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- Logic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions. Task 2: 4 INPUT PRIORITY ENCODERa) Write the truth table.b) Find the outputs in terms of min terms using minimal expression.c) By using K map, find the simple/simplest expression of theoutputs.d) Draw the circuit diagram. (Simulation design will be accepted.)e) Simulate the circuit & explain your results. (Please do notdesign separate simulations for each output. You should design ONEsimulation including all inputs and outputs.)Implement the function, W using ONE 4-to-1 multiplexer and other logic gates. b) Implement the function, X using ONE 4-to-1 multiplexer and other logic gates. Implement the function, Y using TWO 4-to-1 multiplexer and other logic gates. d) Implement the function, Z using ONE 8-to-1 multiplexer and other logic gates. Table Q1 ВCD Braille A B D W Y 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 A ololOThe numbers from 0-9 and a no characters is the Basic 1 digit seven segment display * .can show False True In a (CA) method of 7 segments, the anodes of all the LED segments are * "connected to the logic "O False True Some times may run out of pins on your Arduino board and need to not extend it * .with shift registers True False
- 9. The correct Boolean equation for the combination logic gate circuit sh B- c- a. Y=(A+B+ C ) D b. Y=(A+B) (C+D) c. Y (AB+C) d. Y=( ABC )D 0. The correct Boolean equation for the combination logic gate shown A - B-Solve the problem and simplify the output function using Quine–Mc Cluskey Methods. The following requirements must be met in solving the problem. Requirement:a. Truth Tableb. Timing Diagramc. Quine – Mc Cluskey Method d. Logic Diagram A private company wants to decide on a certain issue. Each of the four officials has an equal share of voting right. At least two of them must approve the solution in order to implement it. Each of them has a switch which closes to vote YES and open to vote NO.Exclusive-OR (XOR) logic gates can be constructed from what other logic gates? Select one: O a. AND gates, OR gates, and NOT gates O b. AND gates and NOT gates O c. OR gates only O d. OR gates and NOT gates
- For the logic diagram shown in Figure 2, find logic function Q prove it is equivalent to Ex-NOR gate. i. A- DDO BUsing truth table for 7-segment logic:1. Determine the minimum logic for segment b2. Determine the minimum logic for segment c3. Determine the minimum logic for segment d4. Determine the minimum logic for segment e5. Determine the minimum logic for segment f6. Determine the minimum logic for segment g1. a. i. Draw the gates required to build a half adder are ii. When simplified with Boolean Algebra (x + y)(x + z) simplifies to : iii. The output of a logic gate is 1 when all its inputs are at logic 0, the gate is either :
- (c) Figure Q3(c)(i) shows a register and Figure Q3(c)(ii) shows the input waveforms (CLOCK and Data in) to the circuit. A1 A9 A10 A2 Function generator A3 A11 A12 AS A13 A6 A14 A7 A15 Data in Bop.7) ip.r 82p.7) Logic analyser U1 U2 U3 U4 UO 6. 1. 6 1 6 INVERTER 3 CLK 3 CLK oCLK CLK 5 K K 5 K K 4027 Clock Function generator Figure Q3(c)(i) (i) Determine the type of register as shown in Figure Q3(c)(i).3-) Make the following Logic Function with Karno diagram in Max.term form the simplest and give the final form; Draw with 2 Input NOR gates only F(A,B,C) = A. (B.C + B'.C) + B. (A'.C' + A.C') + (A.B'.C')Electrical Engineering Draw 2, 1 bit ALUS to create a basic 2 bit ALU. the carry out and carry in bits must ripple across. The ALU should subtract/add, logical NOR, logical AND, and logical OR. Draw out the adding logic circuit