Ży = 69 + 36j ohmsZw = 9 + 6j ohmsLine to line Voltage = 420VAssume positive sequence and Van with zero angle.VanZwZyaAVonZwZy"H10NVanZwZyDetermine the current IA.Select your answer.2.7372 angle -28.3 Amp.2.7372 angle -148.3 Amp.2.7372 angle -91.7 Amp.2.7372 angle 0 Amp.

Ży = 69 + 36j ohms Zw = 9 + 6j ohms Line to line Voltage = 420V Assume positive sequence and Van with zero angle. Van Zw Zy a A Von Zw Zy "H10 N Ven Zw Zy Determine the current IA. Select your answer. 2.7372 angle -28.3 Amp. 2.7372 angle -148.3 Amp. 2.7372 angle -91.7 Amp. 2.7372 angle 0 Amp.

Ży = 69 + 36j ohms Zw = 9 + 6j ohms Line to line Voltage = 420V Assume positive sequence and Van with zero angle. Van Zw Zy a A Von Zw Zy "H10 N Ven Zw Zy Determine the current IA. Select your answer. 2.7372 angle -28.3 Amp. 2.7372 angle -148.3 Amp. 2.7372 angle -91.7 Amp. 2.7372 angle 0 Amp.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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Question

Ży = 69 + 36j ohms
Zw = 9 + 6j ohms
Line to line Voltage = 420V
Assume positive sequence and Van with zero angle.
Van
Zw
Zy
a
A
Von
Zw
Zy
"H10
N
Van
Zw
Zy
Determine the current IA.
Select your answer.
2.7372 angle -28.3 Amp.
2.7372 angle -148.3 Amp.
2.7372 angle -91.7 Amp.
2.7372 angle 0 Amp.

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