1. К K>L 2. (~N v ~L) ^ (~M v ~O) 3. M→N 4. (0 N)^ (Р .. ("M v ~K) ^ (~O v ^P)
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Inference in Propositional Logic - Prove the conclusion from the given premises. Show the solution thank you.
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- Python numpy library functions to perform basic matrix operations are as follows.• C=numpy.add(A, B): Add two matrices A and B and store result in C.• C=numpy.subtract(A, B): Subtract matrix B from matrix A and store result in C.• C=numpy.divide(A, B): Divide matrix A by matrix B and store result in C.• C=numpy.multiply(A, B): Multiply matrix A by matrix B and store result in C.• C=numpy.sum(A): Form the sum of elements of matrix A and store result in c ∈ R.• C=numpy.sum(A, axis = 0): Form the column wise summation of matrix A andstore result in vector C.• C=numpy.sum(A, axis = 1): Form the row wise summation of matrix A, storeresult in vector C.Python code to show the implementation of these methods in a sample matrix.-05 Ex:->> x=[1 2 3 4]; >> y= [1 2 3 4]; > z=[12 3 4]; >> plot3 (x,y,z)10. Let A = {c, n, b}, B = {x, y} and C = {0, 1}. Find a) АХВХС b) СХВХА c) BXCXC
- Sum of two squares def sum_of_two_squares(n): Some positive integers can be expressed as a sum of two squares of some positive integers greater than zero. For example, 74 = 49 + 25 = 7^2 + 5^2. This function should find and return a tuple of two positive integers whose squares together add up to n, or return None if the parameter n cannot be broken into a sum of two squares.To facilitate the automated testing, the returned tuple must present the larger of its two numbers first. Furthermore, if some integer can be broken down to a sum of squares in several ways, return the breakdown that maximizes the larger number. For example, the number 85 allows two such representations 7^2 + 6^2 and 9^2 + 2^2 , of which this function must return (9, 2).The technique of two approaching indices that start from the beginning and end of a sequence, respectively, and approach each other until they meet somewhere is directly applicable to this problem. In this problem, these indices crawl towards each…The cateve cede x_m= [0;d b = [4₁2] L = [00;20] D = [3020 51 u U = [0 -1; 0 0 True Fallse Fac bdash = inv (L+D) *b; B = inv (L+D) * (°; For n = 2:44 2 x_m=bdash - B*x_m end for Jok p can be executed in order to apply three iteration of the Gauss-Seidel method, taking the initial approximetticD 20995 babisión P 3x₁ - x₂ = -4 2X1 +502 = 2 44 OR ان انار (0) X₁₁² =0=X₂₁₂²², to approximate the solution of the system 2 اورانJupyter Notebook Fixed Income - Certicificate of Deposit (CD) - Compound Interest Schedule An interest-at-maturity CD earns interest at a compounding frequency, and pays principal plus all earned interest at maturity. Write a function, called CompoundInterestSchedule, that creates and returns a pandas DataFrame, where each row has: time (in years, an integer starting at 1), starting balance, interest earned, and ending balance, for an investment earning compoundedinterest. Use a for(or while) loop to create this table. The equation for theith year's ending balance is given by: Ei =Bi (1+r/f)f where: Ei is year i's ending balance Bi is year i's beginning balance (note: B1 is the amount of the initial investment (principal) r is the annual rate of interest (in decimal, e.g., 5% is .05) f is the number of times the interest rate compounds (times per year) The interest earned for a given year is Ei - Bi Note the term of the investment (in years) is not in the above equation; it is used…
- Plot. % MA TLAB code for range rng = linspace(-pi,pi,1000); % Plotting sin^2 plot(rng, sin(rng).^2) hold on % Plotting cos^2 plot(rng,cos(rng).^2) % Creating an array of character vectors lgd = {'sine', 'cosine'}; % Converting the array into cell array lgd=cell(lgd); % Adding legend legend(lgd).3 نقاط * The statement that extracts the element (8) from the following matrix -:is [5 1 4] 930 8 2 x = A(2,3); O x = A(3, 2); O x = A(2); O x = A ( 3 ); O x = A(end); O A = L6Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax