y F, = 15N F2 = 22N 300 F= 12N 4 kg F, = 20N F3= 17N

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Chapter9: Solids And Fluids
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Five forces acted on a 4.0 kg box shown below. Find the acceleration in unit vector
notation, direction and magnitude.

y
F2 = 22N
F3 = 15N
30°
4 kg
F4= 12N
F, = 20N
X---
Fs= 17N
Transcribed Image Text:y F2 = 22N F3 = 15N 30° 4 kg F4= 12N F, = 20N X--- Fs= 17N
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