write the following program using simply linked list in C++ language Add definition of the following functions into a simply linked list: 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists. So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not. So if a list contains {1, 3, 7, 8, 9} its sorted, but if a list contains {1, 3, 7, 2, 5} its not sorted. 5) Find sublist : Find and return sublist in a list, the start and stop positions indicate where the sublist starts and where it ends. So if a list contains {1, 3, 7, 8, 9}, sublist at start 2 and stop 4 is {3, 7, 8} . please not like the last answer :D it not work please i need a new simple code
write the following program using simply linked list in C++ language
Add definition of the following functions into a simply linked list:
1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}.
2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}.
3)Count common elements : Count common values between two simply linked lists. So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3.
4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not. So if a list contains {1, 3, 7, 8, 9} its sorted, but if a list contains {1, 3, 7, 2, 5} its not sorted.
5) Find sublist : Find and return sublist in a list, the start and stop positions indicate where the sublist starts and where it ends.
So if a list contains {1, 3, 7, 8, 9}, sublist at start 2 and stop 4 is {3, 7, 8} .
please not like the last answer :D it not work please i need a new simple code
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