You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 12.7 cM between the flower color locus and the plant height locus. There are 8.8 cM between the flower color locus and the leaf type locus. The coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny that are expected to have blue flowers and smooth leaves. Round properly to 4 decimal digits. Answer:
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- You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 8.3 cM between the flower color locus and the plant height locus. There are 12.4 cM between the flower color locus and the leaf type locus. The coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny that are expected to have red flowers and fuzzy leaves. Round properly to 4 decimal digits. Answer:Give typed full explanation You are studying three linked genes in snapdragons. The flower color locus is in the center. There are 13.8 cM between the flower color locus and the plant height locus. There are 14.5 cM between the flower color locus and the leaf type locus. The coefficient of coincidence is 0.8. Pure-breeding tall, red-flowered plants with fuzzy leaves were crossed to pure-breeding dwarf, blue-flowered plants with smooth leaves. The F1 were testcrossed. Calculate the proportion of the testcross progeny that are expected to be dwarf with red flowers. Round properly to 4 decimal digits.Two pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64
- In the model plant Arabidopsis thaliana, the following alleles were used in a cross: T = presence of trichomes t = absence of trichomes D = tall plants d = dwarf plants W = waxy cuticle w = nonwaxy A = presence of purple anthocyanin pigment a = absence (white) The T/t and D/d loci are linked 26 m.u. apart on chromosome 1, whereas the W/w and A/a loci are linked 8 m.u. apart on chromosome 2. A pure-breeding double-homozygous recessive trichomeless nonwaxy plant is crossed with another pure-breeding double-homozygous recessive dwarf white plant. a. What will be the appearance of the F1? b. Sketch the chromosomes 1 and 2 of the parents and the F1, showing the arrangement of the alleles.c. If the F1 is testcrossed, what proportion of the progeny will have all four recessive phenotypes?A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the F₁ had lacerate leaves (jagged-edged leaves). Two F₁ plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy? two genes, with a dominant allele at both loci two genes, where one allele at a single locus is recessive lethal one gene, with codominant alleles at a single locus two genes, with a dominant allele at either or both loci Give genotypes for all the plants in the P, F₁, and F2 generations. Some generations will have more than one genotype. P F₁ F₂ (lacerate) F₂ (normal) aabb A_B_ Answer Bank aaB AaBb A_bb AABBA strain of plants has a mean height of 24 cmcm. A second strain of the same species from a different geographical region also has a mean height of 24 cmcm. When plants from the two strains are crossed together, the F1F1 plants are the same height as the parent plants. However, the F2F2 generation shows a wide range of heights; the majority are like the P1P1 and F1F1 plants, but approximately 4 of 1000 are only 12 cmcm high, and about 4 of 1000 are 36 cmcm high. How many gene pairs are involved? Express your answer as an integer.
- A strain of plants has a mean height of 24 cmcm. A second strain of the same species from a different geographical region also has a mean height of 24 cmcm. When plants from the two strains are crossed together, the F1F1 plants are the same height as the parent plants. However, the F2F2 generation shows a wide range of heights; the majority are like the P1P1 and F1F1 plants, but approximately 4 of 1000 are only 12 cmcm high, and about 4 of 1000 are 36 cmcm high How much does each gene contribute to plant height? Express your answer as an integer.A cross was made between a Red and Long flowered (RRLL) plant and a blue and dwarf flowered (rrll) plant. The resulting F1 plants were testcrossed to blue and dwarf plants. 140 red and long 28 red and dwarf 32 blue and long 145 blue and dwarf After showing your Punnett square for the testcross, use the Chi Square test to determine if the genes are assorting independently. If they are linked, calculate the distance between the two genes. Show your work.Suppose that the wild type phenotype for tomatoes is red, round fruit with three-parted leaves and that a strain of mutant tomatoes has yellow, pear-shaped fruit with entire leaves. A and a represent the alleles for fruit color, B and b represent the alleles for fruit shape, and C and c the leaf shape. Two tomatoes with the genotypes Aa Bb cc and Aa Bb CC are crossed. The resulting Punnett square is shown. One cell has been completed with the correct tomato phenotype. Fill in the rest of the Punnett square by placing a fruit and leaf phenotype in each cell. ABC AbC aBC abC ABC Abc aBc abc Answer Bank
- What would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b C d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.A variety of opium poppy (Papaver somniferum L.) with lacerate leaves was crossed with a variety that has normal leaves. All the F1 had lacerate leaves. Two F1 plants were interbred to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. Give genotypes for all the plants in the P, F1, and F2 generations. Explain how lacerate leaves are determined in the opium poppy.In cucumbers, speckled fruit color (u') is dominant to uniform fruit color (u), and large spines (ss") are dominant to small spines (ss). These two genes are linked at a map distance of 20.4 m.u. A true-breeding cucumber plant with speckled fruit and large spines is crossed with a true-breeding plant with uniform fruit color and small spines. One of the F1 plants is crossed with a plant with uniform fruit color and small spines. What percentage of the offspring of this cross are expected to have uniform fruit color and small spines? 39.8% 10.2% 79.6% 20.4%