7. In pea plants, inflated pod is governed by a completely dominant gene and a constrict pod by a recessive gene. Another independently segregating dominant gene produc green pod while recessive gene produces yellow pod. Give the genotypes of the pare in each of the crosses given below. Phenotypes of Offspring Parental Phenotypes Parental genotypes Inflated Inflated Constricted Cc green yellow Green inflated green x inflated yellow 7.1. 58 62 18 7.2. constricted green x 56 constricted green 7.3 inflated yellow x 64 inflated yellow inflated green x inflated yellow 7.4. 36 38 inflated green x inflated green 7.5. 178 62 58

7. In pea plants, inflated pod is governed by a completely dominant gene and a constrict pod by a recessive gene. Another independently segregating dominant gene produc green pod while recessive gene produces yellow pod. Give the genotypes of the pare in each of the crosses given below. Phenotypes of Offspring Parental Phenotypes Parental genotypes Inflated Inflated Constricted Cc green yellow Green inflated green x inflated yellow 7.1. 58 62 18 7.2. constricted green x 56 constricted green 7.3 inflated yellow x 64 inflated yellow inflated green x inflated yellow 7.4. 36 38 inflated green x inflated green 7.5. 178 62 58

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Description: 7. In pea plants, inflated pod is governed by a completely dominant gene and a constrictedpod by a recessive gene. Another independently segregating dominant gene producesgreen pod while recessive gene produces yellow pod. Give the genotypes of the

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter3: Transmission Of Genes From Generation To Generation

Section: Chapter Questions

Problem 18QP: More Crosses with Pea Plants: The Principle of Independent Assortment Determine the possible...

