y m3 = 2 m4 = 9 (-5, 3) (0, 0)' Im, = 3 (4, 2) -4 -3 - 2 -1 1 2 4 m1 = 6 -2 -3+ (3, - 2) 3. 3. 2.

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter29: Atomic Physics
Section: Chapter Questions
Problem 32P
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Find the center of mass of a system of point masses m1 = 6, m2 = 3, m3 = 2, and m4 = 9,

located at (3, −2), (0, 0), (−5, 3), and (4, 2) as shown

y
m3 = 2
m4 = 9
(-5, 3)
(0, 0)' Im, = 3
(4, 2)
-4 -3 - 2 -1
1
2
4
m1 = 6
-2
-3+
(3, - 2)
3.
3.
2.
Transcribed Image Text:y m3 = 2 m4 = 9 (-5, 3) (0, 0)' Im, = 3 (4, 2) -4 -3 - 2 -1 1 2 4 m1 = 6 -2 -3+ (3, - 2) 3. 3. 2.
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