1. ADDI Ss0, Szero, 10 ADDI Ss1, Szero, 9 SB $s0, -10(Ssp) SB $s1, -9(Ssp) LB $s2, -9(Ssp)
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- func: sq: ADD X20, XZR, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X0, #0x0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 ADD X20, X20, #0x1 ADD X0, X20, #0x0 BL sq ADD X21, X21, X0 MUL x0, x0, x0 BR LR Assume the .text segment begins at address Ox00000000, and that the linker placed "sq" immediately after func in memory. Complete the following table (remove all leading Os and report your answer in hex): Absolute address of the function sq: Ox Byte offset of the first BL call: 0x 30 Byte offset of the second BL call: 0x 60 Byte offset of the third BL call: Ox ⁹⁰Ex. Assume that DS = 1120h, SI = 2498h and AX = 17FEH show the content of mem. Location after %3D execute the code below: 01 org 100h 02 MOV [SI], AX 03 ret Sol:Write ARM Assembly program to do: - ISBN Checksum Validator Use Keil uvision software to write and simulate an ARM assembly program that checks the validity of a given ISBN by verifying the checksum Helping Information to solve program : 1. An ISBN consists of nine digits plus a validation digit. 2. The digits are numbered from right to left as d1, d2 .. d10, with d1 being the validation digit. 3. You can define the ISBN number in a 10-byte array in the memory. Each digit is stored in a byte. 4. To check whether the ISBN is valid or not, the following calculations are performed: Result = (10 x d10 + 9 x d9 + ... + ix di + ... + 2 x d2) % 11 Calculate d1 11 - Result If the calculated d1 equal to the d1 in the input ISBN then it is valid If d1 = 10, it is written 'X' For example, given the following ISBN: ISBN = 5123487654 ISBN= 5 1 2 3 487654 d10 d9 d8 d7 d6 d5 d4 d3 d2 d1 Result = x 10 + x 9 + x 8 + x 7 + x 6 + x 5 + x 4 + x 3 + x 2 mod 11 = 216 mod 11 =7 d1 = 11 - Result = 11 -7 =4 ,…
- SUBJECT : COMPUTER NETWORKING (PLEASE PROVIDE COMPLETE RELEVANT SOLUTION) One important issue in networking is the performance of the network. The question is how can measure the performance of heterogeneous networks. For example, UIIT University network which provides access to students at both wired and wireless networks. In this kind of scenario: You may need to define key performance parameters that can be used to evaluate the network performance. If UIIT has a total bandwidth of 100Mbps and 40Mbps is reserved for admin and faculty. Due to COVID-19 pandemic total students coming daily altogether in morning and evening are 500. How much bandwidth a student can achieve if all students are using internet at the same time?Q6: For the following control implementation: opcode add addi lw SW beq BR JP DMwe Rwe Rwd Rdst ALUop ALUinB What is the case that DMwe control signal will be active (DMwe=1) and What is the case that ALUinB control signal will be inactive (ALUinB=0) !switch (x) { case 1: w = y*z; break; case 2: w = y/z; case 3: w += z; break; case 5: case 6: w z; break; de fault: w = 2; } 00000000004005e0 : rdx, Brex $0x6, &rdi 200614 *0x200ab0 (, &rdi, 8) 2005e0: 2005e3: 2005e7: 2005e9: 2005f0: 2005£3: 2005£7: 2005f8: 2005fb: 2005fd: 