the left, and in equilibrium. Find an expression for P in terms of H, y, o', c' and e. Calculate P (kN) for H=5m, g=18 kN/m3, o'=30 deg, c'=0, and e = TT/4. Weight W P

A 1m thick triangular soil block is shown below. Vertical dimension is H. The bottom face is inclined at e (radian) with horizontal. The weight of the block is W= yarea of the triangle1; y = weight of the soil per unit volume. The resistance force along the bottom face of the block F = Ntan(o') + cinclined length of the triangle at the bottom. N is the normal force at the bottom face of the block. o' = effective friction angle and c' = effective cohesion. A horizontal force P is set to keep the triangle from moving towards the left, and in equilibrium. Find an expression for P in terms of H, y, o', c' and e. Calculate P (kN) for H=5m, g=18 kN/m3, o'=30 deg, c'=0, and e = TT/4. Weight W P

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter10: Stresses In A Soil Mass

Section: Chapter Questions

Problem 10.1CTP: EB and FG are two planes inside a soil element ABCD as shown in Figure 10.50. Stress conditions on...

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