Lab1_report

An 8085 assembly language program is given below. Line 1: MVI A, B5H 2: MVI B, OEH 3: XRI 69H 4: ADD B 5: ANI 9BH 6: CPI 9FH 7: STA 3010H 8: HLT The contents of the accumulator just execution of the ADD instruction in line 4 will be

Here is the data flow diagram for a particular instruction. The various values shown indicate the state of the machine after the action of this instruction. The question mark locates this instruction in memory. GatePC DR 100 GateMARMUX RO X2FFF PC X RI x3006 MARMUX TRAPVECTOR R2 x3005 X0:0 PCMUX R3 x3004 ZEXT R4 x3003 OFPSETŐ OR R5 x3002 PC OR BASER R6 x3001 PCOFFSET (7:0) R7 x3000 ADDR2MUX ADDRIMUX SR2 SRI (100 SEXT IMMS SEXT SRZMUX SEXT FINITE [50] SEXT STATE [40] MACHINE Arith/Logic Operation AL select IRO01 A/L RESULT LOGIC GateALU Gate MDR 16 16 MDR MAR T16 МЕМORY x 30 0O x 30 0 1 X 3:0:0 2 x3003 x3004 x 30 03 x3001 x: 3:0 0 4 X 30 05 X300 6 x3000 x3006 x3002 What is that instruction in binary? (You may use any number of spaces to organize the bits.) address instruction х3002

The numbers from 0-9 and a no characters is the Basic 1 digit seven segment display * .can show False True In a (CA) method of 7 segments, the anodes of all the LED segments are * "connected to the logic "O False True Some times may run out of pins on your Arduino board and need to not extend it * .with shift registers True False

logic circuit just draw the graph please as soon as possible

Task 08 Perform the following arithmetic operations 1. 236DF * AF 2. 8A32F4D5/ C9A5 3. CA92 * BAF9 4. C2A2 * ABCD / BED Task 09 (Home Task) Write two examples for each combination of registers possible for the 'mov' instruction. Hint: See the table above to see all the possible combinations. Task 10 (Home Task) Write two examples for each combination of registers possible for the 'add' and 'sub' instructions. Hint: See the table above to see all the possible combinations. Task 11 (Home Task) Perform the following arithmetic operation: (1+ 2) * (3 – 1) /5 +3 + 2- (1 * 2)

Here is the data flow diagram for a particular instruction. The various values shown indicate the state of the machine after the action of this instruction. GatePC DR 101 GateMARMUX RO OnFFFO OxFFFE PC X RI MARMUX TRAPVECTOR R2 OxFFFD X:0:0 PCMUX R3 OFFFB EXT R4 ODFFA OFFSET6 OR R5 OXFFFD PCOFPSET PC OR BASER R6 OcFFFC (7:0) R7 OscOFO8 ADDR2MUX ADDRIMUX SR2 SRI 010 [100] SEXT IMMS (8:0) SEXT SEXT FINITE SRZMUX [50] SEXT STATE [4:0| 2 MACHINE Arith/Logic Operation AL select A/L RESULT LOGIC GateALU Gate MDR 16 MDR MAR 16 OUTPUT INPUT MEMORY XFE02 XFE06 What is that instruction in binary? (You may use any number of spaces to organize the bits.) address instruction x3002

RESEARCH Draw at least 4 typrs of IC. Discuss the different IC packages. How to identify the pin numbering of IC? Proper handling of IC. What is seven-segment display? How to produce the required decimal digit from 0 through 9 using seven-segment display? Uses of seven-segment display.

Question 1: Use Indirect addressing to write a PIC24 assembly code that complements and adds 5 and multiply by 2 to 1024 data bytes into the memory at starting address Ox1000. The original data are stored in the memory starting from address 0x800. it is an electrical engineering question . this is the full information about the question!

Which of the following is the type of function unit digit and data functions written mathematically?

What is the purpose of the break statement? Force the termination of a program. When a break statement is encountered in a loop, the loop terminates immediately and the execution resumes the next statement following the loop. To produce the systematic code, and the break statement does not affecting the program. To make the code easy to understand.

Consider the following assembly program MOV CX, 1100H DLY: SUBS CX, CX, #1 NOP BNE DLY NXT: --- (a) How many times does the BNE DLY instruction get executed? (b) Change the first line of the program so that BNE DLY is executed 34 times (c) Change the second line of the program so that BNE DLY is executed 34 times, while the fist line stays unchanged (MOV CX, 1100H)

1 _ Compare between the status and control flags? Explain the status flags for the operation AEH+37H ? 2) 2 _What are the purposes of both segmentation and physical generation? Explain with draw and numerical example?

ehcu.org/pluginfile. هل ترید اس لم يقم إيقاف + 100% 10 / 11 Questions:- 1- Write a program in assembly language to perform the following logic ci CI DL [5100]. 2- How we can perform the NEG and NOT instructions by using different instructions. 3- Write the following program by using different instruction or instructions for each instruction on the program. MOV AL , 00 MOV BX , FFFF XOR CL , FF NEG BYTE PTR [DI] AND CX , 161756649_26189.jpg O 12.jpg LG

RESEARCH What is an INTEGRATED CIRCUIT (IC)?  Uses or applications of Integrated Circuit. Types of Integrated Circuit. Draw at least 4 typrs of IC. Discuss the different IC packages. How to identify the pin numbering of IC? Proper handling of IC. What is seven-segment display? How to produce the required decimal digit from 0 through 9 using seven-segment display? Uses of seven-segment display.

