(a) Determine the least squares linear fit to the data: p=mT+c (b) Use your model to calculate the resistivity, p, at T = 10 °C
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hello, may you please help me with part a and b ?
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- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.The following table provides values of the function f(x,y). However, because of potential; errors in measurement, the functional values may be slightly inaccurately. Using the statistical package included with a graphical calculator or spreadsheet and critical thinking skills, find the function f(x,y)=a+bx+cy that best estimate the table where a, b and c are integers. Hint: Do a linear regression on each column with the value of y fixed and then use these four regression equations to determine the coefficient c. x y 0 1 2 3 0 4.02 7.04 9.98 13.00 1 6.01 9.06 11.98 14.96 2 7.99 10.95 14.02 17.09 3 9.99 13.01 16.01 19.02A study was conducted to assess the relationship between students’s score in final exam (y) and number of hours spent for exam (x) in each day. Data on a random sample 20 students were obtained and a regression model was estimated; and the least squares estimates obtained are: intercept a=28.5 and slope b=4.3 with SE(b)=Sb=0.017. The SS are: TSS=2540 and ESS=850. ****** QA) What is the difference between exam score obtained by two students one who studied 5 hours and the other who studied 9 hours per day. QB) In the above Question 1, find 95% CI for the slope and interpret it. In the above Question 1, find and interpret the coefficient of determination (r-square value).
- A study was conducted among a smaple of undergraduate students to find the relationship between the number of cups of coffee consumed (x) and level of anxiety (y). The following least squares regression equation was obtained as a result of the study: ý = 0.3 + 0.0342z The obtained regression equation implies which of the following? Each cup of coffee consumed increases anxiety level by 30.0% Each cup of coffee consumed increases anxiety level by an average amoint of 3.42% Each cup of coffee consumed increases anxiety level by exactly 3.42% Anxiety level increases by 1 unit as a result of consuming 0.3 cups of coffeeA least squares regression line for the following information: n=30 Ex = 501.6 "Ea = 8724.74 Ey 1338.8 Ey = 61980.14 Ery = 23246.55 %3D 11 << 22 is ŷ = 2.550x + 1.993. %3D Compute the SSE using the formula SSE = SSYY - B, SSXY· -1335.8 O101.6 36.3 42.8 O 19.12was completed and is displayed in the computer output. Volume 0.640 - 0.006(Time) Regression Analysis: cuberoot (Volume) versus Time SE Coef Predictor Coef -0.006 0.00017 -35.294 0.000 Volume = - 0.006 + 0.640(Time) Constant Time 0.640 0.000018 35512.6 0.000 s0.030 R-Sq=1.000 R-sq (adj)=1.000 Volume = -0.006 + 0.640(Time) Save and Exit Next Submit Mark this and return & 7 8. 9 y
- he least-squares regression equation is y=660.8x +15,627 where y is the median income and x is the ercentage of 25 years and older with at least a bachelor's degree in the region. The scatter diagram indicates a inear relation between the two variables wvith a correlation coefficient of 0.7527. Complete parts (a) through (d). 55000- 20000- 15 20 25 30 35 40 45 50 55 60 Bachelor's % 適 展 (b) In a particular region, 27.9 percent of adults 25 years and older have at least a bachelor's degree. The median income in this region is $30,681 ls this income higher than what you Would expect? Why? This is lower than expected because the expected income is $ 34,063 (Round to the nearest dollar as needed.) (c) Interpret the slope. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal. Do not round.) %, on average. O A. For every dollar increase in median income, the percent of adults having at least a bachelor's degree is on average. B. For…he least-squares regression equation is y=660.8x +15,627 where y is the median income and x is the ercentage of 25 years and older with at least a bachelor's degree in the region. The scatter diagram indicates a inear relation between the two variables wvith a correlation coefficient of 0.7527. Complete parts (a) through (d). 55000- 20000- 15 20 25 30 35 40 45 50 55 60 Bachelor's % 適 展 (b) In a particular region, 27.9 percent of adults 25 years and older have at least a bachelor's degree. The median income in this region is $30,681. ls this income higher than what you would expect? Why? This is lower than expected because the expected income is $ 34,063 (Round to the nearest dollar as needed.) (c) Interpret the slope. Select the correct choice below and fill in the answer box to complete your choice. (Type an integer or decimal. Do not round.) %, on average. O A. For every dollar increase in median income, the percent of adults having at least a bachelor's degree is on average. B. For…Arm circumferences (cm) and heights (cm) are measured from randomly selected adult females. The 146pairs of measurements yield x=34.69cm, y=163.25cm, r=0.075, P-value=0.368, and y=157+0.1826x. Find the best predicted value of y (height) given an adult female with an arm circumference of 40.0cm. Let the predictor variable x be arm circumference and the response variable y be height. Use a 0.05 significance level. The best predicted value is ____cm.
- The following data is given: -0.2 -0.1 0.2 0.7 1.3 y 5.2 3 0.6 0.4 0.2 1 Determine the coefficients m and b in the function y = that best fit the data. тx + bWhen a stone is dropped in a pond, ripples are formed and travel in concentric circles away from where the stone was dropped. The equation of the least-squares regression line is log(Area) = 0.490 + 2.004 log(Time). What is the predicted area of the circle, in cm2, 4 seconds after the stone is dropped? O 49.72 cm2 199.43 cm2 311.89 cm2 O 1854.10 cm?Consider the following data set: (x, y) : (1.0, 5.1), (1.25, 5.79), (1.5, 6.53), (1.75, 7.45), (2.0, 8.46) If the least squares approximation of the form beax is y=(3.07) e0.5056)x then the total error is: Select one: O a. 0.150 O b. 0.0015 O c. 1.150 O d. 0.015
