3.63 moles of a gas that follows the van der Waals equation of state are placed in a rigid container with a volume of 16.8 dm³ at 284.3 K. The container is heated to a temperature 376.4 K absorbing 3.65 kJ of heat in the process. Calculate AH in Joules for the gas during the process. For this gas the values of the van der Waals constants are: a = 3.38 atm dm6 mol-2 b= 5.18 x 10-2 dm³ mol-1 Be careful with signs!

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Chapter8: Thermochemistry
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3.63 moles of a gas that follows the van der Waals equation of state are placed in a rigid container
with a volume of 16.8 dm³ at 284.3 K. The container is heated to a temperature 376.4 K absorbing
3.65 kJ of heat in the process. Calculate AH in Joules for the gas during the process.
For this gas the values of the van der Waals constants are:
a = 3.38 atm dm6 mol-2
b= 5.18 x 10-2 dm³ mol-¹
Be careful with signs!
Transcribed Image Text:3.63 moles of a gas that follows the van der Waals equation of state are placed in a rigid container with a volume of 16.8 dm³ at 284.3 K. The container is heated to a temperature 376.4 K absorbing 3.65 kJ of heat in the process. Calculate AH in Joules for the gas during the process. For this gas the values of the van der Waals constants are: a = 3.38 atm dm6 mol-2 b= 5.18 x 10-2 dm³ mol-¹ Be careful with signs!
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