A compound has a molar mass of 86 g/mol and has the percent composition (by mass) of 55.8% C, 37.2% O, and 7.0% H. a) Determine the empirical formula. C  O  H  b) Determine the molecular formula. C  O  H

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Chapter10: The Mole
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Problem 154A
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A compound has a molar mass of 86 g/mol and has the percent composition (by mass) of 55.8% C, 37.2% O, and 7.0% H.

a) Determine the empirical formula. C  O  H 

b) Determine the molecular formula. C  O  H 

Expert Solution
Moles of C, H , O

To determine the empirical formula for compound , first we have to consider the given percentage of C , H and O as mass  .

55.8% C, 37.2% O, and 7.0% H.

 Carbon = = 55.8 g

Oxygen = 37.2 g

Hydrogen = 7.0 g

 

 * Moles of carbon 

= Mass of carbon / molar mass of carbon

= 55.8 g / 12 (g/mol)

= 4.65 mol

 

*Moles of oxygen

= Mass of oxygen / molar mass of oxygen

= 37.2 g / 16 (g/mol)

= 2.32 mol

 

*Moles of hydrogen

= Mass of hydrogen/molar mass of hydrogen

= 7 g / 1.0 (g/mol)

= 7 mol

 

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