You are asked to find the actual value that will be in the accumulator, AC, after executing each instruction in each mode, and fill in the table below: Note that for each addressing mode the value of AC is initially 500, and the execution of the second instruction depends on the previous one.
Q: Write a BC assembly subroutine which counts the 1’s in a 16-bit number. You can pass the number to…
A: Ans:) Suroutines are small programs that perform subtasks for a function. Here we need to create a…
Q: Given a memory load instruction, "mov R0; [R1+1000]," please give the input that should be selected…
A: Given instruction: mov R0 , [R1 + 1000] , store content of (R1 +1000) to register R0 [R1 +…
Q: Look at the figure, can you explain to me from the figure the following special registers in the…
A: PC: Program counter holds the address of the instruction which is currently being executed. NPC:…
Q: Suppose we add the following instruction to MARIE’s ISA:This instruction increments the value with…
A: INCZ Instruction: From the description, we can see that the INCZ instruction increments the value at…
Q: Explain why the max size of a memory segment in the real addressing mode is 64K.
A:
Q: Given the following branch instruction and location, answer the following questions about it.…
A: Given that: 0X10000 , 0Xb5000184At present, the PC is at 0X10000 * Type of branch Instruction:…
Q: Given the memory and register information below, what will be the value of the accumulator after…
A: Answer:
Q: "uppose we have the instruction Load 500. Given that memory and register R1 contain the values…
A: Instruction Load is 500 So, Assuming R1 is implied in the indexed addressing mode. Immediate…
Q: Which index register is used by the STOSD instruction?
A: Electronic data interchange (EDI) is mainly for communication and it is used to communicate in…
Q: Explain the fetch cycle in terms of the basic instruction cycle.
A: Task:- Describe the fetch cycle in the basic instruction cycle.
Q: Suppose we add the following instruction to MARIE’s ISA: JumpIOffset X This instruction will jump to…
A: Register Transfer Notation (RTN is a notation which uses symbols to describe the behavior of micro…
Q: 8. is responsible on fetching instructions and reads data from memory and I/C ports then write the…
A: Answer: c) BIU
Q: Q2/ A- Sum of series of 10 numbers stored at memory location 0100H:0500H and then store result in…
A: Move 00 to register B immediately for carry Load the data of memory [0500] into H immediately Move…
Q: When does it become possible for a bit to get accessed from bank "0" in the dire addressing mode of…
A: An Addressing Mode is a method to locate a target data where it is also called an Operand. In…
Q: Suppose, you as a designer of the CPU decide to add two general-purpose registers named D and E…
A: CPU add two genaral purpose registers Two registers are D and E. With the internal bus.
Q: The branch instruction allows the execution to go backward or forward starting from a new a Opcode…
A: answer is option f f.1000. the branch instruction should be 1000
Q: Q2:- (A) Find the phicycal address if (BP) = 0100H , (SI) = 0200H, (SS)= 2000H and a displacement of…
A: Given: Goal: We have to find the physical address using the instruction given in the problem. Also,…
Q: Which instruction copies data from the memory location addressed by ESI into AX?
