3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new length of the 2-inch side. Answer: Lnew = 2.00019 in

3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new length of the 2-inch side. Answer: Lnew = 2.00019 in

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial load acts perpendicular to the geometric cross-section of the component. Based on the direction of the application of the load, an axial load can be tensile or compressive. The analysis of bodies under the action of axial loads is generally studied under the branch of mechanics, known as statics.

Question

3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force
of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new
length of the 2-inch side.
Answer: Lnew = 2.00019 in
1.5 in
2 in.
8 kip-
8 kip
3 in.
4. A solid cylinder of diameter D is subjected to an axial load P. Show that its change in diameter is 8D =
4Pv/лDE.

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