The enzyme triosephosphate isomerase (TIM) catalyzes the following reaction in glycolysis,where it converts dihydroxyacetone phosphate (DHAP) to glyceraldehyde-3-phosphate (GAP).CH₂OHC=OCH₂OPO²-DHAPtriose phosphateisomerase[DHAP] (MM1.002.003.006.00OV. (mM/s)3.7006.7279.25014.800=HHCOHCH₂OPO²-Kinetics experiments were performed on TIM. Enzyme activity (initial velocity, V.) was measuredat varying concentrations of DHAP. The enzyme kinetics were also measured in the presence oftwo inhibitors, A and B. The enzyme concentration used in all experiments was 25.00 μM. Thedata are shown below.GAPV. (mM/s) + A1.4522.7944.0387.281V₁ (mM/s) + B0.7551.3791.9053.077 1. For the uninhibited enzyme, calculate the slope and y-intercept of the Lineweaver-Burkgraph.2. Calculate values of Km and Vmax for TIM.3. How long (in seconds) does a single catalytic event take?4. What will be the V, at 9.00 mM [DHAP] and 25.00 µM [TIM]?

To solve all the 4 questions, we need to draw the Lineweaver Burk (LB) plot in the absence of…

Answered: 1. For the uninhibited enzyme,…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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1. For the uninhibited enzyme, calculate the slope and y-intercept of the Lineweaver-Burk graph. 2. Calculate values of Km and Vmax for TIM. 3. How long (in seconds) does a single catalytic event take? 4. What will be the V, at 9.00 mM [DHAP] and 25.00 µM [TIM]?