3. An insulating bar has a positive and uniform electric charge distribution A and it is desired to calculate the electric potential at point P as shown in the figure. Let x be the horizontal distance measured in standard mode, that is, from the origin and L= 16 cm, what is the value of the denominator within the integral that calculates the electric potential:

Physics for Scientists and Engineers: Foundations and Connections
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Author:Katz, Debora M.
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Chapter26: Electric Potential
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3. An insulating bar has a positive and uniform electric charge distribution X and it is desired to
calculate the electric potential at point P as shown in the figure. Let x be the horizontal distance
measured in standard mode, that is, from the origin and L= 16 cm, what is the value of the
denominator within the integral that calculates the electric potential:
a) r = √x² +0.0064 m²
x
c) r = x² +0.0064 m²
Vp
1
Anto da
T
=
dq
L
= (0.16 m - x)² +0.0064 m²
d) r = √√(0.16 m − x)² +0.0064 m²
-
• P
1|2
L
î
Transcribed Image Text:3. An insulating bar has a positive and uniform electric charge distribution X and it is desired to calculate the electric potential at point P as shown in the figure. Let x be the horizontal distance measured in standard mode, that is, from the origin and L= 16 cm, what is the value of the denominator within the integral that calculates the electric potential: a) r = √x² +0.0064 m² x c) r = x² +0.0064 m² Vp 1 Anto da T = dq L = (0.16 m - x)² +0.0064 m² d) r = √√(0.16 m − x)² +0.0064 m² - • P 1|2 L î
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