3. The manufacturer of the vinegar used in this experiment claims that the vinegar contains 5% acetic acid by weight. Using your results, molarity of vinegar, and 1.0 g/ml for a density of vinegar, calculate the % acetic acid by weight. Can you tell if the manufacturer's claims is reasonable?

Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter13: The Chemistry Of Solutes And Solutions
Section13.6: Expressing Solution Composition
Problem 13.7PSP
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Can you help me solve question 3? “The manufacturer of vinegar…”
3. The manufacturer of the vinegar used in this
experiment claims that the vinegar contains
5% acetic acid by weight. Using your results,
molarity of vinegar, and 1.0 g/ml for a density
of vinegar, calculate the % acetic acid by
weight. Can you tell if the manufacturer's
claims is reasonable?
Transcribed Image Text:3. The manufacturer of the vinegar used in this experiment claims that the vinegar contains 5% acetic acid by weight. Using your results, molarity of vinegar, and 1.0 g/ml for a density of vinegar, calculate the % acetic acid by weight. Can you tell if the manufacturer's claims is reasonable?
Data
molarity of the NaOH
solution, M
initial buret reading, mL
final buret reading, mL
volume of NaOH
solution, mL
volume of CH3COOH,
mL
concentration of
CH3COOH, M
mean concentration of
CH3COOH, M
Calculation
m, V₁
ni
x lo
0.250 M
2.110 m2 000mc 6.0 mc
38.60mL
40.4 m²
34.30mL.
39.30 mL 34.4. ml
36.50
10.00 mL
0.9135 0.85PS 0.860
0.8777
m2V2
n₂
2
0.0086
0.25x 0. 0344
0.86= 0.0086/0.010
38-c
2 (0
365.
molarity #mol/L
=
#mol = molority XL
0.009125 = 0.25 × 0.0365
0.009125/0
0.0005 0.25 X 0.03
0.00877/0.00
-53-
Transcribed Image Text:Data molarity of the NaOH solution, M initial buret reading, mL final buret reading, mL volume of NaOH solution, mL volume of CH3COOH, mL concentration of CH3COOH, M mean concentration of CH3COOH, M Calculation m, V₁ ni x lo 0.250 M 2.110 m2 000mc 6.0 mc 38.60mL 40.4 m² 34.30mL. 39.30 mL 34.4. ml 36.50 10.00 mL 0.9135 0.85PS 0.860 0.8777 m2V2 n₂ 2 0.0086 0.25x 0. 0344 0.86= 0.0086/0.010 38-c 2 (0 365. molarity #mol/L = #mol = molority XL 0.009125 = 0.25 × 0.0365 0.009125/0 0.0005 0.25 X 0.03 0.00877/0.00 -53-
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