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- Explain the sex-linked traits. (S9LT-ld-29.4.4) Solve problems related to sex-linked traits. (S9LT-ld-29.4.4) WHAT I NEED (MATERIALS) • Worksheet • Pens WHAT TO DO (PROCEDURE) PART A Directions: Tell whether the following carry or show the sex-linke recessive spongy-tiny pores trait. Also, tell whether the individuals a male or female. Remember that since most sex-linked traits are recessive, the person w shows the trait can have no X's with big superscripted letters. So, if a m carries the trait, he must also show the trait. XDY XDXD XdY Carrier? (Yes or No) Has the Trait? (Yes or No) Male or Female Phenotype or Appearance of the Individual ided Questions: 1. What chromosomes will result to a normal phenotype (normal spongy po trait12Which of the following genotype(s) must a female child have in order to be color blind? XNXN XNXn XnXn XNY XnY (XN represents the normal color vision allele. Xn represents the color-blindness allele. Y represents the Y chromosome, which does not carry the color-vision gene.) Which of the following genotype(s) must a color-blind male have? Explain your rationale. XNXN XNXn XnXn XNY XnY (XN represents the normal color vision allele. Xn represents the color-blindness allele. Y represents the Y chromosome, which does not carry the color-vision gene.)Let us practice it again! Analyze the pedigree below to answer the questions that follow. Huntington's disease a disorder in which nerve cells waste away, or disintegrate, is passed down through families. certain parts of the brain Huntington's diseate llustration ereated in htps://pregenygenetion.com/ 1. What members of the family above are affected with the Huntington's disease? 2. Tnere are no carriers ior Huntungton's disease you either have it or you do not. Is Huntington's disease caused-by a dominant or recessive trait? 3. Identify the genotypes of the following individuals using the pedigree above. (homozygous dominant, homozygous recessive, heterozygous). I- 1 II -1: II -3: III - 4 : 4. How many children did individuals I-1 and I-2 have? 5. How many girls did II-1 and II-2 have? How many have Huntington's Disease? 6. How are individuals III-2 and II-4 related? I-2 and III-5?
- A woman with achondroplasia (a dominant form of dwarfism) anda phenotypically unaffected man have seven children, all of whomhave achondroplasia. What is the probability of producing such afamily if this woman is a heterozygote? What is the probabilitythat the woman is a heterozygote if her eighth child does not havethis disorder?Which genotype is homozygous? O aaBb O Aabb O AAbb O AABBGiven the karyogram below, anSW Is this a male or female? female Do you see any abnormality? Yes 13 Write the karyotype (genetically speaking)|
- Proband Sex-linked Brackets Arabic numerals Heterosis ||| E III III E III ||| Depict the birth order in a generation of offspring. The first time the condition being studied is recorded but not necessarily the first time the condition has occurred. Unusual vigor or increased function of an organism in a heterozygous state. Genes located on a sex chromosome result in sexually dependent inheritance of certain traits. Placed around a gender symbol such as a circle or square or diamond to indicate adoption. Open in Reading VCan We Talk About Sex? Mindy B. Statter Abstract: A three–year–old female undergoes elective inguinal hernia repair and unexpectedly is found to have testes in the hernia sacs. A recommendation is made not to disclose the patient’s genotype to her mother. This case study addresses the ethical conflict of whether to disclose the patient’s male genotype to the parent that has been raising the child as female. B. Now that disclosure of a CAIS diagnosis is mandatory, what responsibility would a parent potentially have to override a doctor’s recommendations for gender maintenance?Two parents plan to have three children. What is the probability that they will have two girls and one boy in no particular order (order unspecified)? 2 2. 8. What is the probability that these same parents have a girl first, then another girl, followed by a son last? Does this change the probability? How/Why? Genetics Chapter 2 Problems - P. 4 100
- In man, Huntington’s Chorea is autosomal dominant progressive brain disorder and often lethal (H), the individuals usually dying in middle age. Red-green color blindness is recessive and sex-linked (X c ). A double heterozygous woman marries a heterozygous Huntington’s Chorea colorblind man. What are the genotypes of the man and woman? What are the genotypes and phenotypes of the all the remaining offspring after all deaths caused by Huntington’s Chorea? Show COMPLETE cross. TIP: cancel out gametes with HHuman females have two X chromosomes (XX); males have one X and one Y chromosome (XY). a. With respect to X-linked alleles, how many different types of gametes can a male produce? b. If a female is homozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele? c. If a female is heterozygous for an X-linked allele, how many types of gametes can she produce with respect to that allele?A man is homozygous dominant for ten different genes that assort independently. How many genotypically different types of sperm could he produce? A woman is homozygous recessive for eight of these genes and is heterozygous for the other two. How many genotypically different types of eggs could she produce? What can you conclude about the relationship between the number of different gametes possible and the number of heterozygous and homozygous gene pairs that are present?