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- Should be 3 answers in total. Will thumbs up! Next the student conducts two different runs: In RUN 1, 10.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 80.0 mL of wate In RUN 2, 20.0 mL of 5.00 M NAOH is combined with 10.0 mL of 0.010 M CO and 70.0 mL of wate The following plots were obtained for each of the runs: [crystal orange] vs time (RUN 1) In[crystal orange] vs time (RUN 1) 0.0012 0.001 -2 y--0.4463x- 7.3334 y =-0.0002x + 0.0007 R- 0.6565 R = 0.893 0.0008 4 0.0006 -6 0.0004 -8 0.0002 0.0002 -12 time (hr) time (hr) 1/[crystal orange] vs time (RUN 1) 1/[crystal orange] vs time (RUN 2) 12000 25000 10000 20000 8000 15000 6000 y = 2000x + 1000 R =1 10000 y 4000x + 1000 R =1 4000 2000 5000 time (hr) time (hr) Figure 4. Kinetic traces for the reaction between crystal orange and sodium hydroxide. What is the order with respect to CO? | Select ] What is the order with respect to NaOH? | Select ] What is the value of the averaged rate constant for the reaction above? Give…AaBbCcDd AaBbCcDd AaBbC AaBbCcD AdD AaBb- 1 Normal 1 No Spac... Heading 1 Heading 2 Title Subti 田,、 即咖山 Paragraph Styles 1. 3. 2.15.0 mL HNO3 was titrated to equivalence with 60.0 mL of 0.020 NaOH. What is the concentration of the acid? 近0 of F5 F7 6日 てい いレゴTITRIMETRIC DATA SAMPLE: CANE VINEGAR % acidity in label: 4.5% %purity of KHP: 99.80% FORMULA WEIGHT of KHP: 204.22 g/mol STANDARDIZATION OF NaOH SOLUTION TRIAL 1 TRIAL 2 TRIAL 3 Weight of KHP, g 0.1012 0.1004 0.09987 Initial volume of NaOH, mL 5.00 10.01 Final volume of NaOH, mL 4.95 9.99 14.93 Molarity of NaOH Average Molarity of NaOH ANALYSIS OF ACETIC ACID IN A VINEGAR SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of vinegar, mL Initial volume of NaOH, mL 1.00 1.00 1.00 14.98 22.90 30.87 Final volume of NaOH, mL 22.84 30.77 38.75 Molarity of acetic acid Average molarity of acetic acid ANALYSIS OF CARBONIC ACID IN A SODA SAMPLE TRIAL 1 TRIAL 2 TRIAL 3 Volume of soda, mL 20.0 20.0 20.0 Initial volume of NaOH, mL 20.20 22.05 23.93 Final volume of NaOH, mL 22.03 23.89 25.8 Molarity of carbonic acid Average molarity of carbonic acid
- The sample containing 4.2 % NaCl will be determined gravimetrically as AgCl. What weight (in milligrams) of the sample must be taken to obtain a precipitate that will weigh about 0.39 mg? FM: NaCl = 58.44 AgCl = 143.3 %3D Answer in two decimal places. Do not include units in the answer. Answer:A soltion is made by the addition of 40 ml of 40 mM NaO to 40 of 30 mM phoshork acd What is the final ptof the solon for HPOA pat 2.12. pa721, pka1232 14400✓ Question Completion Status: Shown below is a calibration curve for the analysis of theobromine and caffeine in chocholate. if an unknown sample has a caffiene peak height of 3.50 cm what is the concentration of caffeine in the sample in ppm? 20 Peak height (centimeters) 15 10 5 0 Theobromine y = 0.1977x-0.2104 25 Unknown Figure 0-7 Gumantative Chemical Analysis, Seventh Edition 2007 Freeman and Company Caffeine y = 0.088 4x-0.030 3 50 Analyte concentration (parts per million) 100 M ED Feb 2 8:3