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7. In pea plants, inflated pod is governed by a completely dominant gene and a constricted pod by a recessive gene. Another independently segregating dominant gene produces green pod while recessive gene produces yellow pod. Give the genotypes of the parents in each of the crosses given below. Phenotypes of Offspring Inflated yellow Constricted yellow Parental Phenotypes Parental genotypes Inflated groen Constricted Green 7.1. inflated green x inflated yellow 58 62 18 22 7.2. constricted green x constricted green 56 18 7.3 inflated yellow x inflated yellow 64 20 74. inflated gr green x 36 38 inflated yellow 7.5. inflated green x inflated green 178 62 58 22
What are the possible genotype and phenotype of offspring witha parent of two heterozygous tall pea plant? Legend: T- tall pea plant t- short pea plant1. Identify the genotypes of the parents 2. Complete the punnett square 3. What are the possible genotypes of the offspring. 4. What is the genotypic ration 5. What are the possible phenotypes of the offspring 6. what is the phenotypic ratio 7. What is the probability of having short trait.
x² R AA E Paragraph 255 129 112 1 heavy, green, long heavy, green, ovate heavy, yellow, ovate heavy, yellow, long light, yellow, oblate V light, yellow, long light, green, long light, green, ovate Normal No Spacing In an East Indian mango, three genes are linked on the same chromosome. Heavy bloom is dominant to light bloom, skin that is green is dominant to skin that is yellow, and fruit with a long shape is dominant to ovate shape. A plant that is true-breeding for the dominant traits was crossed to a light, yellow and ovate fruit. The F1 plants were then testcrossed to light, yellow and ovate fruit. The following results were obtained: 251 111 133 21 Styles Heac a) Diagram the crosses for the parental generation and F1 test cross. b) Construct a genetic map that shows the order of these three genes and the distances between them.
1. In pea plants, yellow peas are dominant to green peas and purple flowers are dominant to white flowers. For each of the following parental crosses, give the predicted phenotypic and genotypic ratios of the F1 generation. Make punnet squares if necessary. 1. (heterozygous purple-flowered) x (heterozygous purple-flowered) 2. (true breeding white-flowered, yellow pea) x (true breeding purple-flowered, green pea) 3. (heterozygous purple-flowered, yellow pea) x (heterozygous purple-flowered, yellow pea) 2. You have a purple-flowered pea plant. You do not know its genotype. Diagram the test-cross you would conduct to determine the plant’s genotype and what results you would expect if the plant was heterozygous and if the plant was homozygous 3. You are studying five traits in Pentids, an amazonian flying beetle. You have identified each trait as belonging to separate alleles located on separate chromosomes and have categorized those alleles as A,B,C,D, and E, respectively. After years of…
Which of the Pedigree Diagrams above is most likely to show a family with Achondroplasia? A KEY Homozygous Homozygous Heterozygous Heterozygous Wild Type Male Female Male Female Male с. Note: Completely red symbol denotes an individual exhibiting the phenotype of interest 11 IV V 1/4 1/2 1/2 ₂₂( 1/2 1/2 5 1/4 Wild Type Female 1/2 B Affected Known carrier Affected female Normal female Affected male Normal male D
VHO Has typ D VIO0a ana a Wom What would be the expected phenotypes (in percent) of their children? In fruit flies, a gene that controls eye color is X-linked. Red eyes are dominant to the allele for white eyes. What 3) are the expected offspring phenotypes (in percent) if a heterozygous red-eyed female is crossed with a white- eyed male? d man with normal 11 1 woman m
1. You are given a female F1 of unknown genotype. You cross the female fly to a homozygous male that has forked bristles and malformed eyes. The offspring of the cross is shown below: (Define symbols for your traits) Phenotype Forked bristles, normal eyes 752 Number Genotype Forked bristles, malformed 56 eyes Malformed eyes, normal bristles Normal eyes, normal bristles 820 64 a. What are the genotypes of the offspring? b. Based on the progeny, what were the genotypes of the F1 parents? What is the distance between for and mal?
4. What are the possible phenotypes and genotypes of the F1 generation if the P generation consisted of the following cross: a plant that is homozygous dominant for flower color and homozygous dominant for pod color was crossed with a plant that is heterozygous for flower color and homozygous dominant for pod color? Dominant for flower color – P (purple) Recessive for flower color = p (white) Dominant for pod color =G (green) Recessive for pod color = g (yellow) %3D P1: PP X GG Рр X GG PG PG PG PG PG PPGG PPGG PPGG PPGG PG PPGG PPGG PPGG PPGG PPGG PPGG Pp pG PPGG PpGG PPGG PpGG Genotypes: Phenotypes: Genotypic Ratio: Phenotypic 田

9. Radishes may be long, round, or oval in shape and red, white, or purple in colour. A long white variety crossed with a round red one produced oval, purple Fi's. The F2 progeny of F1 selfing comprised nine phenotypic classes as follows: long, red long, purple long, white round, purple 9 8 15 16 oval, red 19 round, white 8. oval, purple oval, white 32 16 round, red 9 (a) Explain the pattern of inheritance. (b) Give the genotypic and phenotypic ratios expected among the progeny of crosses between: A long, purple and an oval, purple plant. An oval, purple plant and a round, white plant How many true-breeding varieties of radish could be established?
In dogs, dark coat color is dominant over albino, andshort hair is dominant over long hair. Assume that theseeffects are caused by two independently assorting genes.Seven crosses were done as shown below, in which D andA stand for the dark and albino phenotypes, respectively,and S and L stand for the short-hair and long-hairphenotypes.Number of progenyParental phenotypes D, S D, L A, S A, La. D, S × D, S 88 31 29 12b. D, S × D, L 19 18 0 0c. D, S × A, S 21 0 20 0d. A, S × A, S 0 0 29 9e. D, L × D, L 0 31 0 11f. D, S × D, S 45 16 0 0g. D, S × D, L 31 30 10 10Write the genotypes of the parents in each cross. Use thesymbols C and c for the dark and albino coat-color allelesand the symbols H and h for the short-hair and long-hairalleles, respectively. Assume parents are homozygousunless there is evidence otherwise.
In this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…
Figure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?