Genetic Analysis: An Integrated Approach (3rd Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 6, Problem 1P

For bacteria that are F + , Hfr, F' , and F - , perform or answer the following.

a. Describe the state of the F factor.

b. Which of these cells are donors? Which is the recipient?

c. Which of these donors can convert exconjugants to a donor state?

d. Which of these donors can transfer a donor gene to exconjugants?

e. Describe the results of conjugation (i.e., changes in the recipient and the exconjugant) that allow detection of the state of the F factor in a donor strain.

f. Describe a “partial diploid” and how it originates.

Expert Solution & Answer
Check Mark
Summary Introduction

To review:

For bacterial strains F+, Hfr, F', and F-, answer the following:

Description for the state of the F factor.

Identification and explanation of donor and recipient cells.

Identification and explanation of donor cells that can convert exoconjugants to donor state.

Identification of the donor that can transfer the donor gene to exoconjugants.

Description of results of conjugation that allow detection of the state of the F factor in the donor strain.

Description on partial diploids.

Introduction:

Conjugation is the process of transfer of the DNA from one donor bacterium to a recipient bacterium. It is also known as lateral gene transfer. Conjugation is always occurring between the donor cell and the recipient cell, it does not occur between two donor cells. The exoconjugant cell is the recipient cell that has a modification in their genome by receiving the DNA from a donor cell in the process of conjugation. During conjugation, bacteria come in contact with the help of sex pilus. The bacterium that has sex pilus is the donor - male bacterium, and the bacterium that lacks sex pilus is the recipient - female bacterium.

The cell that has the ability to donate their DNA is called F+cell. The F stands for the fertility factor. In contrast, the cell which does not contain fertility factor (F factor) is called the F-cell. Hfr stands for high-frequency recombination cells, which have their genome integrated with conjugative plasmid, i.e., Ffactor of the plasmid. This integration of the F factor occurs through homologous recombination.

Explanation of Solution

The F sex factor is the factor present in plasmid or episome (a small part of genome present independently of genome). This factor is present in many forms on the basis of factors include in it.

F+- The bacterium that has plasmid is F+. Plasmid is present in cytoplasm independently of the bacterial genome.

Hfr (high frequency recombination) - The bacterium that has F factor completely integrated with its genome is Hfr.

F-- The bacterium that lacks plasmid or episome but can act as a recipient and receive them from another cell is F-.

F' - Bacterium in which F factor is attached with small part of genome.

Donor cell is a cell that donates factor/s to another cell by conjugation. Only that bacterial cell which already has the F sex factor can transfer it, so F+, Hfr, and F' are donor cells. The bacterial cell, which receives the F sex factor from the donor through conjugation, is the recipient, i.e., F-.

The F+ and F' bacteria are donor cells and can transfer the F sex factor to exoconjugants through conjugation. Once exoconjugants receive the F sex factor, they become F+ (receive F factor from F+) or F' (receive F factor from F'); now they can also donate the F factor. The Hfr are not able to transform exoconjugants into donor bacteria.

Hfr and F' have some portion of bacterial genome attached to the F sex factor, so if we cross F'×F- and Hfr ×F-, the bacterial gene can be transferred to exoconjugants along with the F sex factor. on the other hand, F+ bacteria have plasmid present in cytoplasm independently of the bacterial genome, so F+ is unable to transfer bacterial gene to exoconjugants.

At the time of conjugation, bacterium comes in contact with the help of sex pilus. The bacterium that has sex pilus is the donor - male bacterium, and the bacterium that lacks sex pilus is the recipient - female bacterium. Conjugation tube is formed between the donor and recipient, and F sex factor is transferred from F+ to F-; this process is known as lateral gene transfer. Once F- receives F sex factor from the donor, it becomes F+ (receives F factor from F+) or F' (receives F factor from F'). F- cannot transform into F+ or F' through the cross between Hfr×F-. The recipient, which receives F sex factor and becomes F+, in this plasmid, gets fused with the host genome and transforms F+ to Hfr. This fused plasmid can again cut from genome and come back out; at that time, it carries some portion of the host genome along with it. Now this plasmid is known as F'.

