5. When two alleles are observed independently in a phenotype is called multiple alleles. Human blood group ABO is a good example of multiple alleles. The three alleles are: I^, IB, i. Mother's blood type is AB (IAB) and father's blood type is B (Bi). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes 6. When the allele of a trait is found on X or Y chromosome, it becomes sex-linked. The colorblindness. results differ from males to females. One such example is of red green The mother is a carrier (XC X), and the father is colorblind (XY). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes

5. When two alleles are observed independently in a phenotype is called multiple alleles. Human blood group ABO is a good example of multiple alleles. The three alleles are: I^, IB, i. Mother's blood type is AB (IAB) and father's blood type is B (Bi). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes 6. When the allele of a trait is found on X or Y chromosome, it becomes sex-linked. The colorblindness. results differ from males to females. One such example is of red green The mother is a carrier (XC X), and the father is colorblind (XY). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes

Name: 5. When two alleles are observed independently in a phenotype is call
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Description: 5. When two alleles are observed independently in a phenotype is called multiple alleles.Human blood group ABO is a good example of multiple alleles. The three alleles are: I^,IB, i. Mother's blood type is AB (IAIP) and father's blood type is B (1³i

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter13: Modern Understandings Of Inheritance

Section: Chapter Questions

Problem 2VCQ: Figure 13.4 Which of the following statements is true? Recombination of the body color and red/...