Name the addressing mode for the following instruction MOV AL, [BX+SI] * Your answer

Write down the possible representation level from high level language to logical gates exists in machine architecture. How abstraction is implemented in ISA. In computer organization, how controls are different from data paths.

Would like to know the work behind the highlighted answers Q2: Consider a line of code- LDD $C100. Before execution of this line of code, the memory locations $C100, $c101, $C102, and $C103 was holding $33, $4A, $5A, and $6A, respectively. After execution of the code what would be the content of ACCA and ACCB: I $33 and $5A O $5A and 6A O $33 and $4A O $4A and 5A Q3: Consider a line of code- ADDD $C100. Before execution of this line of code the memory locations $C100, $C101, $C102, and $C103 was holding $33, $4A, $5A, and $6A, respectively and ACCA and ACCB were holding $00 and $11, respectively. After execution of the code what would be the content of ACCA and ACCB: O $33 and $5B O $33 and 5A $5A and $6A O $5A and $6B

What is the result of the following FAL instruction? Input L1 Loo a. O b. O C. A HE e. Ladder logic program FAL FILE ARITH/LOGICAL Control Length Position Mode Destination Expression None of the choices (EN) (DN) Incremental (ER) #N7:101 R6:2 6 0 0 N7:100 On successive transitions, data will be copied from N7:100 into the next position in the file #N7:101 until N7:106 is reached Once input A becomes true, data will be copied #N7:101 into the next address of N7:100 O d. On successive transitions, data will be copied #N7:101 into the next address of N7:100 Once input A becomes true, data will be copied six times from #N7:100 into the word #N7:101

A. Use Microsoft Visual Basic to design a form contain two text boxes and one button called "add", and after click on "add", we get the summation of the numbers between (10 -30), and display the result on text box1 and get the summation of the numbers between (60-80) and display the result on text box2.

Design a code converter that converts a decimal digit from BCD to excess-3 code, the input variables are organized as (A BC D) respectively with A is the MSB, the output variables are organized as (W X Y Z) respectively with W is the MSB, put the invalid decimal numbers as don't care. X= BCD'+B'D+B'C X= BC'D'+B'D+BC X= BC'D'+B'D+B'C X= BC'D'+BD+B'C

Question Vvv For a microprocessor similar to ATmega328p an 8 bit ADC uses a VREF = 3.3 V. When an analog read is executed the return value is 182. What Voltage is present on the input? Enter the value in the box provided in mV. Round to the nearest mV. No units are required .   .Full explain this question and text typing work only     We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line    ..

Align Text I U S AV Aa T T4 Convert to SmartArt- Font Paragraph Micro o operation EX: The memory unit of a computer has 256K words of 32 bits each. The computer has an instruction format with common fields. It has 60 processor registers. Specify the instruction format and the No. of bits in each field if the instruction is in one memory word. Solu:

A state machine can detect when it has received the serial input sequence 011. The input of the machine is 0 or 1.a. Draw state diagramb. Make table of state transitionc. Make the Boolean equation and simplifyd. Draw the circuit of FSM

Write program to load the content of memory location 0x0700 into register R3 then set D6,D7 and complement D4,D5 for date in R3 then store the result in memory location 0x0800 .

a) In Assembly programming what is the functionality of the following instructions DECFSZ ВTESC MOVLW MOVWF goto b) A piece of code is required for a time critical activity. Should this be written in assembly language or C? Explain your answer. 5 Explain the difference between the (For) and (While) loops. Highlight the main components of the (For) loop that are required for its execution. Consider the following C program designed to run on a PIC 18F4455. int main(void) 2 { 1 double voltage; double current; double milliwatts; double energyUsed; double cummulativeEnergy = 0; while (1) { voltage=analogRead (VOLTAGE_PIN)*voltageScaleFactor; current=analogRead (CURRENT_PIN)*currentScaleFactor; milliwatts=voltage*current; energyUsed=milliWatts*0.5; cummulativeEnergy=cummulativeEnergy+energyUsed; 10 11 12 13 14 15 _delay_ms (500); 16 } 17 a) What is the role of the symbols "{" and "}" b) The code here is indented. Explain the importance of indentation N m 4 n Or 00 o A m

What are the two primary categories of output circuits that are used in TTL?

a. (697)10 into Octal and Hexa decimal b. (2D9)16 into Decimal and Octal

give the final result of operation that appears onto OUT-Reg. after convert the whole program below into Op-code? Address OH 1H 3H 4H 5H Mnemonic LDA AH US Address 6H 7H 8H 9H AH BH CH DH EH FH DATA FFH FFH FFH 01H OEH 01H OFH FFH FFH FFH

QUESTION 1 You have used DEBUG to unassemble the following instructions. -U 0100 0108 1369:0100 B84365 MOV AX, 6543 1369:0103 BB3394 MOV BX, 9433 1369:0106 F7E3 DEC BX 1369:0108 CD21 INT 21 The last byte of the instruction loaded at address 0106 is stored in address. 0100 0106 0107 0108