You invested $1,000 at the end of every 6-month period for 10 years at 9% interest compounded semiannually. Use formulas (not tables) to calculate (a) How much your investment is worth after 10 years. Show your work. (b) If you had invested the money at the beginning of each 6-month period rather than at the end , how much would be in your account? Show your work.
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- You put $250 in the bank for S years at 12%. A. If interest is added at the end of the year, how much will you have in the bank after one year? Calculate the amount you will have in the bank at the end of year two and continue to calculate all the way to the end of the fifth year. B. Use the future value of $1 table in Appendix B and verity that your answer is correct.Problem #1. You invested $1,000 at the end of every 6-month period for 10 years at 9% interest compounded semiannually. Use formulas (not tables) to calculate (a) How much your investment is worth after 10 years. Show your work. (b) If you had invested the money at the beginning of each 6-month period rather than at the end , how much would be in your account? Show your work.You invested $250 at the end of every month for 10 years at 7.5% interest compounded monthly. Use formulas (not tables) to calculate (a) How much your investment is worth after 8 years. Show your work. (b) If you had invested the money at the beginning of each month rather than at the end, how much would be in your account? Show your work
- Assume that at the beginning of the year, you purchase an investment for $6,500 that pays $95 annual income. Also assume the investment's value has increased to $7,050 by the end of the year. a. What is the rate of return for this investment? Note: Input the amount as a positive value. Enter your answer as a percent rounded to 2 decimal places.Suppose you invest $1,250 in an account paying 8% interest per year. a. What is the balance in the account after 3years? How much of this balance corresponds to "interest on interest"? b. What is the balance in the account after 31 years? How much of this balance corresponds to "interest on interest"?set up an equation and solve each problem. Suppose that $500 is invested at a certain rate of interest compounded annually for 2 years. If the accumulated value at the end of 2 years is $594.05, find the rate of interest.
- Suppose you invest $1,200 in an account paying 4% interest per year. a. What is the balance in the account after 2 years? How much of this balance corresponds to "interest on interest"? b. What is the balance in the account after 25 years? How much of this balance corresponds to "interest on interest"?You decide to invest $7,500 into an account that pays 1.1% annual compound interest. Write an equation for the balance of the account (B) after t years.Problem #1. You invested $150 at the end of every month for 10 years at 7% interest compounded monthly. Use formulas (not tables) to calculate (a) How much your investment is worth after 10 years. Show your work. (b) If you had invested the money at the beginning of each month rather than at the end, how much would be in your account? Show your work.
- An investor placed $2,000 per year at the end of each year into an investment account. Immediately after the 15th payment, the value of money in the account was $58,720. What is the average annual rate of return the investor has earned on the account? Group of answer choices 7.0% 9.0% 5.1% 6.3%Calculate the time necessary to achieve an investment goal. Give your answer to the nearest day. Use a 365-day year. (First enter the total number of full years, then give the remaining days.) $1,000 at 6% simple interest; deposit $650Suppose you invest $850 in an account paying 5% interest per year. a. What is the balance in the account after 2 years? How much of this balance corresponds to "interest on interest"? b. What is the balance in the account after 29 years? How much of this balance corresponds to "interest on interest"? a. What is the balance in the account after 2 years? The balance in the account after 2 years is $ (Round to the nearest cent.)