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Write a new program in MIPS Assembly language using your LFSR function from the first problem. Start from state 0x00000001, then run a loop counting all the possible states in the LFSR before it cycles back to 0x00000001. This is shown by the following pseudocode:   count = 0; initial = state = 0x00000001; do {     state = LFSR(state);     count++; while (state != initial); print count;   Verify that the number of states is (2^15) - 1 = 32767 . Your program should complete within 30 seconds. If it takes longer then you likely have entered an infinite loop.

Write a new program in MIPS Assembly language using your LFSR function from the first problem. Start from state 0x00000001, then run a loop counting all the possible states in the LFSR before it cycles back to 0x00000001. This is shown by the following pseudocode:   count = 0; initial = state = 0x00000001; do {     state = LFSR(state);     count++; while (state != initial); print count;   Verify that the number of states is (2^15) - 1 = 32767 . Your program should complete within 30 seconds. If it takes longer then you likely have entered an infinite loop.

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Write a new program in MIPS Assembly language using your LFSR function from the first problem. Start from state 0x00000001, then run a loop counting all the possible states in the LFSR before it cycles back to 0x00000001. This is shown by the following pseudocode:

 

count = 0;

initial = state = 0x00000001;

do {

    state = LFSR(state);

    count++;

while (state != initial);

print count;

 

Verify that the number of states is (2^15) - 1 = 32767 . Your program should complete within 30 seconds. If it takes longer then you likely have entered an infinite loop.

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