Which of the following equations below describes the system head of the piping shown below. The total length of the pipe is 154 ft. Take the friction factor to be 0.026. The pipe used has a nominal diameter of 4 inches and Schedule No. 40. The system head H is in ft and the flow rate Q is in ft^3/s. Hint: You need to use the Tioga table and K value for minor losses. Z₂ = 107 ft Reservoir B 90° regular screwed elbow Pump Z₁ = 53 ft Reservoir A A) H-51+25.98(Q^2) B) H=54+24.98(Q^2) H=54+25.98(Q^2) ⠀

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
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Which of the following equations below describes the system head of the piping shown below.
The total length of the pipe is 154 ft. Take the friction factor to be 0.026. The pipe used has a
nominal diameter of 4 inches and Schedule No. 40. The system head H is in ft and the flow rate
Q is in ft^3/s.
Hint: You need to use the Tioga table and K value for minor losses.
Z₂ = 107 ft
Reservoir B
90° regular screwed elbow
Pump
Z₁ = 53 ft
Reservoir A
A) H=51+25.98(Q^2)
B) H=54+24.98(Q^2)
ⒸH=54+25.98(Q^2)
⠀
Transcribed Image Text:Which of the following equations below describes the system head of the piping shown below. The total length of the pipe is 154 ft. Take the friction factor to be 0.026. The pipe used has a nominal diameter of 4 inches and Schedule No. 40. The system head H is in ft and the flow rate Q is in ft^3/s. Hint: You need to use the Tioga table and K value for minor losses. Z₂ = 107 ft Reservoir B 90° regular screwed elbow Pump Z₁ = 53 ft Reservoir A A) H=51+25.98(Q^2) B) H=54+24.98(Q^2) ⒸH=54+25.98(Q^2) ⠀
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