- e. They 4.00 mL of a 7.20 x 10-4 M solution of an unknown acid is diluted with 6.00 mL of hexane, forming solution X. Then 3.00 mL of solution X is diluted with 7.00 x 10-3 Lof hexane, forming solution Y. Then 2.00 x 103 L of solution Y is diluted with 8.00 mL of hexane, forming non 15 et %3D ered solution Z. How many grams of unknown acid are 4.00 mL of solution Z? (Molar mass for unknown acid = 345 g/mol) ed out of Select one: g question O a. 5.08 x 10-6g O b. 2.38 x 10g O c. 5.08 x 104g O d. 1.02 x 10g O e. 2.03 x 10-2g ious page Next page Type here to search 曲:ⒸMacmillan Learning What is the concentration of a solution made by diluting 45 mL of 6.0 M HCl to a final volume of 750 mL? 80 F3 concentration: $ 4 288 F4 % 5 T F5 ^ 6 MacBook Air F6 & 7 - F7 11 00* 8 DII F8 ( 9 DD F9 O ) O. O F10 P 3) F11 { + r = F12 M delete7. A student performed an acid-base titration in the lab and recorded the results as shown below. Look very carefully at the results and answer the questions which follow. 演定結果 Nasco +2HC1 →Naclt Ca t H20 試験 流定 終結演定管讀數(cm) 開始演定管讀數(em) 所需演定劑的體積 (cm) 15.40 27.40 15,40 12.00 34.40 27.40 12,00 36 12.30 (1.5 1200 1200 tll5 3. 所間滴定劑的平均體積- 標 0.025/M 25 f 2010 (a) Why do we perform acid-base titrations in our labs? (b) In the titration performed by the student, what was the net ionic equation for the chemical reaction occurring? (c) List all the wrong things that the student did when writing the report on his titration experiment. (d) What good thing did this student do?
- A procedure7 for determining halogens in organic compounds uses an argentometric titration. To 50 mL50 mL of anhydrous ether is added a carefully weighed sample (10−100 mg)(10−100 mg) of unknown, plus 2 mL2 mL of sodium dispersion and 1 mL1 mL of methanol. (Sodium dispersion is finely divided solid sodium suspended in oil. With methanol, it makes sodium methoxide, CH3O−Na+,CH3O−Na+, which attacks the organic compound, liberating halides.) Excess sodium is destroyed by slowly adding 2‑propanol, followed by 100 mL100 mL of water. (Sodium should not be treated directly with water because H2H2 can explode in the presence of O2O2: 2Na+2H2O⟶2NaOH+H2.)2Na+2H2O⟶2NaOH+H2.) This procedure gives a two‑phase mixture, with an ether layer floating on top of the aqueous layer that contains the halide salts. The aqueous layer is adjusted to pH 44 and titrated with Ag+,Ag+, using the electrodes in Figure 7‑5.How much 0.02916 M AgNO30.02916 M AgNO3 solution will be required to reach each equivalence…1) Listen The Ksp value for calcium sulfate [CaSO4] is 2.40 X 10-5 so if a professor made 1825 mL of a CaSO4(ag) solution then how many grams of calcium (Ca2+) ion would be present in this solution. 0.3948 gram Ca2+ ion 0.4965 gram Ca2+ ion 0.2527 gram Ca2+ ion 0.4747 gram Ca2+ ion 0.3396 gram Ca2+ ion 0.2943 gram Ca2+ ion 1591.docx LAB EXP. #3 -.docx Show All2A student used a pipette to add 25 cm³ of sodium hydroxide of unknown concentration to a conical flask. The student carried out a titration to find out the volume of 0.1 mol/dm3 sulfuric acid needed to neutralise the sodium hydroxide. The following is the table of results obtained. Titration Volume of sulfuric acid used/cm³ 1 27.85 27.30 27.25 27.10 27.30 a. Write down a balanced equation for the reaction between sodium hydroxide and sulfuric acid. b. Describe the titration experimental procedure (details of washings are expected) c. Determine the average titre value and explain your choice of titre values in calculating the average. d. Determine the concentration of sodium hydroxide. e. If instead of sulfuric acid, hydrochloric acid of the same concentration was used what would you expect the average titre value to be and why?