You are a zoologist working with Giraffes. Their main traits are: Grey tongues (G"), Rudimentary Horns (R*), Long necks (L*). You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: G* R* L*/G*R* L* x GRL/GRL F1 (all identical): G* R* L*/G RL Test Cross Progeny 2021 GRL 1987 G* R*L* 600 G R L* 444 G R* L 125 GR L 122 G*R* L 7 G RL G R L* Total progeny= 5307

You are a zoologist working with Giraffes. Their main traits are: Grey tongues (G"), Rudimentary Horns (R), Long necks (L). You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: G* R* L/GR* L* x GRL/GRL F1 (all identical): G* R* L/G RL Test Cross Progeny 2021 GRL 1987 G RL 600 G R L* 444 G R* L 125 GR L 122 GR L 7 G RL G R L* Total progeny= 5307

Biology (MindTap Course List)

11th Edition

ISBN:9781337392938

Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Publisher:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg

Chapter11: The Basic Principles Of Heredity

Section: Chapter Questions

Problem 6TYU: Redgreen color blindness is an X-linked recessive disorder in humans. Your friend is the daughter of...

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You are a zoologist working with Giraffes. Their main traits are: Grey tongues (G+), Rudimentary Horns (R+), Long necks (L+) . You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: G+ R+ L+/G+ R+ L+   x G R L /G R L F1(all identical): G+ R+ L+/G R L What this the distance between G and R? What is the distance between G and L? What is the distance between R and L? What is the correct order of the genes on the chromosome? (5 points) (Hints: You should draw it first. The overall order will not change whether reading from the left or the right side of the chromosome). a. G--R--L b. L--G--R c. G--L--R
you are a zoologist working with Tigers. Their dominant traits are Bright orange fur(B+), Long tails (L+), and sharp teeth (T+) . You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: B+ L+ T+/B+ L+ T+   x B L T /B L T F1(all identical): B+ L+ T+/ B L T Test Cross Progeny 3435 B L T 3069 B+ L+ T+ 1115 B+ L T 1022 B   L+ T+ 426 B   L T+ 428 B+ L+ T 114 B   L+ T 102 B+ L T+ Total progeny= 9711 question: What is the distance between B and L? Give the answer as map units (mu) with 2 decimal places (ie 12.34)
you are a zoologist working with Tigers. Their dominant traits are Bright orange fur(B+), Long tails (L+), and sharp teeth (T+) . You perform the following testcross with an individual with recessive versions of all 3 of the traits. P: B+ L+ T+/B+ L+ T+   x B L T /B L T F1(all identical): B+ L+ T+/ B L T Test Cross Progeny 3435 B L T 3069 B+ L+ T+ 1115 B+ L T 1022 B   L+ T+ 426 B   L T+ 428 B+ L+ T 114 B   L+ T 102 B+ L T+ Total progeny= 9711 question: What is the distance between B and T? Give the answer as map units (mu) with 2 decimal places (ie 12.34)
The colors of chicken feathers follow a codominant pattern. Both Black (B) and White (W) feathers are dominant phenotypes while checkered (BW) is the heterozygous phenotype. Show a cross between 2 checkered chickens. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:
Consider two blood polymorphisms that humans have in addition to the ABO system. Two alleles LM and LN determine the M, N, and MN blood groups. The dominant allele R of a different gene causes a person to have the Rh+ (rhesus positive) phenotype, whereas the homozygote for r is Rh− (rhesus negative). Two men took a paternity dispute to court, each claiming three children to be his own. The blood groups of the men, the children, and their mother were as follows:From this evidence, can the paternity of the children be established?
Heterozygous Cc chickens express a condition called creeper, in which the leg and wing bones are shorter than normal (cc). The dominant C allele is lethal when homozygous. Skin color is determined by the alleles W and w. W_ chickens have white skin and ww chickens have yellow skin. In a mating between 2 chickens heterozygous for both of these genes: 1) What phenotypes will be observed in the progeny? 2) What fraction of the offspring will have each phenotype? Assign alleles. List possible phentoypes. Make gametes, draw Punnett square, and list fractions of genotypes and/or phenotypes of offspring,
You breed two black dogs. It results in 3 offspring, the first which is black, the second which is brown, and the third which is white. Give two genetic explanations as to what could cause their fur color. Make sure each explanation includes two genes and follows along with the provided data. Also, explain the genotype of each color of dog and a ratio of the F2 phenotypes you would expect to see from a dihybrid cross. After you're finished, pick one of the explanations and create a hypothesis for the function of each gene which would explain the molecular basis of the fur color Finally, for each of the two genes, explain how a specific functional difference between the two alleles leads to a difference in their functions
In cardinals, a dominant allele R is required for red feathers (r = colorless). In addition, the dominant allele I (of an unlinked gene. is an inhibitor of color (birds with an I allele are colorless; I overrides the effects of R). If a true breeding red cardinal mates with a colorless female (genotype = r/r; I/I): a) What would be the genotype of the F1 progeny? b) What would be the phenotype of the F1 progeny? c) If the F1 progeny are selfed, what is the expected colorless:red ratio among the progeny?
EE = floppy ears Ee = floppy ears bb = brown fur ee = pointed ears BB = black fur %3D Bb = black fur %D %3D 1. A female dog with the genotype BBee is crossed with a male dog with the genotype bbEe The square is set up below. Fill it out and determine the phenotypes and proportions in the offspring. Ве Ве Ве Ве bE BbEe BbEe How many out of 16 have: black fur and floppy ears? be Bbee Bbee Bbee Bbee black fur and pointed ears? brown fur and floppy ears? bE BbEe BbEe BbEe brown fur and pointed ears? be Bbee Bbee Bbee Bbee .. ... 2. Show the cross: bbEe x BbEe How many out of 16 have: black fur and floppy ears? black fur and pointed ears? I floppy ears? own brown fur and pointed ears?
. Consider the genotypes of two lines of chickens: thepure-line mottled Honduran is i/i ; D/D ; M/M ; W/W, andthe pure-line leghorn is I/I ; d/d ; m/m ; w/w, whereI = white feathers, i = colored feathersD = duplex comb, d = simplex combM = bearded, m = beardlessW = white skin, w = yellow skinThese four genes assort independently. Starting withthese two pure lines, what is the fastest and mostconvenient way of generating a pure line that has coloredfeathers, has a simplex comb, is beardless, and has yellowskin? Make sure that you showa. the breeding pedigree.b. the genotype of each animal represented.c. how many eggs to hatch in each cross, and why thisnumber.d. why your scheme is the fastest and the mostconvenient
Phenotype Genotype Wide bands BB medium Bands Bb narrow bands bb Phenotype Genotype Complete Washing WW half washing Ww No washing ww If a raccoon with a wide tail band that washes only some of its food is crossed with a raccoon with a narrow tail band that doesn’t wash any food, what percentage of their offspring would be medium-tailed and washes all its food? Show COMPLETE cross.
A purebred plant that produces yellow seeds (YY) is crossed with a purebred plant that produces green seeds (yy). The seeds of all of the offspring are yellow. Why? O The yellow allele is (completely) dominant to the green allele. All of the offspring are homozygous yellow. O The yellow allele is recessive to the green allele. O The alleles are codominant. a (24