A: LODS Instruction: An instruction “LODS” loads the register “AL”, “AX”, or “EAX” with the memory…
Q: The 8085 programming manual says that it takes seven T States to fetch and execute the MOV…
A: GIVEN: The 8085 programming manual says that it takes seven T States to fetch and execute the MOV…
Q: Read address Read register 1 ALUSrc ALU operation Read data 1 |MemWrite Read register 2 Registers…
A: Given FIGURE 4.11 The simple datapath for the core MIPS architecture combines the elements…
Q: • For the instruction shown, what value is loaded into the accumulator for each addressing mode?…
A:
Q: QI) I BX=1000, DS-0200, SS=0100, CS-0300 and AL=EDH, for the following instruction: MOV [BX] +…
A: Here is Solution for Above Problem :: Q1). Given Data : BX = 1000 DS = 0200 SS = 0100 CS = 0300 AL…
Q: If the CLK input to the 8086/8088 is 4 MHz, how long is one bus cycle? How much time is allowed for…
A: 1 Machine cycle = 4 T states = 4 Clock Pulse Frequency = 4 MHZ -> 1…
Q: Write an instruction sequence that could be used to read bit 1 of Port 0. What addressing mode is…
A: The 8051 microcontroller has four 8-bit I/O ports (Port 0, 1, 2, and 3). All the ports except Port 0…
Q: write ARM assembly code to find an average of 16 inputs and store in an address then find minimum…
A: Solution: Given, write ARM assembly code to find an average of 16 inputs and store in an…
Q: reate the opcode table for the ALU by giving a binary code and a name for each instruction you built…
A: Hey there, I am writing the required solution of the questin mentioned above. Please do find the…
Q: Two separate systems with different clock speed and cycles per instruction (CPI) are to be evaluated…
A: Given: Two separate systems with different clock speed and cycles per instruction (CPI) are to be…
Q: write the exchange instruction code
A: The mutual exclusion code given is simply a compare and swap instruction. Here I've written the…
Q: 2. Suppose the ROUNDING[2:0] field of the CTRL5_C register is set to 110, what registers are…
A: Included in a register: A computer register (also known as a CPU register) is about a small number…
Q: Write addressing mode that used the following instructions? A- MOV[AB00], BX B- MOV AL, [BP] C- MOV…
A: Given : A . MOV [AB00],BX B. MOV AL,[BP] C.MOV AX,[1200] D. MOV AX,0015H E.MOVS
Q: what is the instruction format of the operation below and how the CPU fetch this operands from…
A: Two address instructions are the most common in commercial computers. Here again each address field…
Q: With your knowledge in memory addressing modes and using the given opcodes LDA = 00 0000 0000 (00) 0…
A: To do: content of the address loaded into the accumulator
Q: e01, 7800, F400 for addresses 40A through 40D. AC starts with value 0F24, PC has the de 40A, and AR…
A: Answer is given below-
Q: Where can we see the carry, zero, and overflow flags that are generated at the end of an…
A: The carry flag is generated at the beginning of an instruction. It is set to 1 if the result of the…
Q: (B)- Identify the addressing modes used for the source and destination operands, and then compute…
A: The answer to the question is given below:
Q: Compute the physical address for the source operand in the following instruction if the contents of…
A: There are different methods for addressing an operand which is referred as Addressing modes. In the…
Q: What is the worst-case MIPS instruction in terms of energy consumption, and what is the energy spent…
A: Worst-case MIPS instruction and Energy spent to execute it: Instruction memory reads all…
Q: 14. What address in the Interrupt Vector Table is used to contain the address of the ISR for…
A: Vector:- A vector is an abstract type of data, which represents both directional and voluminal…
Q: Consider the below instructions and write the datapath components that each of these instructions…
A: To do: completing the instruction
Q: If the current value of the PC is OX57F0_3280, can you use a single jump instruction to get to the…
A: Each machine cycle executes one machine instruction. At the top of the machine cycle, the PC…
Q: Part (a): How do you identify the IO module issuing the interrupt?
A: Since Multiple questions are asked solving first question part(a) repost remaining. The below are…
Q: I need to understand what happens in the following Assembly ARM Instruction. ASRB R0, #2 For…
A: Answer:
Q: Use Indirect addressing to write a PIC24 assembly code that complements and adds 5 and multiply by 2…
A: Assembly code is used to directly tell the computer that what should the computer do. Assembly code…
Q: Suppose we add the following instruction to MARIE’s ISA: JumpOffset X This instruction will jump to…
A: Register Transfer Notation (RTN) is a notation that uses symbols to define actions. Micro-operation…
Q: The program then computes the sum of the three values,
A: Here is the assembly program to compute the sum of theree values:
Q: nterrupt table of pointers having addresses for each interrupt is located at a. high memory b. low…
A: Please see the next step for solution.
I want to solve this in detail
Step by step
Solved in 2 steps with 1 images
- A(n) ________________ instruction always alters the instruction execution sequence. A(n) ______________ instruction alters the instruction execution sequence only if a specified Condition is true.Two 1-bit values generate a 1 result value when a(n) _____ instruction is executed. All other input pairs generate a 0 result value.If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?
