White a Java Function to find unique number in a list ls = [ 2, 3, 4, 10, 5, 6, 6, 4, 10, 3 ] , unique number is number that doesn't repeat this case unique list will be = [ 2, 5 ]
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White a Java Function to find unique number in a list ls = [ 2, 3, 4, 10, 5, 6, 6, 4, 10, 3 ] , unique number is number that doesn't repeat this case unique list will be = [ 2, 5 ]
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- Exercise, maxCylinderVolume F# system function such as min or methods in the list module such as List.map are not allowed Write a function maxCylinderVolume that takes a list of floating-point tuples that represent dimensions of a cylinder and returns the volume of the cylinder that has the largest volume. Each tuple has two floating point values that are both greater than zero. The first value is the radius r and the second value is the height h. The volume of the cylinder is computed using ??2h. The value π is represented in F# with System.Math.PI. If the list is empty, return 0.0. Examples: > maxCylinderVolume [(2.1, 3.4); (4.7, 2.8); (0.9, 6.1); (3.2, 5.4)];;val it : float = 194.3137888> maxCylinderVolume [(0.33, 0.66)];;val it : float = 0.2257988304Recursive Count Write a recursive function rc_count(L:List[int], x:int) -> int that takes a list L and an integer x. The function returns the number of occurrences of x in L. For example, rc_count([1,1,2,3], 1) returns 2 and rc_count([1,1,2,3], 4) returns 0. Your Answer: 1 # Put your answer here 2 SubmitCount dominators def count_dominators(items): An element of items is said to be a dominator if every element to its right (not just the one element that is immediately to its right) is strictly smaller than it. By this definition, the last item of the list is automatically a dominator. This function should count how many elements in items are dominators, and return that count. For example, dominators of [42, 7, 12, 9, 13, 5] would be the elements 42, 13 and 5. Before starting to write code for this function, you should consult the parable of "Shlemiel the painter" and think how this seemingly silly tale from a simpler time relates to today's computational problems performed on lists, strings and other sequences. This problem will be the first of many that you will encounter during and after this course to illustrate the important principle of using only one loop to achieve in a tiny fraction of time the same end result that Shlemiel achieves with two nested loops. Your workload…
- Write a recursive function named Multiply2 that multiples by 2 and prints each element in a given list. For example: mylist=[1,2,3,4] Multiply2(mylist) prints: 2 4 6 8 Note: the function takes only one parameter, which is the list on which the operation will be performed.Question > Not complete Marked out of 1.50 Flag question Previous page Write a recursive function named get_palindromes (words) that takes a list of words as a parameter. The function should return a list of all the palindromes in the list. The function returns an empty list if there are no palindromes in the list or if the list is empty. For example, if the list is ["racecar", "hello", "noon", "goodbye"], the function should return ["racecar", "noon"]. A palindrome is a word that is spelled the same forwards and backwards. Note: The get_palindromes() function has to be recursive; you are not allowed to use loops to solve this problem. For example: Test words = ["racecar", "hello", "noon", "goodbye", "test", 'aibohphobia'] ['racecar', 'noon', 'aibohphobia'] print (get_palindromes (words)) print (get_palindromes ([])) print (get_palindromes (['this', 'is', 'test'])) Answer: (penalty regime: 0, 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 %) Result Precheck Check [] [] Next pageemacs/lisp function Write a function that takes one parameter that is a list of numbers and returns true (t) if all the elements of the list are multiples of the first one and nil otherwise.
- The function that will a single items to the list is Oextend (...) Oadd(...) Oappend(...) Olengthen(...)C++ Programming Language ::::::: Redo the same functions this time as nonmember functions please : NOTE: You can add only one function into the linked list class get_at_position which will return value of element at given position. 1) Insert before tail : Insert a value into a simply linked list, such that it's location will be before tail. So if a list contains {1, 2, 3}, insert before tail value 9 is called, the list will become {1, 2, 9, 3}. 2) Insert before value : Insert a value into a simply linked list, such that it's location will be before a particular value. So if a list contains {1, 2, 3}, insert before 2 value 9 is called, the list will become {1, 9, 2, 3}. 3)Count common elements : Count common values between two simply linked lists.So if a list1 contains {1, 2, 3, 4, 5}, and list2 contains {1, 3, 4, 6}, number of common elements is 3. 4) Check if sorted : Check if elements of simply linked lists are sorted in ascending order or not.So if a list contains {1, 3, 7, 8, 9}…Create a function that determines the elements in a list that can be rearranged to create a sequence of numbers where each number appears exactly once. Examples Evil ([5, 1, 4, 3, 2]) - true // It can be rearranged to have a form [1, 2, 3, 4, 5] evil ([5, 1, 4, 3, 2, 8]) false IN java programming language
- Code in python Given a list, L, the function front_two creates a new list of length 2 out of the first two items in L as follows: In the new list, the second item becomes the first item, and the first item becomes the second. If L contains only one item, the first item in the new list should be the value None. If L is empty, both items in the new list should be value None. The function returns the new list. For example: Test Result L = ['a', 'b', 'c', 'd'] print(front_two(L)) ['b', 'a'] L = [] print(front_two(L)) [None, None] L = [5, 2] print(front_two(L)) [2, 5] L = [7] print(front_two(L)) [None, 7]Computer Science In Racket, write a recursive function called "first-index" that returns only the first index of the specified element in a list. Ex : (first-index '1 '(3 5 1 4 5 2 1)) Would return 3 The function must take 2 arguments, the item you wish to find its index and a listContact list: Binary Search A contact list is a place where you can store a specific contact with other associated information such as a phone number, email address, birthday, etc. Write a program that first takes as input an integer N that represents the number of word pairs in the list to follow. Word pairs consist of a name and a phone number (both strings). That list is followed by a name, and your program should output the phone number associated with that name. Define and call the following function. The return value of FindContact is the index of the contact with the provided contact name. If the name is not found, the function should return -1 This function should use binary search. Modify the algorithm to output the count of how many comparisons using == with the contactName were performed during the search, before it returns the index (or -1). int FindContact(ContactInfo contacts[], int size, string contactName) Ex: If the input is: 3 Frank 867-5309 Joe 123-5432 Linda…