x-intercept(s) y-intercept(s) domain range relative maximum(s)relative minimum(s) y=x²=x4+2.5r3 +-.5r2 +-x+1-6(-2.472, 0)-4(-0.329, 1.198) 2(-1.937, -3.031)(-4,-3)20-15-10-2-5-4MUse the following Graph for Question 2 - 4g(x)f(x)(-1,0)--2-(0,1)(1,5)-4(0.392, 0.705)2

Answered: Image /qna-images/answer/70fc54a0-af05-4efe-a39b-6cef75eb80a5.jpg

y=x² =x4+2.5r3 +-.5r2 +-x+1 -6 (-2.472, 0) -4 (-0.329, 1.198) 2 (0,1) M (-1.937, -3.031) (-4,-3) 20- 15- 10 -2 -5- 4 Use the following Graph for Question 2 - 4 g(x) f(x) (-1,0) --2- -4 (1,5) (0.392, 0.705) 2

y=x² =x4+2.5r3 +-.5r2 +-x+1 -6 (-2.472, 0) -4 (-0.329, 1.198) 2 (0,1) M (-1.937, -3.031) (-4,-3) 20- 15- 10 -2 -5- 4 Use the following Graph for Question 2 - 4 g(x) f(x) (-1,0) --2- -4 (1,5) (0.392, 0.705) 2

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter4: Equations Of Linear Functions

Section4.7: Inverses Of Linear-functions

Problem 49PFA

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Question

x-intercept(s)

y-intercept(s)

domain

range

relative maximum(s)

relative minimum(s)

y=x²
=x4+2.5r3 +-.5r2 +-x+1
-6
(-2.472, 0)
-4
(-0.329, 1.198) 2
(-1.937, -3.031)
(-4,-3)
20-
15-
10
-2
-5-
4
M
Use the following Graph for Question 2 - 4
g(x)
f(x)
(-1,0)
--2-
(0,1)
(1,5)
-4
(0.392, 0.705)
2

Formula Formula A function f(x) attains a local maximum at x=a , if there exists a neighborhood (a−δ,a+δ) of a such that, f(x)<f(a), ∀ x∈(a−δ,a+δ),x≠a f(x)−f(a)<0, ∀ x∈(a−δ,a+δ),x≠a In such case, f(a) attains a local maximum value f(x) at x=a .

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