1- How to read data from Memory location 0100 by using the figure ? MOV AX,0 0100 0102 0100 Address Bus Data Bus Instruction Pointer Decode Unit General Purpose Register AX Execute Unit Instruction Register
Q: Q4./DS 2000, SS 3000, BX-012A, BP-021B, DI 0010 SI 0020. 1. Compute the offset of each of the…
A: We solve the question in figure: Figure 1:
Q: A- The Hardware Architecture Shown in Figure (2), is it a Von-Neumann Architecture or Harvard…
A: According to the information given:- We have to find out the mentioned hardware architecture is…
Q: For a 512k x 32 memory system, how wide does the incoming address bus needed to be in order to…
A: Given, Size of memory system = 512k x 32 For a p x q memory system, Size of address bus = log 2 p…
Q: 12. What is the content value for instruction address 803? * PC 804 AC 804 АС 1CC6 PC D4CA IR 5913…
A: Program counter PC stores the address of next instruction. Given address of current instruction is…
Q: What is the correct address range for a microprocessor with 42 address lines? a. 0000000000 -…
A: Actually, binary numbers are nothing but a 0's and 1's.
Q: The Hack architecture partitions the address space and does not allow both data and instructions to…
A: The Hack computer is a 16-bit von Neumann machine, it consists of CPU, separate memory modules for…
Q: 2) A digital computer has a memory unit with 32 pits per word. The instruction set consists of 102…
A: Given:-
Q: 1. A central processing unit (CPU) has the following hardware components: Program Counter (PC) •…
A: All registered CPU - connected to two internal buses Memory Bus
Q: Desired to have a memory of = 64K bytes. No of bits in address bus to address memory location = 13…
A: Desired to have a memory of = 64K bytes.No of bits in address bus to address memory location = 13…
Q: Instructions that when executed provide desired features, functions and performance is a. software…
A: Instructions are the statements that forces hardware to do activities in computer system.
Q: 12. What is the content value for instruction address 803? * PC 804 AC 804 АС 1CC6 PC D4CA IR 5913…
A: Given address of current instruction is 803 The program counter (PC) holds the address of the next…
Q: Table Q15 shows the micro-operations of fetch cycle, interrupt cycle, and execute cycle of the ADD…
A: Here we write micro-operation in simple way:…
Q: 04. Intel 8086 microprocessor: aCan have 16 Mbyte memory. b Canaddress 16address bus lines. S- Can…
A: The Intel 8086 Microprocessor is an updated variant of the Intel 8085 Microprocessor, which was…
Q: Q5: Compare the following [o Stack Segment and Extra Segment Register Control Flag Register and…
A: Answer :- 1) Stack segment and Extra segment register The stack segment register (SS) is usually…
Q: 58. The memory location’s address where data is to be stored is specified by ___________. a. Memory…
A: The Memory Address Register includes the address of the memory location that is to be read from or…
Q: Register Indirect Addressing C.f. indirect addressing EA = (R) %3D Operand is in memory cell pointed…
A: The address of the operand is directly placed in one of the registers in case of Register Indirect…
Q: Stack Segment and Extra Segment Register Control Flag Register and Conditional Flag Register Logical…
A: 1- Extra Segment Register (ES): also refers to a segment in the memory which is another data segment…
Q: Help please mcq After execution the far jump instruction: JMP A3000127h; the new value of Physical…
A: Solution
Q: What are the duties of segment registers? Select one: a. Physical Address b. Offset Address c.…
A: Answer to the given question A segment register changes the memory address accessed by 16 bits at a…
Q: What is the address space of a processor with 32-bit data bus & 32-bit address bus
A: Some of this is based on how your define "32-bit". As a hardware engineer, I think of 32-bit as a…
Q: A 10-bit address bus support(a) 1,000,000 memory addresses (b) 1024 memory addresses(c) 100 memory…
A: Answer: (b) 1024 memory addresses
Q: 3. Explain in paragraph format what is happening in this example: Address >Add Instruction memory…
A: Introduction to Pipelining Pipelining is a method of breaking down a sequential process into…
Q: Q3. Mark True or False, correct when false: a) Address bus is bidirectional b) Data bus is…
A: NOTE: As per our guidelines we are supposed to answer only one question. Kindly repost other…
Q: Suppose that a 64MB system memory is built from 64 1MB RAM chips. How many address lines are needed…
A: Answer :
Q: Q6. Answer True or False for the followings: a) Machine code is the assembly code b) Data field is…
A: machine code is the assembly code data field is 16 bit while address field is 8 bit Trainer kit can…
Q: The Kiwi™ memory architecture design team has a dilemma. The team is considering several different…
A: a) Design 1 logical address width = 12 bits logical memory size = (2^12)bytes page size = 16 bytes…
Q: Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache A simple processor shown in the…
A: subtraction, addition and multiplication operations are given below:- by bartleby guidelines i am…
Q: 3. A microprocessor has .... ... Data Bus a. unidirectional b. bi-directional с. Both 4. A…
A: Answer : Bi-directional A microprocessor has bi-directional data bus. Explanation: A data bus in a…
Q: A Large Memory with the following buses: Address bus 32 bit. Data bus 32 bit. If we want to build…
A:
Q: Q1: Explain why 8086 Microprocessor have Data line 16 bit and Address line 20 bit.
