Write a function GCD( int A, int B ), when called from main function, returns the GCD (Greatest Common Divisor) of two numbers. Also get two numbers, X and Y from user and call this function to calculate GCD and show the result on Monitor. X and Y must be your reg# and 786, respectively. Note: GCD, Greatest Common Divisor: GCD of two numbers is the greatest number which can divide both the numbers. If the smaller of the two numbers can divide the larger number then the GCD is the smaller number. Else starting from 1 to (smaller / 2), check whether the current element divides both the numbers . If yes, then the highest of these devisors is the required GCD.

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter6: User-defined Functions
Section: Chapter Questions
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Write a function GCD( int A, int B ), when called from main function, returns the
GCD (Greatest Common Divisor) of two numbers. Also get two numbers, X and Y from
user and call this function to calculate GCD and show the result on Monitor. X and Y
must be your reg# and 786, respectively.
Note: GCD, Greatest Common Divisor: GCD of two numbers is the greatest number
which can divide both the numbers. If the smaller of the two numbers can divide the
larger number then the GCD is the smaller number. Else starting from 1 to (smaller / 2),
check whether the current element divides both the numbers . If yes, then
the highest of these devisors is the required GCD.
Transcribed Image Text:Write a function GCD( int A, int B ), when called from main function, returns the GCD (Greatest Common Divisor) of two numbers. Also get two numbers, X and Y from user and call this function to calculate GCD and show the result on Monitor. X and Y must be your reg# and 786, respectively. Note: GCD, Greatest Common Divisor: GCD of two numbers is the greatest number which can divide both the numbers. If the smaller of the two numbers can divide the larger number then the GCD is the smaller number. Else starting from 1 to (smaller / 2), check whether the current element divides both the numbers . If yes, then the highest of these devisors is the required GCD.
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