QuestionPart AExpress the reverse equilibrium constant for the following reaction.6 CH²Cl(g) + 3 Cl₂(g) ↔ 6 CH₂Cl₂(g) + 3 H₂(g)O K=K=OK=OK=-OK=Submit25[CH₂Cl2][H₂]¹[CH3 Cl][C1₂] ¹[CH3 C1][Cl₂][CH₂Cl2 [H₂][CH₂ C1₂] [H₂]³[CH3C1][C12]3[CH3Cl][C12]3[CH₂ C12] [H₂]³[CH3Cl][C12]5[CH₂Cl2][H₂]Provide FeedbackRequest Answer4

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Express the reverse equilibrium constant for the following reaction. 6 CH³CI(g) + 3 Cl₂(g) ↔ 6 CH₂Cl₂(g) + 3 H₂(g) K= K= K= K= K= [CH₂C1₂] [H₂] 4 [CH3CI][C1₂] [CH3Cl][C12] [CH₂Cl2 [H₂] [CH₂ C1₂] [H₂]3 13 [CH3Cl® [C1, 3 [CH3C1®[Cl2]® [CH₂ C1₂] [H₂13 [CH3Cl][C12]5 [CH₂Cl₂] [H₂]5

Express the reverse equilibrium constant for the following reaction. 6 CH³CI(g) + 3 Cl₂(g) ↔ 6 CH₂Cl₂(g) + 3 H₂(g) K= K= K= K= K= [CH₂C1₂] [H₂] 4 [CH3CI][C1₂] [CH3Cl][C12] [CH₂Cl2 [H₂] [CH₂ C1₂] [H₂]3 13 [CH3Cl® [C1, 3 [CH3C1®[Cl2]® [CH₂ C1₂] [H₂13 [CH3Cl][C12]5 [CH₂Cl₂] [H₂]5

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 12.78PAE

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