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- Write in C Language Spilitology Yosef is a peculiar fellow. He introduced the idea to study a string by splitting it into two, and he called it Splitology. Why split a string? We do not know. Didn’t we say that Yosef is a weird one? Yosef is interested in one particular type of string, a palindrome. A palindrome is a string that is the same for both forwards and backwards. Example of palindrome strings are “ada”, “taat”, and “radar”. On the other hand, string such as “taman” is not a palindrome; notice that “taman” becomes “namat” if read backwardsand it’s not the same as “taman”. As the idea of Splitology is still new, Yosef is investigating whether a string can be split into two non-empty strings such that each string is a palindrome. For example, the string “malamini” can be split into “malam” and “ini” while both of them are palindrome. Another example is “ababab”. It can be split into “aba” and “bab”, and both of them are palindrome. Note that “ababab” can also be split into…Static Length, Limited Dynamic Length, and Dynamic Length String implementations have what advantages and disadvantages?C CodeApproved Libraries:<string.h> *not allowed in some questions<math.h><stdlib.h><time.h> (for srand(time(0)) only)
- Failable Initializers - How do I do this practice exercise using Swift code?Dijkstra's algorithm Weight Class Implementationlanguage : C++ Note : Skelton Files Provided Please check the linksproject Details:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/ Files:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/src/ Please provide clear and complete solution for thumps up.What are some ways you can make code more efficient when using if-else blocks?
- When the * operator’s left operand is a list and its right operand is an integer, the operator becomes this. a. The multiplication operator b. The repetition operator c. The initialization operator d. Nothing—the operator does not support those types of operands.JAVA CODE PLEASE Functions With No Parameters and Return Values Quiz by CodeChum Admin Create a function named banner that prints “CodyChum” with a newline. In the main function, write a program that accepts an integer input which would serve as an inclusive stopping point of a loop iteration that starts at the value of 1. If the number that loops through the range is divisible by either 2 or 3, then call the banner function, otherwise just print the number. Input 1. One line containing an integer Output First line is the integer user input. Succeeding multiple lines containing an integer or “CodyChum” 10 1 CodyChum CodyChum CodyChum 5 CodyChum 7 CodyChum CodyChum CodyChumPython Test: import recursive_functionsimport mathdef main():# Test factorialprint('Testing factorial.')assert recursive_functions.factorial(0) == 1assert recursive_functions.factorial(1) == math.factorial(1) == 1assert recursive_functions.factorial(2) == math.factorial(2) == 2assert recursive_functions.factorial(5) == math.factorial(5) == 120assert recursive_functions.factorial(7) == math.factorial(7) == 5040print('All tests pass for `factorial` ()\n')# Test sum_recursivelyprint('Testing sum_recursively.')assert recursive_functions.sum_recursively(0) == 0assert recursive_functions.sum_recursively(1) == sum(range(1+1)) == 1assert recursive_functions.sum_recursively(2) == sum(range(2+1)) == 3assert recursive_functions.sum_recursively(10) == sum(range(10+1)) == 55print('All tests pass for `sum_recursively` () ')# Test sumlist_recursively(l)print('Testing sumlist_recursively.')assert recursive_functions.sumlist_recursively([1,2,3]) == sum([1,2,3])assert…
- Typed plzzzz Asap#include using namespace std; bool isPalindrome(int x) { int n=0,val; val = x; while(x > 0) { n = n * 10 + x % 10; x = x / 10; } } int main() { int n; cin >>n; if(isPalindrome(n)) { cout <public static String pancakeScramble(String text) This nifty little problem is taken from the excellent Wolfram Challenges problem site where you can also see examples of what the result should be for various arguments. Given a text string, construct a new string by reversing its first two characters, then reversing the first three characters of that, and so on, until the last round where you reverse your entire current string.This problem is an exercise in Java string manipulation. For some mysterious reason, the Java String type does not come with a reverse method. The canonical way to reverse a Java string str is to first convert it to mutable StringBuilder, reverse its contents, and convert the result back to an immutable string, that is,str = new StringBuilder(str).reverse().toString(); Here's the tester it must pass: @Test public void testPancakeScramble() throws IOException {// Explicit test casesassertEquals("", P2J3.pancakeScramble(""));assertEquals("alu",…