8. Know how to do these, to trace functions like these and to debug functions like these: // recursive power , compute xn int exp(int x, int n){ if(n== return return *exp } void main(){ int a,b; cin >>a>>b; cout<>a; rev_print(a); }
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- 8. Ackerman's Function Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a system optimizes its performance of recursion. Design a function ackermann(m, n), which solves Ackermann's function. Use the following logic in your function: If m = 0 then return n + 1 If n = 0 then return ackermann(m-1,1) Otherwise, return ackermann(m-1,ackermann(m,n-1)) Once you've designed yyour function, test it by calling it with small values for m and n. Use Python.7. Convert this iterative function into recursive function. [s] int factorial (int num){ int answer=1; for(int t = 1; t>num; t++) { answer answer * (t); return (answer); }Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?
- Part 2: Recursive Fractals Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can generate patterns such as this: pattern(3, 2); pattern(5, 1); pattern(7, 0); With recursive thinking, the function needs only about 10 lines of code (including two recursive calls). Your function prototype should look like this: // Description: I/ The longest line of the pattern has n stars beginning in column col of the output. // Precondition: n is an positive odd number. // Postcondition: A pattern based on the above example has been printed. void pattern (int n, int col); No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a non-negative int as col. Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the large pattern? Here is some code that may be helpful within your function: // A loop to print exactly col columns for (int i = 0; i < col; i++) cout <«…Exercise 1: The number of combinations CR represents the number of subsets of cardi- nal p of a set of cardinal n. It is defined by C = 1 if p = 0 or if p = n, and by C = C+ C in the general case. An interesting property to nxC calculate the combinations is: C : Write the recursive function to solve this problem.Recursive ConversionConvert the following function to one that uses recursion.void sign(int n){while (n > 0)cout << "No Parking\n";n−−;}Demonstrate the function with a driver program.
- 2) Consider a recursive function to find the maximum value in an array of integers. The function declaration is: int maxValue( int vals[], int size, int start ); For this function, we need to know the size of the array and the starting index of the array (because both will change when a recursive call is made). You may assume that there is at least one value in the array. C++ languageWrite a recursive function recursiveMinimum that takes an integer array, a starting subscript, and an ending subscript as arguments, and returns the smallest element of the array. The function should stop processing and return when the starting sub- script equals the ending subscript. c++For function sumtok, write the missing recursive call. This function returns the sum of the values from 1 to k. Examples: sumtok(5) -> 15 public int sumtok(int k) { if (k <= 0) { return 0; } else { return <<Missing Recursive case action>> }}
- Recursion in programming is described as when a function/method makes a direct or indirect call to itself. Which of the features is not valid for a recursive function. Select one: a. The Recursive calls can be more then one b. The Recursive Call – the function calls itself with an input which is a step closer to the stop condition c. The Stoping Conditions can be more than one d. The Recursive call is optional. e. A Stop Condition – the function returns a value when a certain condition is satisfied, without a further recursive callFor function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}