A bacterium that has two copies of some of its genes (not all) is termed as partially diploid. In a bacterium, one copy of the desired gene is present on the bacterial genome, and another copy may be fused with the plasmid. Now, the bacterial cell possesses one complete set of genes and identical copy of portion of the genome.

Example of formation of partial diploid:

F' strain possesses a plasmid that has gene Lac+(can grow on lactose medium), and F- strain genome has Lac-(cannot grow on lactose medium). When cross is done between F'×F- strain of bacteria, F- receives plasmid from F' and becomes F' strain. Now newly formed F' has two copies of Lac gene - Lac+ on plasmid and Lac- on its genome. Now, this newly formed F' strain is termed as a partial diploid strain.

Conclusion

Conclusions:

The bacterium that has plasmid is F+.The bacterium that has F factor completely integrated with its genome is Hfr. The bacterium that lacks plasmid or episome but can act as a recipient and receive them from another cell is F-.The bacterium in which the F factor is attached with a small part of genome is F'.

F+, Hfr, and F' are donor cells. The bacteria which receive the F sex factor from the donor through conjugation is the recipient, i.e. F-.

The F+, F' bacterium are donor cells and can transform exoconjugants to donor strain while Hfr are not able to transform exoconjugants into donor bacterium.

Hfr and F' can transfer bacterial gene to exoconjugants and F+ cannot.

F- receives F sex factor from the donor and becomes F+ (receives F factor from F+) or F' (receives F factor from F'). F- cannot transform into F+ or F' through the cross between Hfr ×F-. The newly F+ formed plasmid gets fused with the host genome and transforms F+ to Hfr. Bacterium with the fused F factor comes out back and has small part of genome attached with it; it is termed as F'.

A bacterium that has two copies of some of its genes (not all) is termed as partially diploid.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
In the Avery, McLeod, McCarty Experiment where supernatant from heat killed, virulent S Strain pneumonia solutions were added to non-virulent R Strain pneumonia cell cultures and allowed to grow in liquid media (i.e., broth). In tubes where Protease was added to the supernatant prior to cell culture, what was the observed effect when plating and growing the S. pneumonia cells to solid media?
You have a leu auxotroph strain of e. coli. You suspect that if you mutagenize this strain, you can isolate prototrophic revertants. You irradiate these cells to generate mutants.  A) What media should you plate these mutants on to identify leu prototrophs?    answers: a. minimal media + carbon source b. minimal media - leu c. rich media d. rich media + ampicillin e. rich media -trp
An E. coli strain where the crp gene that encodes the cAMP receptor protein (CRP), also known as the catabolite activator protein, has a mutation such that it is no longer active. In this case, the strain would no longer be able to (select all that are correct) A. Grow on minimal medium plus glucose B.Synthesize tryptophan C. Grow on minimal medium plus maltose D. Grow in a rich medium E. Grow on minimal medium plus lactose

Chapter 6 Solutions

Genetic Analysis: An Integrated Approach (3rd Edition)

Knowledge Booster
Background pattern image
Biology
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Human Anatomy & Physiology (11th Edition)
Biology
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:PEARSON
Text book image
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Text book image
Anatomy & Physiology
Biology
ISBN:9781259398629
Author:McKinley, Michael P., O'loughlin, Valerie Dean, Bidle, Theresa Stouter
Publisher:Mcgraw Hill Education,
Text book image
Molecular Biology of the Cell (Sixth Edition)
Biology
ISBN:9780815344322
Author:Bruce Alberts, Alexander D. Johnson, Julian Lewis, David Morgan, Martin Raff, Keith Roberts, Peter Walter
Publisher:W. W. Norton & Company
Text book image
Laboratory Manual For Human Anatomy & Physiology
Biology
ISBN:9781260159363
Author:Martin, Terry R., Prentice-craver, Cynthia
Publisher:McGraw-Hill Publishing Co.
Text book image
Inquiry Into Life (16th Edition)
Biology
ISBN:9781260231700
Author:Sylvia S. Mader, Michael Windelspecht
Publisher:McGraw Hill Education
genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license