200600: 200602: 200607: 20060a: 20060b: 200610: 200613: 200614: 200619: mov cmp ja jmpq που imul retq που 0x200ad0 0x200ad8 0x200ae0 0x200c8 cqto idiv Brsi, Brax rdx, Brax retq mov sub retq που retq 8rsi, Brax 8rcx jmp 200607 που $0x1, Seax add srcx, trax $0x1, Seax 8rdx, Brax $0x2, Seax Write the results of the command (gdb) x /10xg 0x200aa0 Address Data (in 8-byte chunk in hexadecimal number, put in XX for unknown) 0x200aa0 0x200aa8 0x200ab0 0x200ab8 0x200ac0 0x200ac8
- Congestion Window ewnd (In Num of Segments) 35 Transmission Round (In RTT) Based on the provided graph following TCA Reno, enter the minimum value of ssthresh. Initial ssthresh = 8.Given: PDA Transition Diagram 0,ɛ/X 1,X/E 1,$/$ E,E/E 91 1,5/$ 9: E,X/X E,S/S qr Identify the strings whether either ACCEPTED or NOT ACCEPTED by the given PDA. NOTE: 0, E/X means read/consume data (0), NO POP (E) / PUSH X E, E / E means NO read/consume data (E), NO POP (E) / NO PUSH (E) ✓00001111 ✓00011111 ✓00000111 ✓0000011111 A. NOT ACCEPTED B. ACCEPTED13 P CODE 123456 123457 123458 213345 254467 311452 P_DESCRIPT Flashlight Lamp Box Fan 9v battery 100W bulb Powerdrill PRICE 1.3.2 Change the price of the Flashlight to 7.20 1.3.3 Delete Lamp from table PRODUCTS 1.3.4 Determine the cheapest product price 1.3.5 Determine the average price of all the products 25.15 10.99 1.92 1.47 34.99 Use an SQL command to do the following: 1.3.1 Insert a new row with the following data (P_CODE = 311234 P_DESCRIPT = hammerdril, PRICE = 8000)
- 00000000 <main>: 0: lea 0x4(%esp),%ecx 4: and $0xfffffff0,%esp 7: pushl -0x4(%ecx) a: push %ebp b: mov %esp,%ebp d: push %ebx e: push %ecx f: sub $0x10,%esp 12: mov %ecx,%ebx 14: movl $0x0,-0xc(%ebp) 1b: movl $0x1,-0x10(%ebp) 22: jmp 48 <main+0x48> 24: mov -0x10(%ebp),%eax 27: lea 0x0(,%eax,4),%edx 2e: mov 0x4(%ebx),%eax 31: add %edx,%eax 33: mov (%eax),%eax 35: sub $0xc,%esp 38: push %eax 39: call 3a <main+0x3a> 3e: add $0x10,%esp 41: add %eax,-0xc(%ebp) 44: addl $0x1,-0x10(%ebp) 48: mov -0x10(%ebp),%eax 4b: cmp (%ebx),%eax 4d: jl 24 <main+0x24> 4f: mov -0xc(%ebp),%eax 52: lea -0x8(%ebp),%esp 55: pop %ecx 56: pop %ebx 57: pop %ebp 58: lea -0x4(%ecx),%esp 5b: ret Command line arguments are passed to int main(int argc, char** argv) as…00000000 <main>: 0: lea 0x4(%esp),%ecx 4: and $0xfffffff0,%esp 7: pushl -0x4(%ecx) a: push %ebp b: mov %esp,%ebp d: push %ebx e: push %ecx f: sub $0x10,%esp 12: mov %ecx,%ebx 14: movl $0x0,-0xc(%ebp) 1b: movl $0x1,-0x10(%ebp) 22: jmp 48 <main+0x48> 24: mov -0x10(%ebp),%eax 27: lea 0x0(,%eax,4),%edx 2e: mov 0x4(%ebx),%eax 31: add %edx,%eax 33: mov (%eax),%eax 35: sub $0xc,%esp 38: push %eax 39: call 3a <main+0x3a> 3e: add $0x10,%esp 41: add %eax,-0xc(%ebp) 44: addl $0x1,-0x10(%ebp) 48: mov -0x10(%ebp),%eax 4b: cmp (%ebx),%eax 4d: jl 24 <main+0x24> 4f: mov -0xc(%ebp),%eax 52: lea -0x8(%ebp),%esp 55: pop %ecx 56: pop %ebx 57: pop %ebp 58: lea -0x4(%ecx),%esp 5b: ret Command line arguments are passed to int main(int argc, char** argv) as arguments argc and argv. You should…What is the minterm that equals 1 if x₁ = x3 = 0 and X2 = X4 = X5 = 1, and equals 0 otherwise if x₁ is MSB and x5 is LSB? X1