A: 8086 Microprocessor have data line and address: It is enhanced version it was designed Intel in…
Q: CPU Main Memory Instructions Space MAR ALU MBR АС BUS PC Control Data Space Cache Explain in your…
A: Here it is the architecture of the simple processor, it having the two main blocks those are CPU and…
Q: The PIC 12F508/509 block diagram Program memory Data bus for program memory, carrying instruction…
A: Functions of peripherals (PIC12F508/509):• 6 I/O pins:- 5 I/O pins with individual direction…
Q: CPU Main Memory Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache Step by step…
A: Given is in a reaction between Fe+3 and NCS-, Kc = 620.4 Volume of Fe+3 = 10 mL molarity of Fe+3 =…
Q: Assume that an Intel CPU has address bus 25-bits wide. What is the maximum addressable memory?…
A: Given: Intel CPU has address bus 25-bits wide .what is maximum addressable memory
Q: 21 - In the microprocessor, the leftmost 3 bits of the 14-bit address bus are reserved for Chip…
A: Given: leftmost 3 bits of the 14-bit address address bus contains 2FBAH find the selected device ID
Q: Take a look at the picture of MIPS 800 Instruction Decode Register Fetch ID Execute Address Calc.…
A:
Q: 1) given the size of the word accessible main memory is 1KB and the size of the word is 16-byte, the…
A: Given Data : Memory size = 1KB Size of memory word = 16 Byte Number of registers = 64
Q: Symmetric multiprocessing architecture of the computer system uses shared a. bus b. memory c.…
A: Let's see all the options: Option (a) : bus Bus is used for transferring data from main memory to…
Q: provide a short explanation on how memory addressing works and why it's important?
A: Addressing Memory: A memory address is a unique address that the device or CPU uses to track…
Q: Explain why 8086 Microprocessor have Data line 16 bit and Address line 20 bit.
A: 8086 microprocessor :- 8086 microprocessor is the enhanced and advanced version of 8085…
Q: processor with 40-bit address pins and 64-bits data pins
A: Given address pins = 40 bits Data pins = 64 bits
Q: Calculate the physical address. Assume DS = 1234h, AX = 4523h with the help of memory diagram. MOV…
A: S. No. 8086 microprocessor 8088 microprocessor 1 The data bus is of 16 bits. The data bus is of…
Q: CPU Main Memory Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache A simple processor…
A: Given is in a reaction between Fe+3 and NCS-, Kc = 620.4 Volume of Fe+3 = 10 mL molarity of Fe+3 =…
Q: CPU Main Memory Instructions Space MAR ALU MBR AC BUS PC Control Data Space Cache A simple processor…
A: According to the guidelines i can answer only first 3 subparts
Q: Suppose that a 32MB system memory is built from 32 1MB RAM chips. How many address lines are needed…
A: As it is given that there are 32 RAM memory chips. To represent 32 different binary numbers we…
Q: In a computer instruction format, the instruction length is 11 bits and the size of an address field…
A: Given:Instruction length = 11 bits = 211 = 2048 bitsAddress register size = 4 bits
Q: Q6) What is a Volatile and Non-Volatile memory? Show the construction of ROM for 32 x 8 ROM. Q7)…
A: Hi, since there are multiple questions in this post, as per our policy, I'll answer the first…
Q: Question#l: Choose the correct answer 1. In 8086 microprocessor , the address bus is А. 12 bit bit…
A: Correct option is 'd' that is 20 bit wide.
Q: The memory unit of a computer has 2M words of 32 bits each. The computer has an instruction format…
A:
Q: Q5. Given the content of memory and the registers below. i. Indicate the type of addressing mode of…
A: The answer has been given in the below steps:
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- A(n) ________________ instruction always alters the instruction execution sequence. A(n) ______________ instruction alters the instruction execution sequence only if a specified Condition is true.If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?Most Intel CPUs use the __________, in which each memory address is represented by two integers.
