The solution to the IVP, is x₁(t) x₂(t) x₁'= -3x1 - x2, x₂= 13x1 + 3x2, = = x₁(0) = 2 x2(0) = -8

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter4: Eigenvalues And Eigenvectors
Section4.2: Determinants
Problem 11AEXP
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The solution to the IVP,
is
x₁(t)
x₂(t)
x₁'= -3x1 - x2,
x₂= 13x1 + 3x2,
x2'=
=
=
x₁(0) = 2
x2(0)
=
-8
Transcribed Image Text:The solution to the IVP, is x₁(t) x₂(t) x₁'= -3x1 - x2, x₂= 13x1 + 3x2, x2'= = = x₁(0) = 2 x2(0) = -8
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