X Incorrect. Compute the standard free energy change for the following reaction: C2H4(g) + 302(g) → 2CO2(g) + 2H20(1) i -1.310E3 kJ eTextbook and Media Hint Save for Later Attempts: 2 of 3 used Submit Answer
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- V Part A Calculate AS for the balanced chemical equation: AS Tall Submit ΙΠΤΑΣΦ 4 Request Answer C? J/K 2H₂S(R) +30₂(g) → 2H₂O(g) +250₂ (8) Substance and state S J/(K-mol) 188.8 205 H₂O(g) 0₂(g) H₂S(g) SO₂(g) 205.7 248.1Match each of the following with its correct answer If AH°, of H,O, is -285.8 KJ/mol and AH° of H,0 is -241.8 KJ/mol, then the AH°, of evaporation of H,O in ( KJ/mol) : 2 (L) (g) Chooser Choose.. -44 -413.9 Using the following information below, calculate AHº, for Pbo in kJ/mol. +44 -108.7 -210 -151.6 PbO + CO (s) (g) Pb + CO (s), 2(g), ΔΗΟ = 131.4 kJ/mol- 1) Molecules AHO Choose... CO 6), -110.5 CO 2(g) -393.5 Given the following thermochemical equation: 16CO, + 18 H O 2(g) AH° = -11020 2CH,8) + 25 0,(g) 18(1) kJ/mol If AH°, [CO,l] = -393.5 kJ/mol and AH°. [H,o ] = -285.8kJ/mol, calculate the standard enthalpy of formation of octane ( C H) 2(g) %3D Choose...v in kJ/mol wwwwtCalculate AS values for the following reactions by using tabulated Sº values from Appendix C.. (a) C₂H4(9) + H₂(g) = C₂H6(9) Asº = J/K (b) 2 CH₂OH(g) + 3 0₂(g) = 2 CO₂(g) + 4H₂O(g) AS⁰ = 3/K (c) 2 PC13(g) + O₂(g) =2 POCI3(9) AS⁰ = J/K (d) N₂04(0) = 2 NO₂(9) AS⁰ = J/K
- Compound SO; (g) SO₂ (g) NH3 (g) NO (g) H₂O (9) Consider the following reaction at 25 °C: 5 SO3(g) + 2 NH³(g) → 2 NO(g) + 5 SO₂(g) + 3 H₂O(g) Given the information in the table, calculate AH° for the reaction. AHf (kJ/mol) -396 -297 -46 90.4 -241.8 Sf (J/mol-K) 256 248 192.5 210.6 188.7Given the following enthalpy change values for the reactions below: A + 2B – C; A,H = 350.1 kJ mol-1 E + F - 2C + D;A,H = 476.2 kJ mol-1 ½ E - G + 2B ; A;H = -229.6 kJ mol-1 Calculate A,H for the following reaction (in kJ mol-1) using Hess's Law: 2A + D - F + 2GCombustion of glucose (C₂H₂O₂) is the main source of energy for animal cells: C₂H₁0()+60₂(g) 6CO₂(g) + 6H₂O() AG,(37 "C)--2872. kJ One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation of one peptide bond, joining one amino acid to another, is 21 kJ/mol. Suppose some cells are assembling a certain protein made of 82 amino acids. (Note that the number of peptide bonds in the protein will be one less than the number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 800. umol of this protein. Round your answer to 2 significant digits. 08 D.P X 1426
- Use the table of standard values below to calculate AHæn. ΔΗ° (6) -414.2 -285.8 -427.0 Na₂O(s) H₂O(l) NaOH(s) -273.0 kJ -154.0 kJ 273.0 kJ 154.0 kJ So (K-mol) 75.1 70.0 64.0(1) C(s) + O2(g) CO2(8) AH, = -393.5 kJ AH = -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO: (2) CO(g) + 02(8) CO2(8) - %3D (3) C(s) + 02(8) CO(g) AH3 = ? 24 - O A) 403.5 O B) 676.5 403.5 O D) 110.5 O E) -110.5Use the tables below to determine the enthalpy of reaction (in kJ) for the following balanced chemical equation: Table T16-5-1. BDES, average single bond dissociation energies (in kJ/mol) I Br CI s P si F ONC H 299 366 431 368 322 323 568 463 391 413 436 220 276 328 259 264 301 453 358 276 348 N 159 243 200 200 335 272 176 193 234 234 203 364 340 368 190 146 F 277 237 193 327 490 582 157 Si 234 310 464 226 226 184 264 319 209 218 253 266 CI 208 218 242 Br 175 193 I 151 Multiple Bonds (BDE in kJ/mol) Bond BDE Bond BDE N=N 418 C=C 620 NEN 941 C=C 815 C=N 615 C=0 745 CEN 891 C=O 1072 N=O 607 O=0 499 Reaction: C2H4 + l2 -> C2H412 P.
- Part B Calculate AG at 298 K if the partial pressures of NO2 and N₂O4 are 0.40 atm and 1.60 atm, respectively. Express the free energy in kilojoules to two decimal places. AG = -5.70 Submit VE ΑΣΦ Provide Feedback Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining P Pearson ? kJ Next >|consiter Tne following FCActiona A uco The enthaly of formation values Below He cakulate the OVCRAIL enthalpy change far r Mis Peaction PareD on toUp answer to pArtA. is B. Ihe ReacTiom exothe Rmic OR evrlotherme SuBstance Ailf° (x]/MOl)ubskance Allfo subslance AHf(M -235 248 -277 HO(1)-286 -11 1,01g-242|0,4 1422. Given the following data: CO(g)+H2O(g)→ CO2(g)+ H2(g) AH (25° C) = -42.0 kJmol1 Cp (CO) = 26.8 + 6 x 10³T JK'mol1 Cp (H2O) = 30.1 + 10 x 10³T JK'mol1 Cp (H2) = 28.5 + 2 x 10³T JK-'mol-1 Cp (CO2) = 26.4 + 42 x 10³T JK-'mol-1 where T is the thermodynamic temperature, calculate the change in enthalpy for the reaction at 1000 K.