Part 2: Recursive FractalsExamine this pattern of asterisks and blanks, and write a recursive function called pattern() that cangenerate patterns such as this:pattern(3, 2);pattern(5, 1);pattern(7, 0);With recursive thinking, the function needs only about 10 lines of code (including two recursive calls).Your function prototype should look like this:// Description:I/ The longest line of the pattern has n stars beginning in column col of the output.// Precondition: n is an positive odd number.// Postcondition: A pattern based on the above example has been printed.void pattern (int n, int col);No error handling needed for this part. Assume that user will provide you a positive odd int as n, and anon-negative int as col.Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within thelarge pattern? Here is some code that may be helpful within your function:// A loop to print exactly col columnsfor (int i = 0; i < col; i++) cout <« "";// A loop to print n asterisks, each one followed by a space:for (int i = 0; i < n; i++) cout « "* ";

#include <iostream> using namespace std; //function 'pattern' to print the pattern void…

Part 2: Recursive Fractals Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can generate patterns such as this: pattern(3, 2); pattern(5, 1); pattern(7, 0); With recursive thinking, the function needs only about 10 lines of code (including two recursive calls). Your function prototype should look like this: I/ Description: II The longest line of the pattern has n stars beginning in column col of the output. I/ Precondition: n is an positive odd number. I/ Postcondition: A pattern based on the above example has been printed. void pattern (int n, int col); No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a non-negative int as col. Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the large pattern? Here is some code that may be helpful within your function: // A loop to print exactly col columns for (int i = 0; i < col; i++) cout <« " "; // A loop to print n asterisks, each one followed by a space: for (int i = 0; i < n; i++) cout « "* ";

Part 2: Recursive Fractals Examine this pattern of asterisks and blanks, and write a recursive function called pattern() that can generate patterns such as this: pattern(3, 2); pattern(5, 1); pattern(7, 0); With recursive thinking, the function needs only about 10 lines of code (including two recursive calls). Your function prototype should look like this: I/ Description: II The longest line of the pattern has n stars beginning in column col of the output. I/ Precondition: n is an positive odd number. I/ Postcondition: A pattern based on the above example has been printed. void pattern (int n, int col); No error handling needed for this part. Assume that user will provide you a positive odd int as n, and a non-negative int as col. Hint: Think about how the pattern is a fractal. Can you find two smaller versions of the pattern within the large pattern? Here is some code that may be helpful within your function: // A loop to print exactly col columns for (int i = 0; i < col; i++) cout <« " "; // A loop to print n asterisks, each one followed by a space: for (int i = 0; i < n; i++) cout « "* ";

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter15: Recursion

Section: Chapter Questions

Problem 1TF

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