Would a component with a larger Rf value have a higher or lower affinity for the mobile phase compared to a component with a smaller Rf value? Explain, using specific color spots from your data.
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Would a component with a larger Rf value have a higher or lower affinity for the mobile phase compared to a component with a smaller Rf value? Explain, using specific color spots from your data.
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- H4)ConsiteR the following Beaction: Pa,t 8 H,0→ Hy POqt 3 HCl IP 12.49 of | 10.09 of Hy O, what is the limiting Ctrl PCI, is PeacteD witn T0.0g Peactant ? Molar nhass of Pelg: 137.329/mel. holarmass of HoO=18:0291 mel malar mass of Hy POz =¢2.00 glmol molar mass of HCl= 35.4A16 glmel. %3DAlt Alt Ctrl HRA chemist pRopaped 1 レ dissilving B.0g of Ag NO, in wateR matke 350.0mb to of Sólution. what is the molaizity Of the solution? molaR mass of silver hiticate =ll09.889mil %3DC B) C) D) E) (C6H5)3P NH₂ Zn(Hg) HCI ۵۰۰ NaOH heat DMSO 1. Excess CH31 2. Ag₂O, H₂O 3. heat -O 53% 35°F Cloudy 12
- ALEKS - Jacqueline Hoppenrey x G convert mg to g - Google Searc x A www-awn.aleks.com/alekscgi/x/Isl.exe/1o_u-IgNslkr7j8P3jH-IQiHqRdYV 6Ux63Syp.JXz0Coxvwqgg4JkWI72X79QvOLp9_7U27sYQhkaocvdwecGvsUzo65uy3F6spORRg1XSqgh81is O STOICHIOMETRY Using molarity to find solute mass and solution volume Jacqueline A chemist adds 55.0 mL of a 4.75M silver perchlorate (AGCIO,) solution to a reaction flask. Calculate the mass in grams of silver perchlorate the chemist has added to the flask. Round your answer to 3 significant digits. Explanation Check Privacy Accessibil 2021 McGraw-Hill Education All Rights Reserved Terms of Useraw The eneray dueram for ihis mechains m-racnan giv he PeaoNion ts endo thermit. Label all parts ľ , product, Acpi van on envray enhapy ntermediasks, acovatad Complex). Reactont Mechansm i Steja) Aaty -> N0 t 6,0 (sloxi). 切0十梅0 一ーはH(tor)College of Teacher Bachelor of Secondary Education *promoting pedagogical excellence elor of Sec omoting pedage RIN ht: (a) (b) Br. C. CH3 b1. HNO3, H2SO4 2. Fe, H30*r H2/Pd s / oD Br NO2 (c) KMN04 7 (d) Cl CH3CH2CH2CI AICI3 H20 7. OCH3 4. Predict the major product(s) of the following reactions: OM (a) CI (b) CH CH CH3CH2C! AICI3 CH3CH2COCI AICI3 (c) CO2H HNO3 (d) N(CH2CH3)2 H2SO4 SO, H2SO4 ASITY
- Q2: (A) Sketch the following Miller indices: 1.[102] 2. (2110) 3.(312)/x/Isl.exe/lo_u-IgNslkr7j8P3jH-IQs_dp5pR4ENzvdYC-70kXyMz36BqJhw3sVPj_jpaFLxvGArYxlbmayqa71YYPJBG6RjdYAdGPjGhFLILID-HEX1YcqAB?1oBw7QYjlbavbSPXtx-YCjsh_7mMmrq#item P Course Home Login | Student Veri... Hb Logout MyProgrammingLab Imported From IE O ITEC2110:Summer2... TunesToTube - Upl.. Publix App Web Development.. O KINETICS AND EQUILIBRIUM Using the Arrhenius equation to calculate k at one temperature fr. Cia 23%#3%# The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energyE=45.0 kJ/mol. If the rate constant of this -1 -1 reaction is 4.4 x 10 M s at 266.0 °C, what will the rate constant be at 177.0 °C? Round your answer to 2 significant digits. -1 k = \\M -1 x10StatisticalAnalysis of Data. Provide what isasked. a.Mean values of ppm Ca and ppm Mg .b.Median values of ppm Ca and ppm Mg. c.Std. dev. of ppm Ca and ppm Mg.
- -ks.com/alekscgi/x/lsl.exe/10_u-lgNslkr7j8P3jH-IQUHIQg6bJxmeSyVpHOEB1plef9xy C5Ca9QlrxeFDNO_5W_JXgzqLjhQzolekwtDgTVd4JcZ_naFz8W0qO0HIZQ5LM92POq ||| = O Acids and Bases Predicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: name nitrous acid acid hydrocyanic acid solution 0.1 M HONHJBr 0.1 M CH3NH3Cl 0.1 M Nal 0.1 M KCN Explanation formula HNO₂ HCN Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. Ka 4.5 x 10 4.9 × 10-10 Check X pH choose one ✓ choose one ✓ choose one ✓ choose one ✓ base S K₂ formula methylamine CH3NH₂ 4.4 x 104 hydroxylamine HONH₂ 1.1 x 108 name 0/5 Allie V E OL A © 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | AccessibilityC Love Fuqua - Learn - X www-awu.aleks.com/alekscgi/x/isl.exe/10_u-IgNslkr7j8P3jH-IBjuJnuCDtT6kRBabGFF3MOAKZ_UVXON202gOiJQTdIGDtYib1Jke3qJJtY-n0BOXd4G0r80JmhB6zbOrS5108W-LPce6pq?10Bw Apple Music 0 O CHEMICAL REACTIONS, Writing the net equation for a sequence of reactions G mg to g-Google Search Explanation Propane can be turned into hydrogen by the two-step reforming process. In the first step, propane and water react to form carbon monoxide and hydrogen: CgHg(g)+3H,O(g)–3CO(g)+7H,(g) Check X In the second step, carbon monoxide and water react to form hydrogen and carbon dioxide: CO(g) + H₂O(g)→H₂(g) + CO₂(g) Write the net chemical equation for the production of hydrogen from propane and water. Be sure your equation is balanced. ローロ O M VHL Central | Dashboard X x + 3 © 2023 McGraw Hill LLC. All Rights Reserved 0 0/5 Terms of Use | Privacy Center Accessibility Feb 1