A support structure is fixed at the base as shown with a weight, W=76 lb, and a moment M =907 ft lb CW around the z-axis, and a force, F = -46i lb. The dimensions shown are a = 4.3ft, b=9.7ft, c=5.8ft, and d=14.8ft. a. What is the moment caused by the force, F? b. What is the moment caused by the weight, c. What are the force support reactions at the base? d. What are the moment support reactions at the base? W b M Fixed at base F
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- (a) Calculate the moment of the 90-N force about point O for the condition @ 15. Also, determine the value of 6 for which the moment about O is (b) zero and (e) a maximum. Ans. (a) Mo-33.5 N m CCw (b) @-36.9 (or 217") (e) 8 126,9 (or 307") F- 90 N 800 mm 600 mm1. When the plastic bushing shown to the right is inserted into a cylindrical enclosure, the insertion tools exert the forces shown in the figure to the right. The diameter of the bushing (cylinder) is 60 mm. Each of the forces is parallel to one of the coordinate axes. Find the resultant force and the resultant y 20 mm 17 N| 12 N moment at point C. AV Ř=-2lî – 29ĵ–16k N Ans.: M. =-0.87î +0.63ĵ+0.39k N · m 80 mm 21 N C 16 N 60 mm 30 mmFind the magnitude of the moment of force F about point A, given: F̄ = <-80,-30,55> lbs, LX = 6 ft, LY = 6 ft, LZ = 6 ft
- Find the moment about point A due to the forces shown in the Figure below. HINT: Choose clockwise as negative and counterclockwise as positive. a. C. 10 N b. M M e. d. M 30 N 30 N = 1 m = -10 N. 1.5 m - 30 N. 1 = 2 m = -10 N 1.5 m + 30 N. 1 M +10 N 1.5 m - 30 N.3 1.5 m = -10 N. 1.5 m - 30 N. 2 M 10 N 2 m + 30 N 1.5 n O O O OThe resultant of the force system shown in fig. is 750 N.cm clockwise ?moment, Find P, F, and the couple C |50 N 12 P 1cm F 100 N --I -|cm P= 407 N and F= 260 N and C=1440 N.cm P= 200 N and F= 260 N and C=1440 N.cm O P= 345 N and F= 407 N and C=3095 N.cm P= 407 N and F= 345 N and C= 3095 N.cm8:05 png.صباحي q2 Compute the moment of these forces as shown in the figure with respect to point A. 6 kN 30° 130° 1.5 m 4 kN -1.5 m- -1.5 m-
- A bent tube is attached to a wall with brackets as shown. A force of F = 480 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. a.) Determine the moment about point D due to the force F. Enter your answer in Cartesian components with units of ft-lbs. b.) Determine the moment about a line (i.e. axis) running from D to C due to the force F. Enter your answer in Cartesian components with units of ft-lbs. 2013 Michael Swanbom BY NC SA A FK Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Be sure to align your cartesian unit vectors with the coordinate axes shown in the figure. Variable Value a 11.4 in 19.4 in 16.5 in d 52.8 in h 37.4 in 44.0 in a. Mp = k) ft-lb b. MpC i + k) ft-lbFind the moment about A & B where AB = 8m, BC = CD = 6m & all forces makes 40° to the C3 %3D horizontal axis. 7kN 8 kN 10kN 15kN 6kN 5kN 4kN 3kNUntitled Section F1 F2 a F3 d F4 Consider the following values: - F5 a = 16 m; b = 11 m; c = 13 m; d = 8 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 88.8 kN.m b) 76.3 kN.m c) 19.6 kN.m d) 55.5 kN.m e) 59.1 kN.m f) 81.3 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 88.8 kN.m b) 120.8 kN.m c) 31.6 kN.m d) 98.9 kN.m e) 41.1 kN.m f) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 125.7 kN.m b) 178.1 kN.m c) 254.6 kN.m d) 439.1 kN.m e) 144.1 kN.m f) 215.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 77.8 kN.m b) 98.3 kN.m c) 100.6 kN.m d) 18.9 kN.m e) 97.1 kN.m f) 60.1 kN.m 5] What is the moment of the force F2 about point E? Activate V ) 151.3 kN.m Go to Setting! a) 122.7 kN.m b) 108.1 kN.m c) 66.6 kN.m d) 83.1 kN.m e)…
- A member is loaded with force system as shown in figure. Find the Moment about A, B ,C, D and E Where F1= 50 N, F2 =30 N, F3 =20 N, F4 =25 N, F5 =35 N, AB =140 m, Point C is in the mid of AE , CD = 45m, AE =90 m. the angle ϴ =55degree (i) The moment about the point 'B' ( in Nm) MB = (ii) The moment about the point 'D' ( in Nm) MD = (iii) The moment about the point 'E' ( in Nm) ME =2. Four forces are applied to the machine element ABDE as shown to the left. Find the resultant 200 mm force and the resultant moment at point A. (Assume that points A, B, D, and E are located at the centroid of the cross-section of the bar, and that the forces act at these points.) 50 N 40 mm 20 mm B. 300 N R =-420î – 50ĵ– 250k N Ans.: 160 mm M, =0î +30.8ĵ –22k N - m 250 N D A 100 mm E 120 NA member is loaded with force system as shown in figure. Find the Moment about A, B ,C, D and E Where F1= 50 N, F2 =30 N, F3 =20 N, F4 =25 N, F5 =35 N, AB =140 m, Point C is in the mid of AE , CD = 45m, AE =90 m. the angle ϴ =55degree (i)The moment about the point 'A' (in Nm) MA = (ii) The moment about the point 'B' ( in Nm) MB = (iii) The moment about the point 'C' ( in Nm) MC = (iv) The moment about the point 'D' ( in Nm) MD = (v) The moment about the point 'E' ( in Nm) ME =