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The greenhouse effect can be explained easily if you understand the laws of blackbody
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- Earth's daylight surface disk absorbs about 1036 W per m2 from the Sun. Using 6400 km for the Earth's radius, how much of this radiative power is emitted by each square meter of the spherical Earth? Hint: Compare the ratio of the disk area to the spherical surface area.arrow_forwardThe photovoltaic systems are designed based on “Peak Sun Hours.” What is peak sun hour?arrow_forwardHow many watts of radiation does a 1-meter-square region of the Sun’s spot emit, at a temperature of 5000 K? How much would the wattage increase if the temperature of the spot were twice as much, 10 000 K?arrow_forward
- What is the temperature of the Sun (google for the answer)? What is the re-entry temperature of the Space Shuttle (google for the answer)? Why don’t you burn up at the reentry temperature of 17318.5K for this Mach 20 flow? Why do you think that the body should actually re-enter the Earth's atmosphere in the opposite direction. (ie.. blunt/flat surface first.)arrow_forwardOur Sun has a surface temperature of about 5800 K. Find the emitted power per square meter of peak intensity for a similar star with 4600 K that emits thermal radiation. Express your answer in scientific notation and with three significant figures.arrow_forwardThe surface temperature of the Sun is about 6000K. For this question, assume it is exactly 6000K. Now suppose that the surface temperature of the Sun was 12,000 K, rather than 6,000 K. a) How much more thermal radiation would the Sun emit, compared to its current output? Answer as a whole number, which is the ratio of the new to the old output.arrow_forward
- Solar scientists want to measure the temperature inside the sun by sending in probes. Imagine that temperature increases by 1 million◦C for every 10,000 km below the surface. A probe that can handle a temperature of x million degrees costs x³ million dollars. a. How much would it cost to measure the temperature 10,000 km down? b. How much would it cost to measure the temperature 100,000 km down? c. How much would it cost to measure the temperature 200,000 km down?arrow_forwardExplain how we use spectral absorption and emission lines to determine the composition of a gas.arrow_forwardMake a sketch of the Sun’s atmosphere showing the locations of the photosphere, chromosphere, and corona. What is the approximate temperature of each of these regions?arrow_forward
- Tutorial Star A has a temperature of 5,000 K and Star B has a temperature of 6,000 K. At what wavelengths (in nm) will each of these star's intensity be at its maximum? If the temperatures of the stars increase, the wavelength of maximum intensity. What is the temperature (in K) of a star that appears most intense at a wavelength of 829 nm? Part 1 of 4 Wien's Law tells us how the temperature of a star determines the wavelength of maximum intensity or at what wavelength the star appears brightest. 2.90 x 106 TK If the temperature is in kelvin (K) then A is in nanometers (nm). Anm ^A = AB = = Part 2 of 4 To determine the wavelengths of maximum intensity for the two stars: 2.90 x 106 2.90 x 106 K nm nmarrow_forwardWhat does the Wien Displacement Law (also known as Wien's Law) tell us? a) There is an inverse relation between the temperature of a thermal emitter and the wavelength where the emission peaks. b) There is a proportional relation between the temperature of a thermal emitter and the wavelength where the emission peaks. c) None of the above.arrow_forwardTutorial Star A has a temperature of 5,000 K. How much energy per second (in J/s/m2) does it radiate from a square meter of its surface? If the temperature of Star A decreases by a factor of 2, the energy will decrease by a factor of Star B has a temperature that is 5 times higher than Star A. How much more energy per second (compared to Star A) does it radiate from a square meter of its surface? Part 1 of 4 The energy of a star is related to its temperature by E = GT4 where σ = 5.67 x 10-8 J/s/m2/K4. Part 2 of 4 To determine how much energy Star A is radiating, we just plug in the temperature to solve for EA. EA = J/s/m² Submit Skip (you cannot come back)arrow_forward
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