Write querry:::----------1 Structured Query Language (SQL) is a language widely used in industry to create, update andquery data in relational databases. You are required to write the SQL code.Q.6.1The below sample data in the third normal form was provided by a databasedesigner. Answer the below questions using this data.Table: Law FirmPrimary key: Law FirmID (auto number)All fields are mandatoryLawFirmID1236Table: LawyerPrimary key: LawyerIDForeign key: Law FirmIDLawyerID789Name122Ze Boss AttorneysLawyers for the WinCourt RulezLawFirmID3SurnameBianchiModiseFerreiraNkosiYearIncorporated201120182019NameAnnalDikelediPietJabulaniQ.6.1.1 Write a SQL statement to create the table Lawyer.Age45573428Hint: The sample data should give you an indication of the datatypes you should use.Q.6.1.2 Write a SQL statement that will calculate the average age of all thelawyers that are at least 40 years old.Q.6.1.3 Write a SQL statement to insert the below row into table LawFirm.

Answered: Write querry:::----------1

Engineering

Computer Science

Write querry:::----------1

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question 2 Structured Query Language (SQL) is a standard computer language for relational database management and data manipulation. SQL queries are used to insert, update and modify data. By referring to the Table1 below, write the SQL statements for the following: Table 1: Students ID Names PhoneNumber Country Somalia Age 1234 Aishah 0131234561 18 Absya Ah Meng Bee Chean Malaysia China 4567 0131234562 21 8910 01312345673 20 1112 01312345674 Korea 19 1314 Buchanan 0131234565 Korea 20 (a) Add new column: Ambition Varchar (20). (b) Display Names and Ambition for 20 year old students using SQL. (c) Delete Table Students. (d) Delete column country. (e) Use SQL statements to update all Country names in the Students table from Korea to Malaysia.
J SHORTAND NOTATION FOR RELATIONAL SQL TABLES Notation Example Meaning Underlined A or A, B The attribute(s) is (are) a primary key Superscript name of relation AR or AR, BR The attribute(s) is (are) a foreign key referencing relation R As an example, the schema R(A, B, C, D, ES) S(F, G, H) corresponds to the following SQL tables: CREATE TABLE R ( A <any SQL type>, B <any SQL type>, C <any SQL type>, D <any SQL type>, E <any SQL type>, PRIMARY KEY(A), FOREIGN KEY (E) REFERENCES S(F) ); CREATE TABLE S ( F <any SQL type>, G <any SQL type>, H <any SQL type>, PRIMARY KEY(F)) EXERCISE Consider the following relational schema, representing five relations describing shopping transactions and information about credit cards generating them [the used notation is explained above]. SHOPPINGTRANSACTION (TransId, Date, Amount, Currency, ExchangeRate, CardNbrCREDITCARD, StoreIdSTORE) CREDITCARD (CardNbr, CardTypeCARDTYPE, CardOwnerOWNER, ExpDate, Limit)…
SQL Database Write PL/SQL or T-SQL procedures to accomplish the following tasks: Obtain the first name and last name, separated by a space, of the guide whose number currently is stored in I_GUIDE_NUM. Place these values in the variables I_FIRST_NAME and I_LAST_NAME. Output the contents of I_GUIDE_NUM, I_FIRST_NAME, and I_ LAST_NAME. Obtain the number of persons, customer number, and customer last name for every reservation whose ID currently is stored in I_RESERVATION_ID. Place these values in the variables I_NUM_PERSONS, I_CUSTOMER_NUM, and I_LAST_NAME, respectively. Output the contents of I_NUM_PERSONS, I_CUSTOMER_NUM, and I_LAST_NAME. Add a row to the GUIDE table. Change the last name of the guide whose number is stored in I_GUIDE_NUM to the value currently found in I_LAST_NAME. Delete the guide whose number is stored in I_GUIDE_NUM
Structured Query Language (SQL) is a language widely used in industry to create, update and query data in relational databases. You are required to write the SQL code. Q.6.1 The below sample data in the third normal form was provided by a database designer. Answer the below questions using this data. Table: LawFirm Primary key: LawFirmID (auto number) All fields are mandatory LawFirmID Name Yearlncorporated 1 Ze Boss Attorneys 2011 2 Lawyers for the Win 2018 3 Court Rulez 2019 Table: Lawyer Primary key: LawyerlD Foreign key: LawFirmID LawyerID LawFirmlD Surname Name Age Bianchi Anna 45 7 2 Modise Dikeledi 57 8 2 Ferreira Piet 34 3 Nkosi Jabulani 28 Q.6.1.1 Write a SQL statement to create the table Lawyer. Hint: The sample data should give you an indication of the data types you should use. Q.6.1.2 Write a SQL statement that will calculate the average age of all the lawyers that are at least 40 years old. Q.6.1.3 Write a SQL statement to insert the below row into table LawFirm.
SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression
SQL QUERIES Employees(EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE,JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID,DEPARTMENT_NAME)Department(DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)Location(LOCATION_ID,STREET_ADDRESS,POSTAL_CODE,CITY,STATE_PROVINCE,COUNTRY_ID) Write a Query in SQL to delete the record of all those cities where city name ends with b fromlocations table.
SQL QUERIES Employees(EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE,JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID,DEPARTMENT_NAME)Department(DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)Location(LOCATION_ID,STREET_ADDRESS,POSTAL_CODE,CITY,STATE_PROVINCE,COUNTRY_ID) Write a query in SQL to display the DEPARTMENT_NAME of all those Departments whoseDEPARTMENT_ID is greater than the DEPARTMENT_ID of Physics department. Write a Query in SQL to show the FIRST_NAME of all those employees whose salary is lessthan the salary of all those employees whose MANAGER_ID is 101 or 102.
sql queries Employees(EMPLOYEE_ID, FIRST_NAME, LAST_NAME, EMAIL, PHONE_NUMBER, HIRE_DATE,JOB_ID, SALARY, COMMISSION_PCT, MANAGER_ID, DEPARTMENT_ID,DEPARTMENT_NAME)Department(DEPARTMENT_ID, DEPARTMENT_NAME, MANAGER_ID, LOCATION_ID)Location(LOCATION_ID,STREET_ADDRESS,POSTAL_CODE,CITY,STATE_PROVINCE,COUNTRY_ID) Write a query in SQL to display the Entire data of All those employees whoseDEPARTMENT_ID is greater than the DEPARTMENT_ID of all those employees who earn morethan 50,000 per month Write a query in SQL to display the minimum, maximum salary and DEPARTMENT_NAMEof all those departments whose minimum salary is greater than 4000 in ascending order.
Description The Employee table holds all employees including their managers. Every employee has an Id, and there is also a column for the manager Id. +--- | Id | Name | Salary | ManagerId | +---- | 1 | 2 | 3 | 4 +---- | Joe | 70000 | 3 | Henry | 80000 | 4 | Sam | Max Given the Employee table, write a SQL query that finds out employees who earn more than their managers. For the above table, Joe is the only employee who earns more than his manager. + | Employee | + | Joe + | 60000 | NULL | 90000 | NULL I
Create a PL/SQL database programming block with DECLARE BEGIN END; In Declare section define a local scalar (simple) variables. lv_deptno NUMBER And assign initial values as 10 lv_deptno NUMBER := 50; In Declare section again, define a cursor and select last_name, salary and manager_id of employees the ones who are working in the department defined in a) In this example department will be lv_deptno:=50; Sample code: Cursor c_emp as SELECT last_name, salary, manager_id FROM employees WHERE department_id = lv_deptno; In the execution section (BEGIN and END) Create CURSOR FOR LOOP for cursor to process In this cursor loop, your code has to check salary and also manager_id numbers each time new records being fetched. And based on these conditions either employee gets raise or not get raise. If employee salary is less than 5000 and also if employees managers is either 101 or 124 then it means employee is due for raise otherwise employee is not due for raise Sample…
PL/SQL Question I need to build pl/sql block that prompts a user for the number of visitors each day for the past 5 days and then displays the average number of visitors per day. For example; day 1: 19 day 2: 21 day 3: 23 ... The avg number of visitors is: ___ like this.
Given the following relation: Book (BooklD, Author, ISBN, Title) Write a PL/SQL block of code that performs the following tasks: i. Read a Book id provided by user at run time and store it in a variable. ii. Fetch the Author and title of the book having the entered id and store them inside two variables i. Display the fetched book author and title. T TTF Paragraph Arial 3 (12pt) ABC T T, e HTML CSS O f. Mashups