3. A board whose width changes as w(x) = 2(√L-√) (0 ≤ x ≤ L), as shown is fixed on the left edge. Here L is the length of the board. The material has an area mass density (per unit area) of pkg/m²

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3. A board whose width changes as w(r) = 2(√L-√x) (0 ≤ x ≤ L), as shown is fixed on the left edge. Here L is the length of
the board. The material has an area mass density (per unit area) of pkg/m²
dA
w(x) = 2(√L-√x)
L
F(x,y)
a) What is the weight of the board? Derive it by integrating weight of a differential element, dA located at x and that has a
width w(a) as shown.
b) What is the moment of the weight of the board about the y-axis. Derive it by integrating the moment applied by the
differential element, dA, located at distance r away from the fixed edge.
c) An additional distributed load, that is constant along the width but changes with distance as F(x, y) = kr² N/m², is
applied on the board (the gray surface in the figure is the force function). What is the moment applied by this external
load on the fixed edge. Solve this using a similar approach as step (b).
Transcribed Image Text:3. A board whose width changes as w(r) = 2(√L-√x) (0 ≤ x ≤ L), as shown is fixed on the left edge. Here L is the length of the board. The material has an area mass density (per unit area) of pkg/m² dA w(x) = 2(√L-√x) L F(x,y) a) What is the weight of the board? Derive it by integrating weight of a differential element, dA located at x and that has a width w(a) as shown. b) What is the moment of the weight of the board about the y-axis. Derive it by integrating the moment applied by the differential element, dA, located at distance r away from the fixed edge. c) An additional distributed load, that is constant along the width but changes with distance as F(x, y) = kr² N/m², is applied on the board (the gray surface in the figure is the force function). What is the moment applied by this external load on the fixed edge. Solve this using a similar approach as step (b).
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