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- O e. Penetrance QUESTION 10 Sickle-cell anemia is a human disorder caused by a recessive allele (HbS) for the hemoglobin gene found on chromosome #11. The normal allele (HbA) is dominant. Mary has sickle-cell anemia, and she marries Steve, who does not have the disease. Mary and Steve have one kid Rosa, who has sickle-cell anemia. What is Steve's genotype? Oa. HbS Ob. HbSHbS O c. HbAHbS O d. HbAHbA Oe. Cannot be determined ck Save and Submit to save and submit. Click Save All Answers to save all answers. 7 20 # 3 $ 4 % 5 MacBook AirQuestion:- 3. Wild type Drosophila has red eyes and gray body*. Autosomal recessive mutations sepia (se) and ebony (e) modify the eye and body color, respectively. What kind of a cross (or crosses) can you set up to determine whether the two genes are linked? You have several lines to choose from: a pure-breeding wild type line (where alleles for both, sepia and ebony are wild type), a double homozygous recessive line, a pure breeding sepia mutant line and a pure breeding ebony mutant line. You don’t have to use all of them. (a) Write down the cross (or crosses, if necessary) which will allow you to determine linkage; include genotypes of both crossed individuals (b) What kind of results (offspring) do you expect if the two genes are linked? (c) What kind of results (offspring) do you expect if the two genes are not linked? For (b) and (c), state the phenotypes, genotypes and numbers.QUESTION 10 Consider the following pedigree. With no other information provided, what is the most likely mode of transmission (or mode of inheritance) of the allele for the unusual trait? autosomal dominant sex-linked recessive autosomal recessive O sex-linked dominant
- QUESTION 4. Red-green color blindness is inherited in an X-linked recessive manner. Joe is red-green color blind. Joe's mother and father both have normal vision, but his mother's father (i.e., Joe's maternal grandfather) is color blind. All of Joe's other grandparents have normal color vision. Joe has three sisters (Patty, Betsy, and Lora), all with normal color vision. Patty (Joe's oldest sister) is married to a man with normal color vision; they have two children, a 9-year-old color-blind boy and a 4-year-old girl with normal color vision. Joe marries a woman who is a carrier of the color-blind allele; they are expecting their first child. Patty & her husband are expecting their third child. L4.9 Q4 Homework • Unanswered Which of the following scenarios has a greater probability of occurring and by how much? Scenario 1: Joe's first child will be a color-blind boy. Scenario 2: Patty's third child will be a color-blind boy. Select an answer and submit. For keyboard navigation, use the…Question 17 Main Content sults following a FISH chromosomal painting experiment. Now what do you think this variation indicates? Chr5 a SNP Oa CNV a translocation from another chromosome a truncation of one homolog of this chromosomequestion- Color blindness is inherited as a sex-linked recessive disease. A normal male marries a female who is heterozygous for the trait. What percentage of their sons will exhibit color blindness?
- Question 21 Assuming the dominant phenotype is shaded, what is the genotype of individual 6? X-linked Dominant 10 11 O XY O X O XYQUESTION 3 Linkage disequilibrium is defined by which of the following? O Positions in the genome where people vary by a single nucleotide base O The occurrence of two alleles in the repulsion configuration O The probability that two genes are linked O Crossing over that occurs between two genes that are located close to each other O The nonrandom association between alleles in a haplotype QUESTION 4 Red-green color blindness is a human recessive X-linked disorder. A young man with a 47, XXY karyotype (Klinefelter syndrome) is colorblind. His mother and father have normal color vision, but his mother has a father who is colorblind Did the nondisjunction event that gave rise to the young man with Klinefelter syndrome happen in the mother, the father or is it impossible to tell (assume that no crossing over took place in prophase I of meiosis)? a. Mother b. Father c. Impossible to tell Did this nondisjunction happen during Meiosis I, Meiosis II, or is it impossible to tell? a. Meiosis I…Question 6 HH is O homozygous O heterozygous O genotype O phenotype
- Question: This is a normal 3 point test cross, except that instead of regular phenotypes, you are looking at DNA markers on a gel. One parent, according to the gel, is heterozygous at each marker. The other parent is homozygous for each marker. (Again, this means it is a test cross: AaEeHh x AAEEHH --but don't be confused by that, because these are not "dominant" and "recessive" per se; the phenotype is just a band on a gel). For each offspring, figure out its genotype (homozygous or heterozygous for each gene. Then, figure that one parent made only AEH gametes, so you can cross that out if it helps.) Then treat it pretty much the same as a 3 point test cross.Quèstion 14 Methylation silences the gene expression. O True O FalseQuestion 14: You examined 8 mutants, so in theory there could be 8 complementation groups (designated below as Group A- Group H). Organize the mutant strains into complementation groups. Entry Format: Each Group: If the answer includes multiple strains, please enter the answer with no spaces, but separate the numbers with a comma, and place those numbers in sequential order (e.g. 1,2,3). Organization of groups: Go in sequential order downwards by the first number of each group. i.e. Group A: 1,2,3 Group B: 4,7 Group C:5 etc. If or once you have used up all of your groups simply type in "None" for the remainder of the groups. Group A: 1,5,7 Group B: 3,6,8 Group C: 2 Group D: 4 Group E: Group F: Group G: Group H: