12. View the proportion of flies from your data that indicate crossover occurred (VG and BL flies) and multiple it by 100. Based on your data, how far apart are these alleles?
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- ฿ & 2 W S Because of the mechanism of sex determination, males of many species can be neither homozygous nor heterozygous. Such males are said to be. X mmand O complementary O hemizygous O dominant Orecessive O None of the answers listed is correct. Provide Feedback Submit Request Answer #3 C E D C $ 4 R F G Search or type URL % 5 V T G ^ 6 MacBook Pro B Y H & 7 5 U C *00 8 M 1- + ( 9 K H O ) O L command P . V I option { 21 ? + 11 = -In a germline cell of genotype Ff Qq where genes F and Q are on different chromosomes, capital and lowercase letters represent alternate alleles (versions or variants) of each gene. If this cell undergoes normal meiosis to produce sperm, what are the possible sperm genotypes? FQ, fq, Fq, fQ Ff, Qq, FQ, fq, Fq, fQ O Ff, Ff, Qq, Qq O F, f, Q, qAffected female Affected male O Unaffected female Unaffected male 11 IV 40/20 20 80/40 80 OO 180 90/20 160/20 20 A) Between 20 and 40 and between 80 and 180, respectively B) Between 20 and 40 and between 160 and 180, respectively C) Between 40 to 80 and between 160 and 180, respectively D) Between 40 to 80 and between 180 and 200, respectively O 40/20 80/20 160 20 180/20 20 dd 180/40 20 180/20 250/20 200 20/20160/20 20 200 20 WATAK 20/20 20 118. A 25-year-old nulligravid woman (individual IV-1 in the pedigree shown) and her 28-year-old husband come to the office for counseling prior to conception. Previous reproductive endocrinologic evaluation of the husband showed no abnormalities. The woman has a family history of fragile X syndrome. The genotype of the CGG trinucleotide repeat length in the 5'-untranslated exon of the FMR1 gene for each individual in the family is indicated. Based on these findings, the repeat length boundaries between normal and premutation and between premutation…
- Content MasteringBiology: Mitosis/Meios x A session.masteringbiology.com/myct/itemView?assignmentProblemID=174963736&offset=next KMitosis/Meiosis Assignment (Part 2) (Unit 3) Learning through Art: Sex-linked Cross 6 of 11 female must have two copies of the recessive allele to have the disease. A human male (XY), on the other hand, has only one X chromosome, and so needs only one copy of the recessive allele to have the disease. Complete the Punnett square below of a cross between a carrier mother (a female who carries one copy of the recessive allele and so appears normal herself) and a non-hemophiliac father. 1. Drag the pink labels to the pink targets to indicate the sex dictated by the genotype in each box. (Pink labels may be used more than once.) 2. Drag the blue labels to the blue targets to indicate whether the genotype in each box confers hemophilia, normal, or carrier status. (Blue labels may be used more than once.) Reset Help x"x (carrier) mother xHY (normal) father Sperm…4gBHUKO43E5N6KbptHzUsbQQ4hiaftS471EHx-dvd_A/viewform Job Listing - USF... My Drive - Google... WT Enrollment Requir... Chemical Princip 1. Which statement is most correct regarding the difference between mitosis and meiosis? O Meiosis can produce any cell type, while mitosis can only make gametes (sperm/egg cells) * 1 p Mitosis essentially clones a cell (makes an identical copy), while meioisis is a more O complex process that divides up a cell's set of chromosomes into gametes (sperm/egg cells) ODNA replication is required for mitosis but not for meiosis Dyads are seen in mitosis but not meiosisIn fruit flies, the color of the eyes is sex linked (on the X chromosome). Complete the cross of the flies in the image to determine the possible offspring produced. Red eyes are dominant (R), White eyes are recessive (r). What percentage of the male offspring are expected to have red eyes? XR Y O a 100% O b 75% 50% Od 25% e 0% Saved at 11:42 am Review Answers JP
- n humans, Turner's syndrome results in a ["Female", "Male", "Hermaphrodite"] with the sexual genotype X0. Klinefelter's syndrome results in a ["Y0", "Male", "XY", "X0", "Female", "XXX", "XXY", "XX", "Hermaphrodite"] with the sexual genotype XXY. (No partial credit given)Rolly's APPLE ACK Free stu X O Leaming Lab Varsity Tutors + tutors.com/learning-lab/assessment/2eb9c784-88d7-4224-91d8-87c72f8edeb1 r rr rr Which best describes the parent genotypes in the punnet square provided? A Homozygous dominant and heterozygous B Two heterozygous C| Homozygous recessive and homozygous dominant D Homozygous recessive and heterozygous I don't know Next Question2: Chart v Add-ins Media Links Comment Footer Page Numb Header Screenshot v Cystic fibrosis is a hereditary illness causing respiratory issues and recurrent lung infections. It is a recessive disorder (c). Using the details below, fill in the Punnett square to determine probability of an offspring having cystic fibrosis. Mother Father -does not -does not have have cystic cystic fibrosis fibrosis genotype Cc -genotype Cc Mother Father Probability of offspring having cystic fibrosis: ada)
- Trivla Game Show _Make Your Own Tri ngston.schoology.com/common-assessment-delivery/start/4789189591?action=onresume&submissionld=463322566 Dillon WF g Aa v Done In guinea pigs, black hair (B) is dominant to white hair (b) and rough hair (R) is dominant to smooth hair (r). What are all the possible genotypes of a guinea pig that has black, rough hair? (Select all that apply.) O BBRR BBRr BBrr BBRR BbRr O bbRR O bbRr O bbrr O Black O White O Rough OSmooth O Rough O Smooth1. 10 Meiosis Reading and Voc X James Green- Recovery Opportu X d/e/1FAlpQLSe2TqFrpPuk-re3-isqbyWK6SUIH3pkHhJdbT0tlqogh58bww/viewform?hr_submission=Chkis-WD4ZSE What is the process by which haploid gametes combine, forming a diploid 3p cell with 2n chromosomes, with n chromosomes from the female parent and n chromosomes from the male parent? Topography O Fertilization Genomics Crossing over 2 points nit that controls inherited trait expression that is passed IIW O () ENG 9:37 am O GENBIO-1ST-SEM-MIDTERN X 9 Schoology G karyotype of a certain huma x 6 BigBlueButton - GNBIO Messenger My Questions | bartleby + A app.schoology.com/common-assessment-delivery/start/5385424680?action=Donresume&submissionld=643190401 The diagram below shows a karyotype of a certain human. 8. 10 11 12 13 14 15 16 17 18 19 21 22 X Y Based on the karyotype, which of the following statements is most likely true? O The individual has a genetic condition caused by a nondisjunction event. The individual has a genetic condition caused by the X and Y chromosomes being different sizes. O The individual has a genetic condition caused by a chromosomal duplication. O The individual has a genetic condition caused chromosomes number one being different sizes. GENBIO-1ST-SEM-.pdf O 245180335_56899...jpg Show all ... TID N DAD × IDD . I ID.