- 用Reac Crar Consider the diagram below that shows the fetching data flow for an indirect cycle along with the content of some memory addresses. What will be the content of the MAR register after finishing the execution of the indirect cycle for the instruction "ADD (750)" that uses indirect addressing mode? CPU MAR Memory Control unit Address Content 220 750 340 900 750 340 MBR 900 860 Address Data Control bus bus bus Select one: О 900 O 220 O 750 O 340 O860 ONone of the mentioned cholces is correct, 在Register R1 (used for indexed addressing mode) contains the value: 0x200 Memory contains the values below (memory address -> contents) : 0x100 -> 0x600 ... 0x400 -> 0x300 ... 0x500 -> 0x100 ... 0x600 -> 0x500 ... 0x700 -> 0x800 When the instruction "Load 0x500" is executed, the value loaded into the AC is when using immediate addressing, it is when using direct addressing, it is when using indirect addressing, and when using indexed addressing.Q1- Write a program in assembly language for the 8085 microprocessor to send 10 bytes of data located at the memory address (3000H to 3009H) using SOD at a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When sending each of the required bytes, you must adhere to the following: The two high bits of the start bits must be sent, after that the data bits are sent, after that the low bit of the stop bit is sent. The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes. The solution must be integrated and include the calculation of the baudrate delay time Transmit No Set up Character Bit Counter Send Start Bit Wait Bit Time Get Character in Accumulator Output Bit Using Do Wait Bit Time Rotate Next Bit in Do Decrement Bit Counter Is It Last Bit? Yes Add Parity if Necessary • Send Two Stop Bits Return (a)
- 6. Assume that two numbers: dividend and divisor are saved in memory address M1 and M2 respectively. Quotient and remainder should be saved in R1 and R2 respectively. Write assembly language instructions and then list microoperations for each instruction and list the control signals required to be activated for each microoperation. MBR is used as buffer for any register to register transfer operation. Signal Description: Control signals operation Comments C0 MAR to RAM (through address bus) C1 PC to MBR C2 PC to MAR C3 MBR to PC C4 MBR to IR C5 RAM to MBR C6 MBR to ALU C7 Accumulator to ALU C8 IR to MAR C9 ALU to Accumulator C10 MBR to Accumulator C11 Accumulator to MBR C12 MBR to RAM (through data bus) C13 IR to Control Unit C14 MBR to R1 C15 MBR to R2 C16 MBR to R3 C17 MBR to R4…Computer Science A computer uses a memory of 64K words with 16 bits in each word.It has the following registers: PC, AR, TR, AC, DR and IRA memory-reference instruction consists of two words: an 16-bit operation-code(one word) and an address field (in the next word).a-List the sequence of microoperations for fetching a memory reference instructionand then placing the operand in DR. Start from timing signal To.b-Design the logic control gates arrangement to perform the fetch instructions.333: E8B3 8B3: 0A12 A12: 2153 Since the contents of the relevant addresses are 333 in the basic computer given above, the initial value of the PC is 333; When fetching and executing an indirectly addressing ISZ instruction, write the contents of the following registers in hexadecimal (hex) format for the T5 time. AR ........... DR......... IR ........... PC ........... SC ...........
- 02:- (A) Find the phicycal address if (BP) = 0100H, (SI) = 0200H , (SS) = 2000H and a displacement of 10H, of the instruction MOV AL. (BP+S+10H]. Which the name of Addressing Modes? 02:- (B) Find the result of the following: 1111-iIH+110010111011B 03: Write a piece of code to find the number of negative integers in an array of size 1024 bytes contain signed numbers stored at addresses starting at 21000H, store the result in a location 51000HQ1- Write a program in assembly language for the 8085 microprocessor to receive 10 bytes of data via the SID and store it at the memory address (3000H to 3009H) using a baud rate of 1200. Information: The 8085 processor operates at a frequency of 3.072 MHz. When you receive each byte of the required bytes, you must adhere to the following: The bits of two high bits will be received at the beginning of the reception (start bits), after that the data bits will be received, after that the low bit of the stop bit will be received (stop bit). The following flowchart will help you, but you should notice that this flowchart deals with one byte, and you are required to deal with 10 bytes The solution must be integrated and include the calculation of the baudrate delay time Of+CD!HID+[00 Yes SIDATA Read SID Start Bit? Wait for Half-Bit Time Set up Bit Counter Wait Bit Time Read SID Save Bit Decrement Bit Counter All Bits Received? Add Bit to Previous Bits Go Back to Get Next Bit Return IMUNIQ5. Given the content of memory and the registers below. i. Indicate the type of addressing mode of each line of instruction belowii. Deduce the target addressiii. Deduce the Value loaded into accumulator register (A) 10 marks Data at location Memory Address03600 3030103000 360000C303 6390003030 C303Memory content Base Register (B) 00600Program Counter (Pc) 003000Index Register (X) 000090 Register Content Instructions Opcodes - LDA = 00SN opcode n i x b p e Displacement Target Address (TA)1 000000 1 1 0 0 1 0 0110 0000 0000 2 000000 1 1 1 1 0 0 0011 0000 0000 3 000000 1 0 0 0 1 0 0000 0011 0000 4 000000 0 1 0 0 0 0 0000 0011 0000 5 000000 1 1 0 0 0 1 0000 1100 0011 0000 0011