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4. Attached earlobes are dominant over free hanging earlobes. Complete the Punnett Square for the following individuals: Mom-Bb and Dad=bb Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes 5. When two alleles are observed independently in a phenotype is called multiple alleles. Human blood group ABO is a good example of multiple alleles. The three alleles are: IA, IB, i. Mother's blood type is AB (IAI³) and father's blood type is B (I³i). Provide the genotype and phenotype ratios using the Punnett square given below. Genotypes Phenotypes Genotypes Phenotypes 6. When the allele of a trait is found on X or Y chromosome, it becomes sex-linked. The results differ from males to females. One such example is of red green colorblindness. The mother is a carrier (X© Xº ), and the father is colorblind (X© Y). Provide the genotype and phenotype ratios using the Punnett square given below. Phenotypes
15. Human blood types is an example of a multiple allele system. Fill in the table below, showing what genotype(s) is/are associated with each phenotype. Use i = type O, IA = type A, IB = type B. Remember blood type is an example of codominance Blood Phenotype Genotype(s) (list all possibilities) AB
For numbers 34-50. Given the following pedigree, answer the following questions. 1st generation would be the grandparents, 2" generation would be the children of the grandparents and the 3" generation would be the children of the 2"generation. Trait that would be track is autosomal dominant and recessive. Cleft chin (CC or Ce) = Dominant No cleft chin (ce) = Recessive II 10 34-37. What is the expected Genotype of the grandfather? A. CC В. Се С. се D. Either A or B 38-41. What is the expected genotype of number 4 given the following genes in the 1st generation A. CC В. Се C. Either A or B D. Neither A nor 8 42-45. Who are the persons failed to inherit cleft chin from the grand mother? A. Number 5, 1, 8,9 and 7 B. Number 2, 9, 7, 10 and 3 C. Number 2, 5, 7, and 9 D. Number 1, 3 and 10 E. Nurmber 2 and 5 47-50. If number 10 married a person without a cleft chin and all the off-springs have cleft chin, what is the genotype of number 10? A C В. Сс С. сс D. Either A nor B
25. List the three alleles for blood: 26. List the genotypes for blood: 27. List the phenotypes for blood: 28. A type of chicken shows codominance with black (B) being codominant with white (B'). The heterozygous condition is checkered. Cross a checkered rooster with a white hen. Show the following: Genotypes: Phenotypes: Genotypic Ratio: Phenotypic Ratio:
For numbers 1-9. Cross the following blood type of the wife and husband and answer the questions provided. Wife: Type A Husband: Type AB 1-3. What are the possible genotype of the offspring? А. АО, ВО В. А, ВО, АВ С. АО, ВВ D. AA,AB 4-6. What are the possible Phenotype? A. Type A and B В. Туре АВ С. Туре А, В аnd AB D. Type A, B and O 7-9. What is the percentage of type AB if the genotype you cross is AO and AB? А. 25% В. 50% C. 75% D. 0%
B What is the genotype ratio? What is the phenotype ratio? 3. What are the expected genotype and phenotype ratios in the following genetic conditions? Use scratch paper to do the Punnett square if needed but you do not need to draw it on the worksheet. a. Monohybrid cross between 2 heterozygous individuals (Aa x Aa) Genotype ratio: 1:2:1 Phenotype ratio: 3:1 G q 8:32 a b. Dihybrid cross between 2 heterozygous individuals (AaBb x AaBb) Genotype ratio: Phenotype ratio: 4. Both Mrs. Smith and Mrs. Jones had babies the same day in the same hospital. Mrs. Smith took home a baby girl, whom she named Sharon. Mrs. Jones took home a girl, whom she named Jane. Mrs. Jones began to suspect, however, that the child had been accidentally switched with Mrs. Smith baby in the nursery. Blood test were made; Mr. Smith was type A, Mrs. Smith was type B, Mr. Jones was type A, Mrs. Jones was type A. Sharon was type O, and Jane was type. B. Had a mix-up occurred? Use scratch paper, you do not need to…
9. Make a pedigree for each of the following situations. For each individual, write the individual's genotype (when possible) next to the individual's symbol (e.g. O xty, I Gg): a. Two parents do not have cystic fibrosis and they have a daughter with cystic fibrosis and a son who does not have cystic fibrosis. The daughter grows up and she mates with a male who does not have cystic fibrosis. Their only child is a boy and he has cystic fibrosis. b. A man with hemophilia mates with a female without hemophilia. They have one son and one daughter. The daughter has hemophilia and the son does not have hemophilia. The son grows up, and he marries and mates with a female. Their only child is a boy, and he has hemophilia.
Codominance ABO blood typing is an example of codominance, where A and B are both dominant to O. A woman who is AB type has a child with a man who is O type. Use I allele formatting to designate each genotypes: IA IA, IA i, IB IB, IB i, IA IB, ii A) List the genotype of each parent. B) Complete a Punnett square. List all the genotypes for the predicted offspring of this mating (using the format of genotypes listed above) C) What is the probability that any of their offspring will be O type? D) What is the probability that any of their offspring will be AB type?
Date Name Punnett Square Practice Worksheet 1) For each of the genotypes (AA, Aa or aa) below determine what the phenotype would be. Purple flowers are dominant to white flowers. PP Pp PP Hairy knuckies are dominant to non-hairy knuckles in humans. Hh hh HH Bobtails in cats are recessive. Normal tails are dominant. Tt tt TT 2) For each of the following write whether it is homozygous dominant, heterozygous or homozygous recessive. AA gg Pp Ii TT Use the following information for questions 3-5: In dogs, the gene for fur color has two alleles. The dominant allele (F) codes for grey fur and the recessive allele (f) codes for black fur. 3) The female dog is heterozygous. The male dog is homozygous recessive. Figure out the percentage or ratio of possible phenotypes and genotypes of their puppies by using a Punnett Square. Plae the oileles for the mule parent helm One alele n e h lie: % of possible Genotypes: FF Plar the alfele f he emle p r ti side One elleir on ch tine Ff: % of possible…
V. Two Gene Pairs (Extra Credit) 1... A. In peas, the allele for tall plants (T) is dominant over the allele for short plants (t). The allele for smooth peas (S) is dominant over the allele for wrinkled peas (s). Use this information to cross the following parents. I 1. heterozygous tall and smooth X heterozygous tall and smooth 2. heterozygous tall, wrinkled X short, wrinkled AL.
Blood group: A Blood group: 0 Blood group: B Cross 5 Cross 6 Blood group: O AO 0 Parental genotypes B0 Gametes Possible fertilizations Children's genotypes Blood groups 3. A wife is heterozygous for blood group A and the husband has blood group O. Biood A (a) Give the genotypes of each parent (fil in spaces on the diagram on the right). Blood o group group Determine the probability of: Parental genotypes (b) One child having blood group O: (c) One child having blood group A: Gametes Possible fertlizations (d) One child having blood group AB: Children's genotypes Biood sdno6 4. In a court case involving a paternity dispute (i.e. who is the father of a child) a man claims that a male child (blood group B) born to a woman is his son and wants custody. The woman claims that he is not Blood A group Blood O group the father. Parental genotypes (a) If the man has a blood group O and the woman has a blood group A, could the child be his son? Use the diagram on the right to illustrate the…
. An allele A that is not lethal when homozygous causes rats to have yellow coats. The allele R of a separate gene that assorts independently produces a black coat. Together, A and R produce a grayish coat, whereas a and r produce a white coat. A gray male is crossed with a yel-low female, and the F1 is 3 8 yellow, 3 8 gray, 1 8 black, and 1 8 white. Determine the genotypes of the parents.