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1). pk and wh
Phenotype | Genotype | Number |
white |
+ wh + |
47 |
wild | +++ | 200 |
Pink, opaque | pk+op | 46 |
pink, white | pk wh+ | 205 |
opaque | ++op | 199 |
white, opaque | +wh op | 49 |
Pink, white, opaque |
pk wh op |
206 |
pink | pk++ | 48 |
Total | 1000 |
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- IN DROSOPHILA, AN X-LINKED RECESSIVE MUTATION, Xm CAUSES MINIATURE WINGS. LIST THE F₂ PHENOTYPIC RATIOS IF: A MINIATURE-WINGED FEMALE IS CROSSED WITH A NORMAL MALE AND A MINIATURE-WINGED MALE IS ● ● CROSSED WITH A NORMAL FEMALE. WHAT WOULD THE PHENOTYPIC RATIO FROM (A) BE IF THE MINIATURE- WINGED GENE WERE AUTOSOMAL? ASSUME IN ALL CASES THAT THE P1 INDIVIDUALS ARE TRUE-BREEDING.Consider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?In Drosophila, the X-linked recessive mutation vermilion (v) causes bright red eyes, in contrast to the brick-red eyes of wild type. A separate autosomal recessive mutation, suppressor of vermilion (su-v), causes flies homozygous or hemizygous for v to have wildtype eyes. In the absence of vermilion alleles, su-v has no effect on eye color. Determine the F1 and F2 phenotypic ratios from a cross between a female with wild-type alleles at the vermilion locus, but who is homozygous for su-v, with a vermilion male who has wildtype alleles at the su-v locus
- A female Drosophila fly is heterozygous for three recessive pigmentation mutations called pl, wh, and tp. pl is associated with purple eyes, wh is associated with a white body, and tp is associated with transparent wings. A geneticist crosses this fly to a male purple, white, and transparent fly and obtains the 1000 progeny given in the table. Phenotype white wild type purple, transparent purple, white Number 50 200 52 205 Based on the table, which genes are linked? wh and tp O pl and tp Opl and wh Calculate the distance between the linked genes. distance between the linked genes: Phenotype transparent white, transparent purple, white, transparent purple Number 199 43 206 45 m.u.A geneticist is using a three‑point testcross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the F1 progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. progeny curved 277 anomalous, buckled 283 wild type 5 anamalous, buckled, curved 5 buckled, curved 133 anomalous 127 anomalous, curved 86 buckled 84Miniature wings (Xm) in Drosophila result from an X-linked allele that is recessive to the allele for long wings (X*). Give the genotypes of the parents in the following cross: Male parent Female parent Male offspring Female offspring Long Miniature 750 miniature 761 long O male: X* / X* and female X™ /x+ O male: X*/Xt and female Xm /xm O male: X*/ Y and female Xm /xm O male: Xm/ Y and female Xm /xm
- A geneticist is using a three-point testcross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the F₁ progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. Testcross progeny phenotype curved anomalous, buckled wild type anamalous, buckled, curved buckled, curved anomalous anomalous, curved buckled Number 277 283 4 6 133 127 83 87 map distance: m. u.A geneticist is using a three-point testcross to map three linked Drosophila recessive mutations called a, b, and c, where a is associated with anomalous gait, b is associated with buckled wings, and c is associated with curved bristles. She first crosses homozygous anomalous, buckled flies to homozygous curved flies. Next, she testcrosses the F1 progeny to anomalous, buckled, curved flies. She obtains 1000 progeny distributed as shown. From this data, calculate the map distance between b and c. Testcross progeny phenotype Number curved 281 map distance: m. u. anomalous, buckled 279 wild type 4 anamalous, buckled, curved buckled, curved 128 anomalous 132 anomalous, curved 83 buckled 87It is assumed that in Drosophila the following genotypes produce phenotypes. َA- B- = Red color A- bb = Plum color aa B- = Magenta color aa bb = White color The third latent genotype, cc, kills homozygous Plums, but has no effect on other genotypes. Also, genotype C- does not produce a large phenotype. If first-generation Drosophilas are heterozygous for all of these genes and interbreed, what phenotypic ratios are expected in society?
- In Drosophila, a cross was made between females expressing thethree X-linked recessive traits, scute bristles (sc), sable body (s),and vermilion eyes (v), and wild-type males. All females were wildtype in the F1, while all males expressed all three mutant traits.The cross was carried to the F2 generation and 1000 offspringwere counted, with the results shown in the following table. Nodetermination of sex was made in the F2 data. Question:Calculate the coefficient of coincidence; does this represent positive or negative interference? Phenotype Offspringsc s v 314+ + + 280+ s v 150sc + + 156sc + v 46+ s + 30sc s + 10+ + v 14Vermillion eye color in Drosophila sp. is a sex-linked recessive trait. What phenotype would be found in this progeny of a cross between a vermillion female and a wild type male?In a cross in Drosophila involving the X-linked recessive eye mutationwhite and the autosomally linked recessive eye mutation sepia(resulting in a dark eye), predict the F1 and F2 results of crossingtrue-breeding parents of the following phenotypes:(a) white females * sepia males(b) sepia females * white malesNote that white is epistatic to the expression of sepia