We are interested in comparing the average supermarket prices of two leading colas in the Tampa area. Our sample was taken by randomly going to each of eight supermarkets and recording the price of a six-pack of cola of each brand. The data are shown in the following table. Find a 98% confidence interval for the difference in mean price of brand 1 and brand 2. Assume that the paired data came from a population that is normally distributed. Price Supermarket Brand 1 Brand 2 $2.25 $2.30 2.47 2.45 2.44 2 4 5 6 7 8 2.38 2.27 2.15 2.25 2.36 2.37 x1 = 2.3125 $1 = 0.1007 2.29 2.25 2.25 2.42 2.40 x2=2.3500 $2=0.0859 (-0.1768, 0.1018) (-0.0846, 0.0096) (-0.0722, -0.0028) (-0.0779, 0.0029) Difference $-0.05 0.02 -0.06 -0.02 -0.10 0.00 -0.06 -0.03 d=-0.0375 Sd = 0.0381
We are interested in comparing the average supermarket prices of two leading colas in the Tampa area. Our sample was taken by randomly going to each of eight supermarkets and recording the price of a six-pack of cola of each brand. The data are shown in the following table. Find a 98% confidence interval for the difference in mean price of brand 1 and brand 2. Assume that the paired data came from a population that is normally distributed. Price Supermarket Brand 1 Brand 2 $2.25 $2.30 2.47 2.45 2.44 2 4 5 6 7 8 2.38 2.27 2.15 2.25 2.36 2.37 x1 = 2.3125 $1 = 0.1007 2.29 2.25 2.25 2.42 2.40 x2=2.3500 $2=0.0859 (-0.1768, 0.1018) (-0.0846, 0.0096) (-0.0722, -0.0028) (-0.0779, 0.0029) Difference $-0.05 0.02 -0.06 -0.02 -0.10 0.00 -0.06 -0.03 d=-0.0375 Sd = 0.0381
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.3: Measures Of Spread
Problem 1GP
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Transcribed Image Text:We are interested in comparing the average supermarket prices of two leading colas
in the Tampa area. Our sample was taken by randomly going to each of eight
supermarkets and recording the price of a six-pack of cola of each brand. The data
are shown in the following table. Find a 98% confidence interval for the difference in
mean price of brand 1 and brand 2. Assume that the paired data came from a
population that is normally distributed.
Price
Supermarket
1
2
3
4
5
8
Brand 1
$2.25
2.47
2.38
2.27
2.15
2.25
2.36
2.37
x1 = 2.3125
$1 = 0.1007
Brand 2
$2.30
2.45
2.44
2.29
2.25
2.25
2.42
2.40
x2 = 2.3500
$2 = 0.0859
(-0.1768, 0.1018)
(-0.0846, 0.0096)
(-0.0722,-0.0028)
(-0.0779, 0.0029)
Difference
$-0.05
0.02
-0.06
-0.02
-0.10
0.00
-0.06
-0.03
d = -0.0375
sd = 0.0381
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