- A(n) ____________________ instruction copies data from one memory location to another.A subtraction instruction takes two operands, subtracts the first from the second, and the result goes into the second. Write a 16-bit subtraction instruction, where... The first operand is stored at the memory address contained within the %edx register. (NOTE: To be clear, the %edx register contains the memory address OF the operand, not the operand itself! Recall the syntax of "indirect addressing," to use here.) The second operand -- also where the result shall be stored -- is stored directly in the 16-bit %bp register. Type the appropriate assembly language instruction here:Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. If the given register are fewer than required, just put zeroes in the most significant place. A -effective address B - physical address/es e.g. 19000-19001 C- is for addressing mode type, e.g. direct D- content of the destination after execution e.g. if register: AX=1234 if memory (lower address first): 12000=34;12001=12 3(2).JPG ... AX =6FFAH DX =BFA8H SS = 6FFEH SI %3D 2BCАН IP = FADEH ВХ -9CF5H CS =5FFEH ES = 8DBEH BP = 6EEFH CX =3FFEH DS =AF9EH DI = 5EC9H SP = 9AABEH MOV [BX+SI+ADBCH], ESP EFFECTIVE ADDRES: Blank 1 PHYSICAL ADDRESS/ES: Blank 2 ADDRESSING MODE : Blank 3 CONTENT OF THE DESTINATION: Blank 4
- Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. If the given register are fewer than required, just put zeroes in the most significant place. A -effective address B - physical address/es e.g. 19000-19001 C- is for addressing mode type, e.g. direct D- content of the destination after execution e.g. if register: AX=1234 if memory (lower address first): 12000=34;12001=12 5(2).JPG AX =6FFAH DX =BFA8H SS = 6FFEH SI = 2BCAH IP = FADEH ВХ %-9CF5H CS =5FFEH ES = 8DBEH BP = 6EEFH CX =3FFEH DS =AF9EH DI = 5EC9H SP = 9AABEH MOV [ESI*2 + CBECH], EDX EFFECTIVE ADDRES: Blank 1 PHYSICAL ADDRESS/ES: Blank 2 ADDRESSING MODE : Blank 3 CONTENT OF THE DESTINATION: Blank 4What happens if an instruction is written to VA page 30 before it has been approved? In the following contexts, a TLB that is maintained by software would be more efficient than one that is handled by hardware:Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. If the given register are fewer than required, just put zeroes in the most significant place. A -effective address B - physical address/es e.g. 19000-19001 C - is for addressing mode type, e.g. direct D - content of the destination after execution e.g. if register: AX=1234 EFFECTIVE ADDRES: PHYSICAL ADDRESS/ES: ADDRESSING MODE : CONTENT OF THE DESTINATION: if memory (lower address first): 12000=34;12001=12
- Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. A - is for addressing mode type, e.g. directB - physical address/es e.g. 19000-19001 C - content of the destination after executione.g. if register: AX=1234 if memory (lower address first) : 12000=34;12001=12 DS = 8EFDHSS = AFDEHDI = B8F9HSI = D3CDHBP = A5D8HAX = 5FFEHBX = B3DFHCX = CADEHDX = B2BCHSP = A4FBHDetermine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. A - is for addressing mode type, e.g. direct B - physical address/es e.g. 19000-19001 C - content of the destination after execution e.g. if register: AX=1234 if memory (lower address first) : 12000=34;12001=12 GIVEN DS = 8EFDH SS = AFDEH DI = B8F9H SI = D3CDH BP = A5D8H AX = 5FFEH BX = B3DFH CX = CADEH DX = B2BCH SP = A4FBH MOV[BP+SI+9FEDH], EAX Find Addressing mode: Physical address/es: Content of the destination:Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. If the given register are fewer than required, just put zeroes in the most significant place. A -effective address B - physical address/es e.g. 19000-19001 C - is for addressing mode type, e.g. direct D - content of the destination after execution e.g. if register: AX=1234 if memory (lower address first): 12000=34;12001=12 EFFECTIVE ADDRES: PHYSICAL ADDRESS/ES: ADDRESSING MODE : CONTENT OF THE DESTINATION: