You have made a physical pendulum by swinging a rod of mass M = 1.08 kg and length L = 1.45 meters around its end. The mass of the rod is distributed uniformly along its length. We will assume that the amplitude of the swing is max = 19.34 degrees.Solid Rod Swings inSimple Harmonic Motion^0=-0,max0=+0₁maxDetermine all the following:The FORMULA for the moment of inertia of your rod, I =The distance from the pivot point to the Center-Of-Mass, d =The angular frequency of the pendulum, w =The amplitude of the motion in radians, max =radiansThe angular velocity when 0 = 64% of full swing, w(0 = 0.64 0max):NOTE: The first question requires a FORMULA, not a value.rad/sec=metersrad/sec

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ou have made a physical pendulum by swinging a rod of mass M= 1.08 kg and length L 1.45 meters around its end. The mass of the rod is distributed uniformly along its length. We will assume that the amplitude of the swing is max 19.34 degrees. Solid Rod Swings in Simple Harmonic Motion

ou have made a physical pendulum by swinging a rod of mass M= 1.08 kg and length L 1.45 meters around its end. The mass of the rod is distributed uniformly along its length. We will assume that the amplitude of the swing is max 19.34 degrees. Solid Rod Swings in Simple Harmonic Motion

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter16: Oscillations

Section: Chapter Questions

Problem 31PQ

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