Which of the reactions are spontaneous (favorable)? DHAP = glyceraldehyde-3-phosphate AG = 3.8 kJ/mol L-malate + NAD+ oxaloacetate + NADH + H+ AG = 29.7 kJ/mol O C,H,O5 C,H,O, + H,0 AG= 3.1 kJ/mol Rh(I) O C,H, + H2 C,H. AG = -150.97 kJ/mol O C,H130,P + ATP C,H4012P, + ADP AG = –14.2 kJ/mol 12 2 O glutamate + NAD+ + H,O – NH + a-ketoglutarate + NADH + H* AG = 3.7 kcal/mol

Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section5.5: Enthalpy Changes For Chemical Reactions
Problem 1RC: 1. For the reaction 2 Hg(l) + O2(g) → 2 HgO(s), ∆rH° = 181.6 kJ/mol-rxn. What is the enthalpy change...
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Which of the reactions are spontaneous (favorable)?
DHAP = glyceraldehyde-3-phosphate AG = 3.8 kJ/mol
L-malate + NAD+
→ oxaloacetate + NADH + H+
AG = 29.7 kJ/mol
C,H¸O;
C,H,O, + H,0 AG= 3.1 kJ/mol
Rh(I)
C,H, + H,
C,H, AG = -150.97 kJ/mol
C,H1,0,P
O̟P + ATP
C,H14012P2 + ADP
AG = -14.2 kJ/mol
glutamate + NAD+ + H,O → NH† + a-ketoglutarate + NADH + H*
AG = 3.7 kcal/mol
Transcribed Image Text:Which of the reactions are spontaneous (favorable)? DHAP = glyceraldehyde-3-phosphate AG = 3.8 kJ/mol L-malate + NAD+ → oxaloacetate + NADH + H+ AG = 29.7 kJ/mol C,H¸O; C,H,O, + H,0 AG= 3.1 kJ/mol Rh(I) C,H, + H, C,H, AG = -150.97 kJ/mol C,H1,0,P O̟P + ATP C,H14012P2 + ADP AG = -14.2 kJ/mol glutamate + NAD+ + H,O → NH† + a-ketoglutarate + NADH + H* AG = 3.7 kcal/mol
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